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This following code will help you to access the file which is added to the project
Add the file into the project and then set the property as embedded file then you will be able to access with the following code. or you can add the file in the resource file and you will be able to access the file.
Assembly embeddedFile = Assembly.GetExecutingAssembly();
Stream StreamEmbeddedFile;
StreamEmbeddedFile = embeddedFile.GetManifestResourceStream ("NameSpace.Test.xml");
XmlDocument myStylesheet = new XmlDocument();
myStylesheet.Load(StreamEmbeddedFile);
Here, "NameSpace" is default namespace.
if you have any other problem on this pls let me know
Thanks
Raja.S
modified on Tuesday, August 19, 2008 7:25 AM
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Hi Raja.S,
This code does not seem to work as I need to run it from the class inside a class library project. i.e. Assembly is not recognised in intellisense
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You have to include "using System.Reflection;" it is available in Class Library as well. you mean to say the color of the code is not changed in the IDE that means you haven’t included the name space.
This is getting the running assembly if it is class library then class library(dll) will be loaded to the running process on the demand , when it executes the code from class library the running assembly will be the class library(dll) .
Thanks
Raja.S
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Correction to my previous post.
I have created a windows application.
There are forms inside the windows form application project. There is a class library project too.
The .sln is in the following path:
C:\Work\Developments\SQLchecks\SQLchecks
The windows forms are inside the windows application project as below:
C:\Work\Developments\SQLchecks\SQLchecks\SQLchecks
There is a class library project called DataAccess which has classes and an xml file called Settings.xml :
C:\Work\Developments\SQLchecks\SQLchecks\DataAccess
Question:
from within a class inside the DataAccess project which is a class library project, how do I refer to the Settings.xml file which is also in the same directory?
Thanks
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Got that !! your class library and the setting.xml in the same folder you want to access that setting.xml from the class library
simple:
using System.Reflection;
string path = Assembly.GetExecutingAssembly().Location;
path = path + "setting.xml";
let me know the result.
Thanks
Raja.S
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This seems to be IN-correct because it returns:
"C:\\Work\\Developments\\SQLchecks\\SQLchecks\\SQLchecks\\bin\\Debug\\DataAccess.dllSettings.xml"
Please note the Settings.xml file is inside C:\\Work\\Developments\\SQLchecks\\SQLchecks\\DataAccess
Where DataAccess is a classLibrary Project which sits inside a dataAccess folder.
I then modified the above code and placed "\Settings.xml"
The new error is:
Could not find a part of the path 'C:\\Work\\Developments\\SQLchecks\\SQLchecks\\SQLchecks\\bin\\Debug\\DataAccess.dll\\Settings.xml'."
Any thoughts please?
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Sorry it should be
path = path + "\\setting.xml";
this should work
Thanks
Raja.S
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The new error is:
Could not find a part of the path 'C:\\Work\\Developments\\SQLchecks\\SQLchecks\\SQLchecks\\bin\\Debug\\DataAccess.dll\\Settings.xml'."
Thanks
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Have checked is that setting.xml is there in that path ?
can i get your hotmail id if possible we can chat ?
Thanks
Raja.S
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hey man your getting the path with the assembly name discard assembly name from the path and put the setting.xml every thing should work fine
it should be
'C:\\Work\\Developments\\SQLchecks\\SQLchecks\\SQLchecks\\bin\\Debug\\Settings.xml'."
Thanks
Raja.S
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Hi,
These files are present in:
C:\Work\Developments\SQLchecks\SQLchecks\DataAccess\bin\Debug
DataAccess.dll
Settings.xml
...
...
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Find the code here
// get current path for the assembly
string path = Assembly.GetExecutingAssembly().Location;
path = Path.GetFullPath(Path.Combine(Path.GetDirectoryName(path),".."));
path = path + @"\setting.xml";
Thanks
Raja.S
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final code here
using System.IO;
using System.Reflection;
// get current path for the assembly
string path = Assembly.GetExecutingAssembly().Location;
path = Path.GetFullPath(Path.Combine(Path.GetDirectoryName(path),".."));
path = path + @"\setting.xml";
pls let me know the result
Thanks
Raja.S
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Hi,
Error is:
Message: "Value cannot be null.\r\nParameter name: inputUri"
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this excemption seems to be some problem in your application code , code which i have provided you, i have tested, it is getting the running assembly path and then with .. its discaring the assembly name and get the setting.xml file.
Thanks
Raja.S
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Hi,
Using your code the path is:
"C:\\Work\\Developments\\SQLchecks\\SQLchecks\\SQLchecks\\bin\\Settings.xml"
But after publishing, the Settings.xml is sitting inside the debug so somehow I need to access:
"C:\\Work\\Developments\\SQLchecks\\SQLchecks\\SQLchecks\\bin\\Debug\\Settings.xml"
So I used the following code:
path = AppDomain.CurrentDomain.BaseDirectory + "Settings.xml";
This seems to be working fine on my Development machine but after publishing it to users machines then this does not seem to get the Settings.xml file.
Not sure what I am doing wrong?
Thanks
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Here's a chunk of code that might help you with this. If you set "test.xml" as an "embedded resource", rather than "content", then it will actually reside inside the compiled library file, and you can access it like this:
using ( Stream prototype = System.Reflection.Assembly.GetExecutingAssembly().GetManifestResourceStream( "Namespace.test.xml" ) ) {
byte[] fileData = new byte[ prototype.Length ];
prototype.Read( fileData, 0, (int)prototype.Length );
File.WriteAllBytes( filePath, fileData );
}
Be sure to use the namespace when identifying the file name. I think there are other overloads of this function you can use as well.
“Time and space can be a bitch.”
–Gushie, Quantum Leap
{o,o}.oO( Looking for a great RSS reader? Try FeedBeast! )
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Yes, I changed it fro mcontent to Embedded resource.
How about using the following code instead of yours
path = AppDomain.CurrentDomain.BaseDirectory + "Settings.xml";
This works on my machine but not when it is published to the users machines using clickonce.
The error on users machine is:
Can not find file 'c:\Documents and Settings\JoeDowe\localsetting\App\2.0\...\Settings.xml'
Why is the system looking in Documents and Settings?
Thanks
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First you have to build your application with release mode, in the release mode where is the setting.xml is copied or else you can create a build event to copy to the files into specific location then try to publish this applciation .are you publishing the application to FTP or some URL or to the specific disk location ?
Thanks
Raja.S
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This is now solved by manually placing the xml file into the windows application project and then publish.
Thanks
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Copying also you can do it by build events no need to do that manually
Thanks
Raja.S
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How do you mean please?
When I build, the file does not copy from class library prohect to the windows app project, so I have to do it manually.
Thanks
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how can i convert .wav file to g.711 using c#.net to push it in cisco ip phones
Thanks in advance
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This[^] article may help
DaveBTW, in software, hope and pray is not a viable strategy. (Luc Pattyn)Expect everything to be hard and then enjoy the things that come easy. (code-frog)
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sorry dave but can you tell me the steps to convert from .wav to g.711
i have read your article but i couldn't find where i will give it my .wav file
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