C# Discussion Boards - CodeProject

vijaylumar13-Oct-09 1:12

vijaylumar

13-Oct-09 1:12

hi
thank u for ur help

but what about the Numerics

i.e if the actual value is 1.6 then after changing the culture to denmark
it is showing this as 1,6

can u help me regarding this

stancrm13-Oct-09 1:27

stancrm

13-Oct-09 1:27

Just reload it again, the same answer...

Example :
double d = 1.23;
textBox.Text = d.ToString(); // showing 1.23
//..change culture here..
textBox.Text = d.ToString(); // showing 1,23

vijaylumar13-Oct-09 1:41

vijaylumar

13-Oct-09 1:41

hi
i implemented your first answer

i got an error at the line

label1.Text = Resource.MyLabelText;

i dont have any Resource or MyLabelText

what does it mean "Resource.MyLabelText;"

stancrm13-Oct-09 1:46

stancrm

13-Oct-09 1:46

Add in your VS project a resource file, named it Resource.resx.
Then add an entry : "MyLabelText" value is BlaBlaBla

To add another resources, for example german, then do the same
again as above, change the filename to Resource.de.resx.
Then add an entry : "MyLabelText" value is BlaBlaBlaGerman

vijaylumar13-Oct-09 1:59

vijaylumar

13-Oct-09 1:59

it means i have to maintian a Resource file for every language
and i have to do it manually

is there any another way that if we select a language then the label text should change to the selected language

stancrm13-Oct-09 2:04

stancrm

13-Oct-09 2:04

benjymous13-Oct-09 3:04

benjymous

13-Oct-09 3:04

No. Windows/dotNet can't automatically translate your application's text - you'll have to do that yourself (or get someone to do it for you)

Help me! I'm turning into a grapefruit!
Buzzwords!

Simulation mobile users in network

Eddy Vluggen13-Oct-09 3:10

Eddy Vluggen

13-Oct-09 3:10

vijaylumar wrote:
is there any another way that if we select a language then the label text should change to the selected language

Windows can't automatically translate texts. You could use an online translation-service to do the translations, but those aren't nearly as accurate as you want them to be.

For inspiration on automated translations, start with this[^] CodeProject article.

I are Troll Smile | :)

trungtin13-Oct-09 0:10

trungtin

13-Oct-09 0:10

Hi,
I have a set of mobile users, I need to simulate this MUs in the network, this MUs transfer data to each other, one MU can search for information from other MUs.
After that measure the response time when has result.
I don’t know how to set up.
I have ideas but I do not know how to set up
Thanks.

xmlDocument

arkiboys12-Oct-09 23:40

12-Oct-09 23:40

Hi,
Assuming I have an xml file which looks something like:

<main>
<field1>
<table>
<columns>
<column>
<ElementName>1234</ElementName>
<ElementValue>uyt</ElementValue>
</column>
...
</columns>
</table>
</field1>
...
<field2>

<table>
<columns>
<column>
<ElementName>654322</ElementName>
<ElementValue>xyz</ElementValue>
</column>
...
</columns>
</table>
...
</field2>
...
...
</main>

The code below retrieves the values for
ElementName>654322</ElementName> and
<ElementValue>xyz</ElementValue> as shown:

private void ModifyXML()
{
XmlDocument doc = new XmlDocument();
doc.Load(strPath);

// Retrieve all prices.
XmlNodeList nodeList = doc.GetElementsByTagName("ElementName");

foreach (XmlNode node in nodeList)
{
string strValue = node.ChildNodes[0].Value.ToString();
if (strValue.ToLower() == "654322")
{
ListBox1.Items.Add(node.OuterXml);
ListBox1.Items.Add(node.NextSibling.OuterXml);
ListBox1.Items.Add("");

//Console.WriteLine(node.ChildNodes[0].Value);
//Console.WriteLine(node.NextSibling.InnerXml);
}
}
}

Question:

Please note that I do not want to use xpath or linq or database. Just the xmlDocument for business reasons

Using this code below, how can I add a column element i.e.

