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Do you have a googleupdate app running on your PC?
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yeah, is that the magic?
i have google toolbar installed
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Raj Aryan 1001 wrote: yeah, is that the magic?
Yep.
Sorry I misunderstood what you were asking.
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that's brilliant, you cracked it
these hidden services can do anything
you are just brilliant, thanks
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Raj Aryan 1001 wrote: it would be great , is'nt it?
No. If one user were able to install an app, remove an app, or alter an app in a way that affects all users of the system, it would not be great. It would be unsafe.
Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum
Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.
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yeah correct, but if application can get installed atleast for signed on user without uac prompts then it would be better i think (if it asks for admin password and user does not have admin password then user will not be able to install it and may be google chrome can be installed, will check)
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Hi,
I am trying to make a brick game. I want to have a class for the players ball. The ball will split in 3 when a certain item is collected. The code compiles fine but when it runs it gives me the error "Object reference not set to an instance of an object." Also what's the best way of writing the code for 3 ball objects without having to duplicate code 3 times. Thanks.
#include "stdafx.h"
using namespace System;
using namespace System::Drawing;
using namespace System::Windows::Forms;
public ref class Ball
{
public:
PictureBox^ gameBall;
int speed;
double xVel;
double yVel;
Ball()
{
}
void Add_to_form( Form ^ form )
{
speed = 5;
xVel = speed;
yVel = speed;
gameBall = gcnew PictureBox();
gameBall->BackColor = Color::LimeGreen;
gameBall->Size = Drawing::Size(20,20);
gameBall->Location = Drawing::Point(form->Width/2-35,form->Height/2-50);
form->Controls->Add(gameBall);
}
};
public ref class Form1 : public Form
{
public:
PictureBox^ paddlePlayer;
Timer^ gameTimer;
Ball ball1;
Form1()
{
this->Size = Drawing::Size(640,480);
this->BackColor= Color::SkyBlue;
this->MouseMove += gcnew System::Windows::Forms::MouseEventHandler(this, &Form1::pongMain_MouseMove);
gameTimer = gcnew Timer();
gameTimer->Interval = 20;
gameTimer->Start();
gameTimer->Tick += gcnew System::EventHandler(this, &Form1::gameTimer_Tick);
paddlePlayer = gcnew PictureBox();
paddlePlayer->BackColor = Color::LimeGreen;
paddlePlayer->Size = Drawing::Size(128,16);
paddlePlayer->Location = Drawing::Point(this->Width/2,this->Height-65);
this->Controls->Add(paddlePlayer);
this->Controls->Add(ball1.gameBall);
}
System::Void pongMain_MouseMove( Object^, System::Windows::Forms::MouseEventArgs^ e)
{
if(e->X < this->Width-paddlePlayer->Width - 18)
{
paddlePlayer->Location = Drawing::Point(e->X,paddlePlayer->Location.Y);
}
}
System::Void gameTimer_Tick(System::Object^ sender, System::EventArgs^ e)
{
ball1.gameBall->Location = Point(ball1.gameBall->Location.X + Convert::ToUInt32(ball1.xVel), ball1.gameBall->Location.Y + Convert::ToUInt32(ball1.yVel));
if(ball1.gameBall->Location.Y < 0)
{
ball1.gameBall->Location = Point(ball1.gameBall->Location.X, 0);
ball1.yVel = -ball1.yVel;
}
if(ball1.gameBall->Location.Y > this->Height - ball1.gameBall->Size.Height - 45)
{
ball1.gameBall->Location = Point(ball1.gameBall->Location.X, this->Height - ball1.gameBall->Size.Height - 45);
ball1.yVel = -ball1.yVel;
}
if(ball1.gameBall->Location.X > this->Width - ball1.gameBall->Size.Width-25)
{
ball1.gameBall->Location = Point(ball1.gameBall->Location.X,ball1.gameBall->Location.Y);
ball1.xVel = -ball1.xVel;
}
if(ball1.gameBall->Location.X <= 0)
{
ball1.gameBall->Location = Point(ball1.gameBall->Location.X,ball1.gameBall->Location.Y);
ball1.xVel = -ball1.xVel;
}
if(ball1.gameBall->Bounds.IntersectsWith(paddlePlayer->Bounds))
{
ball1.gameBall->Location = Point(ball1.gameBall->Location.X,ball1.gameBall->Location.Y);
ball1.yVel = -ball1.yVel;
}
}
};
[STAThread]
int main()
{
Application::Run(gcnew Form1());
}
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Please repost your message in Managed c++/CLI forum.
