C / C++ / MFC

garyflet wrote:

How does the server know which clients, if any, are still attached?

garyflet wrote:

When my automation client calls COleDispatchDriver::ReleaseDispatch(), thus releasing the server, the server receives a WM_CLOSE message. If there are other clients still connected, the server,if visible, is supposed to display a message to that effect and offer to close.

garyflet wrote:

If invisible, the server simly doesn't close.

Roger Stoltz wrote:

I may be misinterpreting your question, but this is done by reference counting.
The server will in general not know anything about its clients, it only knows that it has one or more clients attached to it.

Roger Stoltz wrote:

From your question I assume you're talking about an application that runs as an out-of-process COM server. I wouldn't expect the server to close, or even the WM_CLOSE message being sent, unless the reference count reaches zero. Popping a dialogue asking the user whether to shut down the server or not seems a bit odd since there shouldn't be any clients left.

garyflet wrote:

My MDI server has a CCmdTarget derived class: CAutoApp. I noted that CAutoApp gets created with every new client connection

garyflet wrote:

After any client calls ReleaseDispatch(), my server gets a WM_CLOSE message whether or not there are any clients left.

garyflet wrote:

why do I get a WM_CLOSE message even when there are clients left?

Steve Thresher wrote:

Can someone tell me if this is possible

Nandu_77b wrote:

if ( (' ' != *from ) || ('\t' != *from))

SandipG wrote:

Nandu_77b wrote:

if ( (' ' != *from ) || ('\t' != *from))

Don't you think it should be &&

Can anyone confirm??

Nandu_77b wrote:

string removeSpaces( string & str )
{
std::string::iterator to = str.begin();
std::string::iterator from;

for( from = str.begin(); '\0' != *from; ++ from )
{
if ( (' ' != *from ) || ('\t' != *from))
*(to ++) = *from;
}
if( *to != '\0' )
str.erase(to, from);

*to = '\0';
return str;
}

string removeSpaces( string & str )
{
  std::string::iterator to = str.begin();
  std::string::iterator from;

  for( from = str.begin(); str.end() != from; ++from )
  {
    if ( (' ' != *from ) && ('\t' != *from))
      *(to++) = *from;
  }
  if( to != str.end() )
    str.erase(to, from);
}

std::string& removeSpaces( std::string& str )
{
	std::string::iterator to = str.begin();
	std::string::iterator from = to;

	// Loop until we reach the end of the string
	while( from != str.end() )
	{
		// Check if the current char is a space OR a tab
		if( (*from == ' ') || (*from == '\t') )
		{
			// The current char is a space OR a tab, skip it!
			++from;
		}
		else
		{
			// The current char is NOT a space or a tab, copy it!
			*to++ = *from++;
		}
	}
	
	// If the iterator has not reached the end of the string, delete the rest
	if( to != str.end() )
	{
		str.erase( to, from );
	}

	// Return a REFERENCE to the same string we got as formal parameter
	// instead of making a copy of it on the stack
	// There's no point in returning a copy since the function operates
	// directly on the provided string buffer
	return str;
}