Thanks

<column>
<ElementName>newValue</ElementName>
<ElementValue>newdata</ElementValue>
</column>

OR

delete one of the above column elements i.e. to remove:
<column>
<ElementName>654322</ElementName>
<ElementValue>xyz</ElementValue>
</column>

SeMartens12-Oct-09 23:55

12-Oct-09 23:55

Hi,

you could use the AppendChild and RemoveChild methods of the XmlNode-class. For this navigate to the node you want to remove and call

nodeToRemove.ParentNode.RemoveChild(nodeToRemove)

To add a new node call

node.AppendChild(newNode)

Have a look here for the full documentation

http://msdn.microsoft.com/en-us/library/system.xml.xmlnode_members.aspx[^]

Regards
Sebastian

It's not a bug, it's a feature!

Check out my CodeProject article Permission-by-aspect.

Me in Softwareland.

arkiboys13-Oct-09 0:43

13-Oct-09 0:43

Hi,
I have been looking at msdn samples.
It seems I am having problems with .Append
How do I append something like:
<column>
<ElementName>654322</ElementName>
<ElementValue>xyz</ElementValue>
</column>

SeMartens13-Oct-09 0:46

13-Oct-09 0:46

You have to create a new node column. Then create nodes for elementname and elementvalue. Append these nodes to the column node. Last step is to append the column node to the node in your document.

Btw, if you want to create nodes, use the CreateNode method of your XmlDocument.

It's not a bug, it's a feature!

Check out my CodeProject article Permission-by-aspect.

Me in Softwareland.

arkiboys13-Oct-09 0:51

13-Oct-09 0:51

Not sure what you mean.
How is this possible to tell the system where exactly in the hierarchy to place this elelemnt within the file?
Are you able to write a test sample based on the xml I gave before?
Thanks

SeMartens13-Oct-09 1:02

13-Oct-09 1:02

Well I will try (without intellisense)...

private void ModifyXML()
{
   XmlDocument doc = new XmlDocument();
   doc.Load(strPath);

    // Retrieve all prices.
    XmlNodeList nodeList = doc.GetElementsByTagName("ElementName");

    foreach (XmlNode node in nodeList)
    {
        string strValue = node.ChildNodes[0].Value.ToString();
        if (strValue.ToLower() == "654322")
        {
            ListBox1.Items.Add(node.OuterXml);
            ListBox1.Items.Add(node.NextSibling.OuterXml);
            ListBox1.Items.Add("");
          
            // create new column node
            XmlNode columnNode = doc.CreateElement("column");
            // create elementName
            XmlNode elementNameNode = doc.CreateElement("elementName");
            // create elementValue
            XmlNode elementValueNode = doc.CreateElement("elementValue");
            // set values
            elementNameNode.InnerText = "foo";
            elementValueNode.InnerText = "bar";
            // append to column node
            columnNode.AppendChild(elementNameNode);
            columnNode.AppendChild(elementValueNode);
            // append column node to current node
            node.ParentNode.AppendChild(columnNode);
 
           

         }
     }
}

It's not a bug, it's a feature!

Check out my CodeProject article Permission-by-aspect.

Me in Softwareland.

arkiboys13-Oct-09 1:19

13-Oct-09 1:19

Hi,
I tried it with a bit of adjustments.
But I get this:

<column>
<ElementName>1234</ElementName>
<ElementValue>uyt</ElementValue>
<column>
<ElementName>newKey</ElementName>
<ElementValue>newValue</ElementValue>
</column>
</column>

instread of:

<column>
<ElementName>1234</ElementName>
<ElementValue>uyt</ElementValue>
<column>
<column>
<ElementName>newKey</ElementName>
<ElementValue>newValue</ElementValue>
</column>

-----------
This is the code:

Thanks

private void LoadXMLmodify()
{
XmlDocument doc = new XmlDocument();
doc.Load(strPath);

// Retrieve all prices.
XmlNodeList nodeList = doc.GetElementsByTagName("mapKey");

foreach (XmlNode node in nodeList)
{
string strValue = node.ChildNodes[0].Value.ToString();
if (strValue.ToLower() == "0024007")
{
if (node.NextSibling.InnerXml.Trim() == "1")
{
string strMapValue = node.NextSibling.InnerXml.Trim();