"Every Little Smile can touch Somebody's Heart...
May we find Hundreds of Reasons to Smile Everyday... and
May WE be the Reason for someone else to smile always!" (ICAN)
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Just create three instances of your Ball class. Instead of managing a single Ball instance, use a list of Balls, even when you only have one entry. Iterate over the list of balls each frame.
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Thanks for the suggestion. It helped.
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Hi,
I have created my own ownerdrawn menu, subclassed from CMenu, implementing the MeasureItem and DrawItem methods, which works flawlessly so far. However, I would like to change the visual appearance of the complete menu border, i.e. not the border of single menu items, but the whole menu border instead. Is there a good way to achieve this? Which method do I have to reimplement?
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I recently have my huffman coding work by storing all of the character frequencies in an array sorted. The coding gives me the correct binary string for each character, but that is just for the characters in the array. What if I want to encode and display the binary characters coming from how they are arranged in the file itself?
Basically, my idea is that get each of these characters in the file and store them in a char string so that I can encode them from that point on. However, my program is weird because it outputs some characters but most are just blank. This is a section of the code that gets the characters from an input file and store them into a character array. counts_char is a function that gets the frequencies of each character; it also makes its instance of an input file stream.
char *stringChar;
ifstream infile( "project2input.txt" );
infile.seekg (0, ios::end);
size = infile.tellg();
stringChar = new char[size];
while(!infile.eof())
infile>>noskipws>>stringChar;
infile.close();
counts = new int[256];
count_chars( counts );
for (int k = 0; k<size; k++)
cout<<stringChar[k];
The output looks like this:
l ░↨l
♦ ^♂ É l É l 8 l 8 l 0l ╨
List of characters in the file with their frequencies:
E (0.0351617)
J (0.0351617)
- (0.0351617)
0 (0.0351617)
2 (0.0351617)
3 (0.0351617)
4 (0.0351617)
5 (0.0351617)
6 (0.0351617)
7 (0.0351617)
8 (0.0351617)
9 (0.0351617)
I (0.0703235)
M (0.0703235)
N (0.0703235)
O (0.0703235)
U (0.0703235)
W (0.0703235)
q (0.0703235)
z (0.0703235)
G (0.0703235)
1 (0.0703235)
T (0.105485)
k (0.105485)
C (0.175809)
x (0.21097)
; (0.246132)
j (0.246132)
S (0.281294)
. (0.351617)
A (0.457103)
v (0.703235)
w (0.914205)
g (0.949367)
y (1.16034)
, (1.6526)
f (1.86357)
b (1.89873)
u (1.9339)
m (2.00422)
(2.03938)
p (2.14487)
c (2.391)
d (2.63713)
l (3.41069)
h (3.44585)
s (4.99297)
i (5.16878)
r (5.30942)
a (5.37975)
o (5.66104)
n (5.9775)
t (6.8917)
e (10.9001)
(15.225)
2899 characters
Char Symbol Codes:
E = 0000000000000000000000000000000000000000000000000000001
J = 000000000000000000000000000000000000000000000000000001
- = 00000000000000000000000000000000000000000000000000001
0 = 0000000000000000000000000000000000000000000000000001
2 = 000000000000000000000000000000000000000000000000001
3 = 00000000000000000000000000000000000000000000000001
4 = 0000000000000000000000000000000000000000000000001
5 = 000000000000000000000000000000000000000000000001
6 = 00000000000000000000000000000000000000000000001
7 = 0000000000000000000000000000000000000000000001
8 = 000000000000000000000000000000000000000000001
9 = 00000000000000000000000000000000000000000001
I = 0000000000000000000000000000000000000000001
M = 000000000000000000000000000000000000000001
N = 00000000000000000000000000000000000000001
O = 0000000000000000000000000000000000000001
U = 000000000000000000000000000000000000001
W = 00000000000000000000000000000000000001
q = 0000000000000000000000000000000000001
z = 000000000000000000000000000000000001
G = 00000000000000000000000000000000001
1 = 0000000000000000000000000000000001
T = 000000000000000000000000000000001
k = 00000000000000000000000000000001
C = 0000000000000000000000000000001
x = 000000000000000000000000000001
; = 00000000000000000000000000001
j = 0000000000000000000000000001
