C / C++ / MFC

Vaclav_Sal wrote:

if(!bmp->CreateBitmapIndirect((BITMAP * ) m_Doc->m_lpBi))

Mark Salsbery
Microsoft MVP - Visual C++

mjackson11 wrote:

When I try to define setID in the derived class

template<class _ty=""> void fwdCurve<_Ty>::setID(dbID id)

I get a C2244:   indexedObject::setID : unable to match function definition to an existing declaration

mjackson11 wrote:

I am able to work around this by declaring setID() in the derived class definition and explicitly calling the base class method but why is this happening?

mjackson11 wrote:

If I define setID in the derived class declaration, when I implement it, it does not call the base class setID method. Seems like the compiler is defining them as two different methods instead of the derived class inhereting.

#include <iostream>

class Base
{
public:
   void A() { std::cout << "Base::A\n"; }
   void B() { std::cout << "Base::A\n"; }
   virtual void C() { std::cout << "Base::C\n"; }
};

class Derived : public Base
{
public:
   void A() { std::cout << "Derived::A\n"; }
   virtual void C() { std::cout << "Derived::C\n"; }
};

void VirtualTest(Base* pBase, const char* objName)
{
   std::cout << "Calling pBase->A() with pBase = " << objName << "...\n";
   pBase->A();
   std::cout << "Calling pBase->C() with pBase = " << objName << "...\n";
   pBase->C();
}

int main(int, char**)
{
   Base base;
   Derived derived;

   std::cout << "Calling base.A()...\n";
   base.A();
   std::cout << "Calling base.B()...\n";
   base.B();
   VirtualTest(&base, "&base");

   std::cout << "Calling derived.A()...\n";
   derived.A();
   std::cout << "Calling derived.B()...\n";
   derived.B();
   VirtualTest(&derived, "&derived");
}

Calling base.A()...
Base::A
Calling base.B()...
Base::A
Calling pBase->A() with pBase = &base...
Base::A
Calling pBase->C() with pBase = &base...
Base::C
Calling derived.A()...
Derived::A
Calling derived.B()...
Base::A
Calling pBase->A() with pBase = &derived...
Base::A
Calling pBase->C() with pBase = &derived...
Derived::C