|
Hello leppie,
I have attempted to look, but was not able to find an answer (hince the reason I have posted to the board). I thank you for your "non-willingness" to help though. Have a nice day.
|
|
|
|
|
when do you want to validate that?
if you want to validate on textchange you can write code for that . or for any button click you can use Regx.
Thanks
|
|
|
|
|
Thank you. I will give it a shot.
|
|
|
|
|
That work. Once again thank you.
|
|
|
|
|
you are welcome
|
|
|
|
|
int number;
bool isNumber = int.TryParse(text, out number);
modified 12-Sep-18 21:01pm.
|
|
|
|
|
Hi Greeeg,
Great Idea !!!!
|
|
|
|
|
using System;
using System.Drawing;
using System.Windows.Forms;
namespace WindowsApplication11 {
public class FormA : Form {
public virtual new Size PreferredSize {
get {
return new Size(300, 300);
}
}
}
static class Program {
[STAThread]
static void Main() {
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Form form = new FormA();
form.Size = form.PreferredSize;
Application.Run(form);
}
}
}
Chris
|
|
|
|
|
chris175 wrote: public virtual new Size PreferredSize { get { return new Size(300, 300); } }
What is "Size" ?
|
|
|
|
|
|
Its Working Fine
using System;
using System.Drawing;
using System.Windows.Forms;
namespace WindowsApplication11
{
public class FormA : Form
{
public virtual new Size PreferredSize
{
get
{
return new Size(300, 300);
}
}
}
static class Program
{
[STAThread]
static void Main()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Form form = new FormA();
Application.Run(form);
form.Size = form.PreferredSize;
}
}
}
|
|
|
|
|
I encountered something similar, and got the right size AFTER the call to Application.Run (). If you get the size in FormA's Load method, it might be right at that point.
|
|
|
|
|
Because when you Application.Run(form) , InitializeComponent() gets called which probably resets the size of the form.
Scott P
“It is practically impossible to teach good programming to students that have had a prior exposure to BASIC: as potential programmers they are mentally mutilated beyond hope of regeneration.”
-Edsger Dijkstra
|
|
|
|
|
The wrong size is placed on the form BEFORE Application.Run(form) is called. I dont think it has anything to do with InitializeComponent() function since there isn't one within the class FormA .
Chris
|
|
|
|
|
carbon_golem wrote: Because when you Application.Run(form), InitializeComponent()
No, you have it all wrong, there is no magic involved. InitializeComponent() is usually called from the Form's constructor.
|
|
|
|
|
If you do FormA form = new FormA() then your method will be called, otherwise the System.Windows.Forms.Control.PreferredSize property will be called (can be seen in .NET reflector). I guess this has to do with the fact that PrefferedSize in Control is not marked virtual or abstract .
regards
modified 12-Sep-18 21:01pm.
|
|
|
|
|
PreferredSize isn't virtual; you cannot override it.
Instead your code created a new virtual property with the same name - but your Main method refers to the original PreferredSize property.
You should override the virtual GetPreferredSize method instead.
|
|
|
|
|
That is what I was looking for... Thanks
|
|
|
|
|
Hi everybody.
I have a class that uses a socket to comunicate with remote server. In that class I have two threads - one for sending data and one for receiving. I am not shure if I have to lock the socket instance becouse I use it in both threads. The problem is if I lock it when receiving the object is locked all the time becouse socket.receive blocks until it receives some data. My simplified receiving methods is
void read()
{
byte[] buffer = new byte[ReadBufferSize];
int readCount;
while (true)
{
readCount = 0;
try
{
//lock(_socket)
//{
readCount = _socket.Receive(buffer); // this call blocks
//}
}
catch (Exception ex)
{
}
if (readCount > 0)
{
//Notify the main thread that data was received
}
}
}
Does anybody has any solution? Maybe I should use some other method(not socket.receive)? Is locking the socket instance even necessary? Any advice will be apreciated.
Uros
|
|
|
|
|
From my experience, you should not have to lock the socket.
|
|
|
|
|
Thanks. Are you shure about that? I mean do you know that, or you didn't use locking and had no problems becouse of it?
Uros
|
|
|
|
|
Nope, AFAIK NetworkStream is bidirectional, so you can send and receive at the same time. Try it without locks. If it breaks, investigate, find a solution and write an article to tell us about it
|
|
|
|
|
Where can i post a thread for help with javascript?
There is no "JS" forum?
Thanks
|
|
|
|
|
|
you can also post it in web development section.
if this releated with asp.net , you can alos post over asp.net fourm
Thanks
|
|
|
|