|
|
OP means ? is it Original Poster ?
Regards,
Paresh.
|
|
|
|
|
for what i understand, yes...
|
|
|
|
|
How does a server manages to accept another connection when already one client is connected. Does it assignes a different port for different clients?
KIRAN PINJARLA
|
|
|
|
|
The server has a listener socket that waits to accept client connections - this is the accept(...) function. Once a client connection is accepted, it's assigned a new (seperate) client-socket - this is the return value from the accept(...) function. This client socket is used to communicate with the client (can be passed to a seperate thread) while the server can continue waiting for more clients with the listener socket by calling accept(...) again, and so on ...
Hope this helps ...
Guy.
|
|
|
|
|
Hi!
I want to set the bitrate at the time of encoding proccess can any body help me for this?
Thanks in advance.
"Success lies not in the result , But in the efforts !!!!!"
Amit Mistry - petlad -Gujarat-India
|
|
|
|
|
CShare dg;
dg.Domodal();
addlog();
Above mention is my code. when I call addlog after Domodal . It gives me an unhandled exception error and go to heap memory functions. but when I call addlog before the Domodal it executes fine.Please any one suggest some solution for this problem
S.yamini
|
|
|
|
|
What is addlog ? and what does work?
|
|
|
|
|
I have generated a MAP file for an MFC application with two threads. The load address in the MAP file is 0x00400000. But the program is showing a run-time error for an instruction at 0x77fcca41 which is refering to memory at 0xffffffff that could not be read. But there are no instruction at 0x77fcca41 in the MAP file. I would like to know whether anyone has come across such a problem and was able to trace the cause. If so some help is required
|
|
|
|
|
Debugging release builds using map files is outdated, unnecessary and inefficient. Simply enable debug information for your release build (be sure to do so for the compiler and linker) and debug as normal.
Steve
|
|
|
|
|
That address is in one of the OS DLLs. If you can repro the crash, run the EXE in the debugger and look at the stack trace when the crash happens. You can then look up the addresses that are on the stack.
|
|
|
|
|
HI im currently doing a proj on time capturing.... So i have a push button switch connected to the Rs232 to TTL Converter...the Rs232 in connected to the pc.. So can anybody help to give me the program to capture the time when the push button is pressed....Thanx
-- modified at 1:17 Thursday 26th April, 2007
|
|
|
|
|
braleping,
welcome to code project. Cross posting your messages to mulitple forums is not considered appropriate. Also where you ask for someone to "give me the program" please read the first message at the top of the forum "How to get an answer to your question"[^] Specifically item #2
led mike
|
|
|
|
|
hi friends,
pls any one give the code to upload vedio files in the database and retrieving these from database to one aspx page.its very urgent.
prasanna
|
|
|
|
|
See here.
"A good athlete is the result of a good and worthy opponent." - David Crow
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
|
|
|
|
|
does anyone know how to convert FAT to CDFS?
give me some source code please
|
|
|
|
|
That sounds like an odd requirement. Please explain.
"A good athlete is the result of a good and worthy opponent." - David Crow
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
|
|
|
|
|
how to replace '............344' with empty string from the string like:
'1. visual basic.net ............344'
i am using regular expression in vb.net
this is the sample code
sText = Regex.Replace(sText, " (\\.+)\\d+", "");
thanx
|
|
|
|
|
Im sorry but I dont understand what you said you have a string (...344) and now you want to replace this string with null string on c++ ?
|
|
|
|
|
This is a C++ forum!
Steve
|
|
|
|
|
After I've created a new resource (IDD_TBL_A_DLG) and open ClassWizard, ClassWizard tells me I have a new resource and do I want to create a new class for it. When I try to create the class for this resource, I get the following:
"Unable to open the files (C:\RetPlan\TableA.h, C:\RetPlan\TableA.cpp) for class CTableA".
However, the .cpp and .h files are created but the Wizard can not add to them!
Can anyone clue me in as to what is going on? This is a VC++ 6.0 Project and is 'dialog-based'.
John P.
|
|
|
|
|
jparken wrote: "Unable to open the files (C:\RetPlan\TableA.h, C:\RetPlan\TableA.cpp) for class CTableA".
However, the .cpp and .h files are created but the Wizard can not add to them!
Can anyone clue me in as to what is going on? This is a VC++ 6.0 Project and is 'dialog-based'.
Delete .aps, .clw, and .ncb files and restart IDE.
|
|
|
|
|
jparken wrote: Can anyone clue me in as to what is going on? This is a VC++ 6.0 Project and is 'dialog-based'.
It's a known bug with VS6. The files get created, but ClassWizard just doesn't know about them. Clean up the project's temporary files, and then restart the IDE.
"A good athlete is the result of a good and worthy opponent." - David Crow
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
|
|
|
|
|
Thanks very much. This is the first time this had happened to me.
John P.
|
|
|
|
|
I am trying to hash a password using MD5 to get the resultant digest. These are taken from the example I am following (which is from a trusted authority):
• First get the bytes of the original password, assuming a "Latin-1" encoding. For the password "Baltimore1," these bytes are: 66 97 108 116 105 109 111 114 101 49 44 (i.e. the value of "B" is 66, "a" is 97, etc).
• Then get the MD5 hash of these bytes. MD5 is a standard, public algorithm. Once again, for the password "Baltimore1," these bytes work out as: 223 238 161 24 62 121 39 143 115 167 51 163 245 231 226 94
• Finally, create the new password by forming a string whose Latin-1 encoding is the bytes from the previous step. For the "Baltimore1," password, if this is string is written to the screen, it looks like: ßî¡_>y'?s§3£õçâ^(i.e. the 62 above is a ">", the 121 is a "y", etc).
However, whenever I perform the hash I don't get the same result, I get:
6, 156, 90, 148, 160, 205, 176, 131, 162, 231, 168, 208, 232, 207, 90, 241
and string: œZ” Í°ƒ¢ç¨ÐèÏZñ
The code extract I am using is:
...<br />
unsigned char* pszPwd = simple_digest( "md5", "Baltimore1", strlen("Baltimore1"), &len );<br />
...<br />
<br />
unsigned char* simple_digest( char* alg, char* buf, unsigned int len, unsigned int* olen )<br />
{<br />
const EVP_MD* m;<br />
EVP_MD_CTX ctx;<br />
unsigned char* ret;<br />
<br />
OpenSSL_add_all_digests();<br />
<br />
if ( !( m = EVP_get_digestbyname( alg ) ) )<br />
{<br />
return NULL;<br />
}<br />
<br />
if ( !(ret = (unsigned char*)malloc(EVP_MAX_MD_SIZE)) )<br />
{<br />
return NULL;<br />
}<br />
<br />
EVP_DigestInit( &ctx, m );<br />
EVP_DigestUpdate( &ctx, buf, len );<br />
EVP_DigestFinal( &ctx, ret, olen );<br />
<br />
return ret;<br />
}
This is using the OpenSSL library. I tried to do the hash with completely seperate code that performs a MD5 hash and it came to the same result!
Can anyone PLEASE point me to where I am going wrong?
|
|
|
|
General 
News 
Suggestion 
Question 
Bug 
Answer 
Joke 
Praise 
Rant 
Admin 
Submit an article or tip
