C# Discussion Boards - CodeProject

Vikas K.29-Jul-07 21:21

29-Jul-07 21:21

Hi,

Sorry, If I have posted this query to a wrong group!

I'm facing an issue with C# project. I use VS 2005 express edition.

I was developing a C# project and had couple of UI controls that I had placed
using UI editor. Everything was fine but now I can't view the "UI designer" now.

If I run the project I do get the UI that I had designed but cant edit it now?

How can I see the disigner again?

Thanks
Vikas

Re: C# Project corrupted?

T.EDY29-Jul-07 21:53

T.EDY

29-Jul-07 21:53

Hi,

Try to close the form and Rebuild Solution..and if the rebuild has succeeded..try to open your form again,sometimes i get the same problem but when i do that my UI designer can be view again

Kind Regards,

Tomi

Re: C# Project corrupted?

Vikas K.29-Jul-07 23:29

Vikas K.

29-Jul-07 23:29

I tried but still I can't see the form design! I guess, I will have to port the entire code into a new project now Cry | :((

Re: C# Project corrupted?

Developer61130-Jul-07 0:05

Developer611

30-Jul-07 0:05

Hi there .

I think , it's better to check your reference files.
Maybe you missed one of your reference . if it is , remove you reference from reference list and add it to your project reference again , and then Rebuild your solution or project , what ever as you want . Smile | :)

DMASTER

Re: C# Project corrupted? [modified]

Martin#30-Jul-07 0:08

Martin#

30-Jul-07 0:08

Hello,

What you can try:
In your project explorer, rightclick the Form or usercontrol you can not edit and change the "buildaction" to an other setting and then back to "compile" (I have not the english version and only 2003 so I don't know the exact names).
Then make a rebuild.

Hope it helps!

All the best,

Martin

Re: C# Project corrupted?

Vikas K.30-Jul-07 19:54

Vikas K.

30-Jul-07 19:54

Hi, Ok I know why this is happening but pls tell me whats wrong in doing this?

1. My form is like this: Everything is proper and I can view the designer

<br />
//file Form1.cs<br />
<br />
public partial class Form1 : Form<br />
{<br />
 // many functions/events related to UI controls are here<br />
}<br />

2. I need to have a special control class say MyPictureBox derived from PictureBox so added the code as follows in file Form1.cs:

<br />
//file Form1.cs<br />
<br />
public class MyPictureBox : System.Windows.Forms.PictureBox<br />
{<br />
  // some special code will be put here<br />
}<br />
<br />
public partial class Form1 : Form<br />
{<br />
 // many functions/events related to UI controls are here<br />
}<br />

Thats it: Now If I try to open the designer I get the error:

<br />
One or more errors encountered while loading the designer. The errors are listed below. Some errors can be fixed by rebuilding your project, while others may require code changes. <br />
<br />
The service System.Windows.Forms.Design.ISelectionUIService already exists in the service container. Parameter name: serviceType <br />
Hide     <br />
<br />
at System.ComponentModel.Design.ServiceContainer.AddService(Type serviceType, Object serviceInstance, Boolean promote)<br />
at System.ComponentModel.Design.ServiceContainer.AddService(Type serviceType, Object serviceInstance)<br />
at System.ComponentModel.Design.DesignerHost.System.ComponentModel.Design.IServiceContainer.AddService(Type serviceType, Object serviceInstance)<br />
at System.Windows.Forms.Design.ComponentDocumentDesigner.Initialize(IComponent component)<br />
at System.ComponentModel.Design.DesignerHost.AddToContainerPostProcess(IComponent component, String name, IContainer containerToAddTo)<br />
at System.ComponentModel.Design.DesignerHost.Add(IComponent component, String name)<br />
at System.ComponentModel.Design.DesignerHost.System.ComponentModel.Design.IDesignerHost.CreateComponent(Type componentType, String name)<br />
at System.ComponentModel.Design.Serialization.DesignerSerializationManager.CreateInstance(Type type, ICollection arguments, String name, Boolean addToContainer)<br />
at System.ComponentModel.Design.Serialization.DesignerSerializationManager.System.ComponentModel.Design.Serialization.IDesignerSerializationManager.CreateInstance(Type type, ICollection arguments, String name, Boolean addToContainer)<br />
at System.ComponentModel.Design.Serialization.TypeCodeDomSerializer.Deserialize(IDesignerSerializationManager manager, CodeTypeDeclaration declaration)<br />
at System.ComponentModel.Design.Serialization.CodeDomDesignerLoader.PerformLoad(IDesignerSerializationManager manager)<br />
at Microsoft.VisualStudio.Design.Serialization.CodeDom.VSCodeDomDesignerLoader.PerformLoad(IDesignerSerializationManager serializationManager)<br />
at System.ComponentModel.Design.Serialization.BasicDesignerLoader.BeginLoad(IDesignerLoaderHost host) <br />

Afterwards, I will not be able to view the original designer but I think the designer related to MyPictureBox which is blank.

