C / C++ / MFC

void EditInt(int& IntRef)
{
   IntRef=7;
}

int AnInt=6;
EditInt(AnInt);

Greg Utas wrote:

That's passing as a pointer, not as a reference.

void function(type& arg)
{
   if(&arg == nullptr)
      throw std::invalid_argument("function received null argument");
}

type* nasty = nullptr;
function(*nasty);

struct MyStruct
{
  MyStruct () {memset (this, 0, sizeof(MyStruct));} //always initialize your stuff.
    int a;
    int b;
    const char* text;
    short c;
};

Maximilien wrote:

It seems weird that the compiler accept to not fully initialize the struct.
They (old retired programmers) seem to expect the values to be zero-initialized.

Quote:

All members that are not initialized explicitly are empty-initialized.

Maximilien wrote:

I'm looking at old code.

Maximilien wrote:

seem to expect the values to be zero-initialized.

struct S {
  int i;
  double d;
  char str[10];
};

struct S s { .d = 123.4; }; 

[k5054@localhost]$ cat example.cpp 
#include <iostream>

struct S
{
    int i;
    float f;
    double d;
};

int main()
{
    S  s{0};

    std::cout << s.f << '\n';
}
[k5054@localhost]$ g++ example.cpp
[k5054@localhost]$ g++ example.cpp -Wall
[k5054@localhost]$ g++ example.cpp -Wextra
example.cpp: In function ‘int main()’:
example.cpp:12:11: warning: missing initializer for member ‘S::f’ [-Wmissing-field-initializers]
   12 |     S  s{0};
      |           ^
example.cpp:12:11: warning: missing initializer for member ‘S::d’ [-Wmissing-field-initializers]
[k5054@localhost]$ 

honey the codewitch wrote:

there was a cleaner way to do this stuff