//Remove element...
//Debug.WriteLine("mapKey : " + strValue + " and mapValue : " + strMapValue + " removed.");
//node.RemoveChild(node.FirstChild);

//Add element...
XmlNode columnNode = doc.CreateElement("Mapping");
XmlNode elementKeyNode = doc.CreateElement("mapKey");
XmlNode elementValueNode = doc.CreateElement("mapValue");

elementKeyNode.InnerText = strValue;
elementValueNode.InnerText = "999";

columnNode.AppendChild(elementKeyNode);
columnNode.AppendChild(elementValueNode);

node.ParentNode.AppendChild(columnNode);

//string strMapValue = node.NextSibling.InnerText;
//Debug.WriteLine("mapValue changed from : " + strMapValue + " to : " + "newValue");
//node.NextSibling.InnerText = "newVlaue";

//doc.Save(strPath);
}
}
}

doc.Save(strPath);

}

SeMartens13-Oct-09 1:25

13-Oct-09 1:25

okay, try node.parentnode.parentnode

You are appending the new column node to an existing column node, but it must be the node above the existing column node.

It's not a bug, it's a feature!

Check out my CodeProject article Permission-by-aspect.

Me in Softwareland.

arkiboys13-Oct-09 1:29

13-Oct-09 1:29

Error:
In my code I sent you it gives an error on the line:
foreach(XmlNode node in nodeList)

It says: The element list has changed. The enumeration operation failed to continue.
Thanks

SeMartens13-Oct-09 1:32

13-Oct-09 1:32

As the error message is saying a list can not be changed during the iteration. Convert the XmlNodeList to an array and use this array to iterate through the nodes.

It's not a bug, it's a feature!

Check out my CodeProject article Permission-by-aspect.

Me in Softwareland.

arkiboys13-Oct-09 1:35

13-Oct-09 1:35

The xml has many many elements and subelements...
How can This be converted to array?
And may be I should not be in the loop to save?
Thanks

SeMartens13-Oct-09 1:38

13-Oct-09 1:38

Build a new list or array containing the elements of the XmlNodeList.

List<XmlNode> myNodes = new List<XmlNode>(doc.GetElementsByTagName("ElementName"));

Then iterate through myNodes.

It's not a bug, it's a feature!

Check out my CodeProject article Permission-by-aspect.

Me in Softwareland.

arkiboys13-Oct-09 1:41

13-Oct-09 1:41

I guess I do not have to be in the loop when I add a new row?
Don't you think?

SeMartens13-Oct-09 1:47

Re: xmlDocument [modified]

13-Oct-09 1:47

Yes that is correct. But sometimes the logic just needs to be done within a loop. If you can avoid doing all this within the loop -> do it.

Smile | :)

It's not a bug, it's a feature!

Check out my CodeProject article Permission-by-aspect.

Me in Softwareland.

arkiboys13-Oct-09 1:59

13-Oct-09 1:59

I have modified the loop so that as soon as there is an addition to the xml, then save the file and then break; this way it comes out of the loop.

Question:
I can see the xml I added is in there, so I now try to remove it as follows:
Do you see what is wrong here because i get an error on line with ????? it says object reference not set to an instance of an object.
Not that this error does not always happen. It seems I have to close the file and then re-open it to work correctly. Is this the way it should be?

Thanks

private void LoadXMLRemove()
{
XmlDocument doc = new XmlDocument();
doc.Load(strPath);

// Retrieve all .
XmlNodeList nodeList = doc.GetElementsByTagName("mapKey");

foreach (XmlNode node in nodeList)
{
//?????
string strValue = node.ChildNodes[0].Value.ToString();
//???????
if (strValue.ToLower() == "0024007")
{
if (node.NextSibling.InnerXml.Trim() == "1")
{
string strMapValue = node.NextSibling.InnerXml.Trim();

//Remove element...
Debug.WriteLine("mapKey : " + strValue + " and mapValue : " + strMapValue + " removed.");
node.RemoveChild(node.FirstChild);

doc.Save(strPath);
break;
}
}
}
}

modified on Tuesday, October 13, 2009 8:05 AM

SeMartens13-Oct-09 2:09