But if I put the body of MyPictureBox after the body of Form as shown below, everything is fine!

<br />
//file Form1.cs<br />
<br />
public partial class Form1 : Form<br />
{<br />
 // many functions/events related to UI controls are here<br />
}<br />
<br />
public class MyPictureBox : System.Windows.Forms.PictureBox<br />
{<br />
  // some special code will be put here<br />
}<br />

Pls let me know what is the procedure in adding a derived UI control class?

Thanks

Re: C# Project corrupted?

Martin#30-Jul-07 20:02

Martin#

30-Jul-07 20:02

Hello,

The Problem is that both classes have design support.
It is not good practice to but them all in one file.
If you put the picturebox in a special file you will also be able to open it over the designer.

All the best,

Martin

Re: C# Project corrupted?

Vikas K.30-Jul-07 20:12

Vikas K.

30-Jul-07 20:12

Thank you Martin and others who gave quick answers!
I created another file and things are pretty nice now!

Help is really appreciated Smile | :)

problem in generating crysatl reports

monuSaini29-Jul-07 21:14

monuSaini

29-Jul-07 21:14

Hello Every body,

I am new with crystal reports. I want to generate report for those employees whose age is more than 50 yrs.

But I am not able to do so .It is showing all the records.

I had added an crystal report in my project.

I link it with the database through wizard only,

On form1 it had inserted an crystal report viewer. on the load event of the form1 I had used the following code but it is use less.

SqlConnection Connection = new SqlConnection("server='server1'; user id='sa'; password='admin'; database='employee'");

SqlCommand myCommand = new SqlCommand("SELECT * from companyEmp where age < '50'");

myCommand.Connection = Connection;
myCommand.CommandType = CommandType.Text;

SqlDataAdapter DA = new SqlDataAdapter();
DA.SelectCommand = myCommand;

DataSet DS = new DataSet();
DA.Fill(DS);

crystalReportViewer1.SetDataSource(DS.Tables[0]);
crystalReportViewer1.ReportSource = objNewReport;

But it is still showing all the record of companyEmp.

Regards,

rahul saini

Re: problem in generating crysatl reports

Edwin Syarief29-Jul-07 22:18

Edwin Syarief

29-Jul-07 22:18

monuSaini wrote:
SqlCommand myCommand = new SqlCommand("SELECT * from companyEmp where age < '50'");

U just need:
SqlCommand("SELECT * from companyEmp where age < 50");

'50' -> type string
50 -> int

Regard,

Edwin

Re: problem in generating crysatl reports

monuSaini29-Jul-07 22:58

monuSaini

29-Jul-07 22:58

Hello Edwin,

Thanks for ur rply.

But still same problem.

It is showing all the records.

If I am using only this

crystalReportViewer1.ReportSource = NewReport;

then also it is showing all the records.

Rregards,

rahul saini

Re: problem in generating crysatl reports

T.EDY29-Jul-07 23:28

T.EDY

29-Jul-07 23:28

may i know the data type of age in your database?

Regards,

Tomi

Re: problem in generating crysatl reports

monuSaini29-Jul-07 23:33

monuSaini

29-Jul-07 23:33

Hello Tomi,

Thanks for ur rply.

Its int.

Regards,

rahul saini

Re: problem in generating crysatl reports

T.EDY29-Jul-07 23:42

T.EDY

29-Jul-07 23:42

Hi Rahul,

I wonder if u want to show the data if the age is above 50 right?

if u use query:

SELECT * FROM Your_Table Where age < 50

u got an output data age below 50, if u want to show the data where age is more than 50 than u must change your query into :

SELECT * FROM Your_Table WHERE age > 50

i try to my query analizer thats work Smile | :)

Regard,

Tomi

Re: problem in generating crysatl reports

Edwin Syarief29-Jul-07 23:47

Edwin Syarief

29-Jul-07 23:47

TomiEdy wrote:
if u use query:

SELECT * FROM Your_Table Where age < 50

u got an output data age below 50, if u want to show the data where age is more than 50 than u must change your query into :

SELECT * FROM Your_Table WHERE age > 50

I think U right Tomi, maybe U must check your query Rahul

Regard,

Edwin

Re: problem in generating crysatl reports

T.EDY29-Jul-07 23:57

T.EDY

29-Jul-07 23:57

Thank You Edwin

Regard,

Tomi

Re: problem in generating crysatl reports

Edwin Syarief29-Jul-07 23:41

Edwin Syarief

29-Jul-07 23:41

SqlDataAdapter adapter = new SqlDataAdapter(yourQuery, conn);
DataSet ds = new DataSet();
DataTable dt = new DataTable("tablename");
adapter.Fill(dt);
ds.Tables.Add(dt);
ds.WriteXml("C:\text.xml");

