C / C++ / MFC

manju#123 wrote:

_TCHAR *csUserName
csUserName = "manju";

manju#123 wrote:

I want to remove to ";" character ..

Jijo raj wrote:

Do you mean that your username is read from user directly and you want to remove all ; from it?

CString csUserName = "User;Name;";
csUserName.Remove( ';' );

_TCHAR *csUserName,coUserName;
CString UserName

if(_tcsicmp(it->first, "USERNAME") == 0)
{                 
 csUserName = const_cast<_TCHAR*>(it->second);
 UserName = CString(_T(csUserName));				
 UserName.Remove(';');
 coUserName = (LPCTSTR) (LPSTR)UserName;
 login[iServerCtr].sUserName = coUserName;
}

manju#123 wrote:

But i am getting some error..
Plz check i am correct or no..

Jijo raj wrote:

Could you please provide the error description?

CString UserName(it->first)
UserName.Remove(';');
if(UserName.CompareNoCase("USERNAME") == 0)
{

 //now if login[].sUserName is a pointer then 
   if(login[iServerCtr].sUserName)
        delete [] login[iServerCtr].sUserName;
   login[iServerCtr].sUserName = new TCHAR[_MAX_PATH];
//if its defined as array you don't need the above three lines
 
  //finally
   _tcscpy( login[iServerCtr].sUserName, UserName);
}//if

theCPkid wrote:

Also in first line of your code TCHAR *csUserName,coUserName

theCPkid wrote:

try coUserName = UserName.GetBuffer();

theCPkid wrote:

coUserName = (LPCTSTR) (LPSTR)UserName;

_TCHAR *csUserName,*coUserName;
CString UserName

if(_tcsicmp(it->first, "USERNAME") == 0)
{                 
 csUserName = const_cast<_TCHAR*>(it->second);
 UserName = CString(_T(csUserName));				
 UserName.Remove(';');
 coUserName = UserName.GetBuffer;
 login[iServerCtr].sUserName = coUserName;
}

theCPkid wrote:

You tried GetBuffer and not GetBuffer() [Red faced]

TCHAR *pos = _tcschr(csUserName, _T(';'));
*pos = _T('\0');

C# Beginner Nick wrote:

No intent on blaming, i assure you. What i was trying to say was, that your help was ended at that point and i need some more.

C# Beginner Nick wrote:

creating a setup.exe that is in the Other Projects node, i don't have that.