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No. Nobody here is going to do your homework for you. No matter how many times you repost it.
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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Since this is a standard class project one would expect the teacher to cover all of this.
First step.
1. Learn basics of C (or C++)
2. Learn basics of compiling C.
3. Write a hello world program.
4. Learn how methods work. Write methods that add, subtract, etc, and nothing else.
Next steps depends on how the calculator works.
If a console
1. Learn about stdin and stdout
2. Learn how to run application to read keyboard input and output response
If a UI. This is MUCH harder than above.
1. Find a C UI library
2. Learn basics of that
3. Design calculator UI look.
4. Implement UI look
5. Learn how to tie the UI into C method calls.
Final step - Put all of the above together to build your app.
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Do you realize your post is nearly useless?
We need far more details in order to help you.
"In testa che avete, Signor di Ceprano?"
-- Rigoletto
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I would have said completely useless.
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"In testa che avete, Signor di Ceprano?"
-- Rigoletto
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CP could make it a requirement that with any request for having someone doing your homework for you, the name and email of the professor must be specified, so we know where to go to obtain more details about the task.
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Hi,
Is this how it should be done?
int Strawberry = 10;
int * PointerInd0 = &Strawberry;
int ** PointerInd1 = &PointerInd0;
// I’m not sure what comes next
int *** PointerInd2 = &PointerInd1;
Sorry I’m not enclosing the source code in code tags, I don’t have edit options on mobile.
modified 14-Sep-23 9:15am.
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Calin Negru wrote:
int *** PointerLvl3 = &PointerLvl2;
Yes, indeed. You can continue with as many levels of indirection as you wish (although I don't remember needing more than two).
Mircea
modified 14-Sep-23 9:29am.
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If that is true then this simple assign address to is a bit deceiving because you still have to remember what PointerInd2 is, you need special syntax to access Strawberry from PointerInd2
***PointerInd2 = 31; // just a guess
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Calin Negru wrote: ***PointerInd2 = 31; // just a guess
Yes, nothing wrong with that. I don't see why you see it as deceiving. If you miss one of the indirection operators and you write:
**PointerInd2 = 31; compiler will flag it with an error like "cannot assign 'int' to 'int*' ".
But, again, cases where you need more than two level on indirection are exceedingly rare. Probably because we humans aren't great at keeping track of stack levels.
Mircea
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>I don’t see why you see it as deceiving
It’s just a single &sign one that could make you believe it’s a typical pointer you’re dealing with. You need to be in a high alert so to speak and always have in mind what you have declared.
modified 14-Sep-23 16:05pm.
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Calin Negru wrote: you believe it’s a typical pointer you’re dealing with.
The developer should of course be aware of the code they are writing/modifying.
And this should not be something that is used very often.
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>The developer should of course be aware
I know. If you look at the address assignation alone you don’t have a clue what that is (Something = &SomethingElse) you have look at the declaration to figure it out. Sorry if that sounds like repeating the same thing. What I’m saying is that it’s not your C# fire and forget.
modified 15-Sep-23 3:36am.
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Correct, I think. A simple test program would confirm that, but I'm not feeling the urge.
But if you need more than two or three levels of indirection, then the problem space should lead to sensible variable naming. That and intelligent comments should make your intent clear. And, of course, you've got typedefs or C++ using statements to help reduce the brain cramp that I find multiple indirection sometimes brings. If you're using C++, you also have references which might help reduce the (apparent) levels of indirection going on.
Keep Calm and Carry On
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int Strawberry = 10;
int * PointerInd0 = &Strawberry;
std::cout << "*PointerInd0: " << *PointerInd0 << std::endl;
int ** PointerInd1 = &PointerInd0;
std::cout << "**PointerInd1: " << **PointerInd1 << std::endl;
int *** PointerInd2 = &PointerInd1;
std::cout << "***PointerInd2: " << ***PointerInd2 << std::endl;
int **** PointerInd3 = &PointerInd2;
std::cout << "****PointerInd3: " << ****PointerInd3 << std::endl;
Results:
*PointerInd0: 10
**PointerInd1: 10
***PointerInd2: 10
****PointerInd3: 10
And so until the compiler or the application gives up. If you are really interested then get an assembly listing and see what the machine code is doing.
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Thank you Richard, you make it clear.
modified 14-Sep-23 16:02pm.
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You're welcome. It always helps to look at actual code.
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I have changed my mind about what I want to ask. I’m not interested in groups anymore.
How do you solve units colliding at all? If it’s just two units is it about where the two units have been ( last visited node ) and where they are traveling towards?
Also what if a unit collides with more than one unit in a short amount of time?
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Hi,
It sounds like you just need a push in the right direction. Have a look at the Flow Field family of algorithms.
Flow field algorithm
Did you have a C++ related question to ask?
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Randor wrote:
It sounds like you just need a push in the right direction.
Heh, I thought the paronomasian response was clever but I doubt anyone noticed. 
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