Then On your crystal report Database Fields:
change your dataset with "text.xml"

If U have finish it, then create a dataset with your query, then change the code like this:

SqlDataAdapter adapter = new SqlDataAdapter(yourQuery, conn);
DataSet ds = new DataSet("YourDataSet");
DataTable dt = new DataTable("tablename");
adapter.Fill(dt);
ds.Tables.Add(dt);

ReportDocument rd = new ReportDocument();
rd.SetDataSource = ds;
crystalReportViewer1.ReportSource = rd;

Regard,

Edwin

Re: problem in generating crysatl reports

monuSaini30-Jul-07 0:08

monuSaini

30-Jul-07 0:08

Hello Edwin,

When i m writing the xml it is giving me following error.

ds.WriteXml("C:\text.xml");

Illegal characters in path.

Regards,

rahul saini

Re: problem in generating crysatl reports

PhilDanger30-Jul-07 3:42

PhilDanger

30-Jul-07 3:42

ds.WriteXml("C:\text.xml");

-- \t is the character code for a tab. You need to escape your backslashes by... using another backslash.

ds.WriteXml("C:\\text.xml");

Re: problem in generating crysatl reports

monuSaini30-Jul-07 17:22

monuSaini

30-Jul-07 17:22

Hello Edwin,

One of my friend had told me that this issue can be resolved through SELECT EXPERT. Do you had any idea about this.

Regards,

rahul saini

Re: problem in generating crysatl reports

Developer61130-Jul-07 0:24

Developer611

30-Jul-07 0:24

Hi there .

Look my friend you set you ReportViewer data source it's wrong . you must create new instance of your CrystalReport.rpt file . for example i have an report file named report.rpt .

// Create new instance of your CrystalReport File
Report _Report = new Report();

// Set Report data source ,no your viewer .
_Report.SetDataSource(Your_DataSource);

// Finally set your report viewer report source to your Report file .
crystalReportViewer1.ReportSource = _Report;

DMASTER

Re: problem in generating crysatl reports

monuSaini30-Jul-07 1:54

monuSaini

30-Jul-07 1:54

Hi,

I had use this also but again it is showing the same result.(all the records are showing)

this the code i m using

SqlConnection Connection = new SqlConnection("server='sName'; user id='sa'; password='admin'; database='employee'");

SqlDataAdapter DA = new SqlDataAdapter("SELECT empId,empName,empAge from companyEmp where age < 50", Connection);

DataSet DS = new DataSet();

DA.Fill(DS);

newReport objNewReport = new newReport();
objNewReport.SetDataSource(DS.Tables[0]);

crystalReportViewer1.ReportSource = objNewReport ;

Regards,

rahul saini

Re: problem in generating crysatl reports

Developer61130-Jul-07 5:10

Developer611

30-Jul-07 5:10

Wow , I got it .you are using untyped dataset , right ?

look answer to my question I hope, I can help you .

1: Did you put any typed dataset in your report form ?
2: Did you used directly connection in report ?

Send your email address to my mail : www.Developermaster61@gmail.com

I hope, I elaborate in more detail .

DMASTER

How to detect a Mouse Double Click under Mouse_Down?

Khoramdin29-Jul-07 20:28

Khoramdin

29-Jul-07 20:28

Hello everyone,

Is there anyone that I can know there was a Mouse Double Click in the MainForm_MouseDown? I currently can detect if there has been a Left or a Right click but I would like to be able to check for Double Click.

if (e.Button == MouseButtons.Left)<br />
        {<br />
            MessageBox.Show("You have just clicked on " + e.Button + " button.");<br />
            MessageBox.Show("X: " + e.X + " -- Y: " + e.Y);                                      <br />
        }<br />
        if (e.Button == MouseButtons.Right)<br />
        {<br />
            MessageBox.Show("You have just clicked on " + e.Button + " button.");<br />
            MessageBox.Show("X: " + e.X + " -- Y: " + e.Y);<br />
}

Thank you very much and have a great day.

Khoramdin

Re: How to detect a Mouse Double Click under Mouse_Down?

Martin#29-Jul-07 20:41

Martin#

29-Jul-07 20:41

Hello,

I don't think that it's possible in MouseDown, as MouseDown is fired bevore Click and Double Click.
But MouseUp is fired after Click and DoubleClick.

So this would work:

private bool FlagDoubleClick = false;
protected override void OnDoubleClick(EventArgs e)
{
    FlagDoubleClick = true;

    base.OnDoubleClick (e);
}

protected override void OnMouseUp(MouseEventArgs e)
{
    if(FlagDoubleClick)
    {
        //Do it here!
        FlagDoubleClick= false;
    }
    base.OnMouseUp (e);
}

All the best,

Martin

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