S = 000000000000000000000000001
. = 00000000000000000000000001
A = 0000000000000000000000001
v = 000000000000000000000001
w = 00000000000000000000001
g = 0000000000000000000001
y = 000000000000000000001
, = 00000000000000000001
f = 0000000000000000001
b = 000000000000000001
u = 00000000000000001
m = 0000000000000001
= 000000000000001
p = 00000000000001
c = 0000000000001
d = 000000000001
l = 00000000001
h = 0000000001
s = 000000001
i = 00000001
r = 0000001
a = 000001
o = 00001
n = 0001
t = 001
e = 01
= 1
The portion before the list of characters is the one where the characters are supposed to be printed out as they were in the file.
Please help me with this. Thank you.
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Francis Paran wrote: infile.seekg (0, ios::end);
When do you seek back to the beginning?
Francis Paran wrote: infile>>noskipws>>stringChar;
Is this supposed to append to stringChar?
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"Some people are making such thorough preparation for rainy days that they aren't enjoying today's sunshine." - William Feather
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I already got it working by having the ifstream variable initialized at the end using the ios::ate parameter on its instance. Thank you for the advice. I wouldn't have realized what I did wrong if it wasn't for your intuitive question, asking me when I seek back to the beginning.
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Hi, i need to write a code which can convert a raw image to anyother desired format like BMP or JPEG etc.
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Howdy.
Best you get cracking then - or find a "ken I hav the codez plz" site.
If you had the slightest inkling of what you're doing, you'd realize that about a man-year's worth of work goes into a typical jpeg encoder. With that said, your option of (1) get (image file) format specification documents (2) Write appropriate code, will not work in a timely fashion.
You'll need to find libraries that are suitable for you, in terms of (a) price and (b) compatibility with your code and other libraries.
Have fun young jedi!
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Spot-on, Spartan! Marked as "correct answer". 
"Real men drive manual transmission" - Rajesh.
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You don't need any library
Just use Shell apis (1 line of code to convert any format into any other format)
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The Image::Save method that belongs to the GDI+ library can convert between certain formats.
There is a library call FFmpeg[^] that can do practically whatever you can think of.
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another option CImage class, which in turn uses Gdi+ calls. Use it's Save method.
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Hello,
I am C++/VC++ developer. I have query from long time in my mind, what is difference between 16bit/32bit/64bit OS and how (why) it affets softwares(exe/dlls). And how int size is related with all this. Like in 16 bit enviroment int is of 2 byte and so on..
Regards
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Basically, the OS bitness has to do with the address range that the OS can use.
Considering a flat address space, 16-bit OSs can use addresses from 0 to 65536 (2 to the power 16).
Similarily for 32-bit OS it will be 0 to 4294967296 (4 GB) and for 64-bit OS it will be 0 to 18446744073709551616 (whatever).
This means as the bitness increases, the OS can handle more code and data.
The processor also needs to be matched for bitness.
This means, a 32-bit processor cannot host a 64-bit OS.
But a 64-bit processor can host a 64-bit, 32-bit or 16-bit OS.
This is because the internal storage of the processor (registers) must be wide enough.
In the case of intel processors, 16-bit processors have 16-bit registers like AX, BX, CX, DX etc.
32-bit processors have 32-bit registers like EAX, EBX, ECX, EDX etc.
And 64-bit processors have 64-bit registers like RAX, RBX, RCX, RDX etc.
This is why the size of data types like int changes.
However, for 64-bit Windows, the size of int is still 32-bit.
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