C / C++ / MFC

tayyyar wrote:

but something wrong

tayyyar wrote:

...but something wrong...

tayyyar wrote:

ıwas complie many times but the program coming we can say read when ı execute program ısaw the window just
"access1 "
and then stop and givme error .

after that ı have to shutdown the program.

I'm stuck ı have no idea how can ı get rid of that ?

some people say give me spesific ı think this message a little bit specific .

tayyyar wrote:

some people say give me spesific ı think this message a little bit specific .

tayyyar wrote:

ı have got an appointment my lecturer next week for this program .

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<time.h>

#define size 9     //Don't use #define for your constants. Instead use the const keyword and the desired type of the object you are creating.
#define size2 81

int checkingSquare(int *i, int *j, int *row, int *column, int **a);

int main()
{
     int i, j, row, column, controller = 0; //Only controller is being initialised to zero here. 
     int **a = 0;

     srand(time(NULL));
     for(i = 1; i < 10; i++)
     {//start for1 NOTE: there is no need to place comments like this showing which braces match
      //up if you have properly formatted your code with indentations like I have done for you.     
          for(j = 1; j < 10; j++)
          {//start for2
               while(controller == 0)
               {
                    printf("access1");
                    controller = checkingSquare(&i, &j, &row, &column, a);
               }
          }//end for 2

     }//end for 1

     for(i=1;i<10;i++)
     {
          for(j=1;j<10;j++)
          {
               printf("%d\n",a[i][j]);
          }
     }
     return 0;
}

void square(int *inte, int *inte2, int *row, int *column)
{
     *row = *inte / 3;
     if(*row != 1)
     {
          *row++;
     }
     *column=*inte2 / 3;

     if(*column != 1)
     {
          *column++;
     }
}

int checkingSquare(int *i, int *j, int *row, int *column, int **f)
{
     int x, y;
     *(*(f + *i) + *j) = rand() % 9 + 1; //Terrible code. Very hard to read. Not to mention when debugging you are causing an access violation 
                                         //when code execution reaches this line. This is probably where your problem lies. I suggest you learn
                                         // to use your debugger as this is something that should have taken you about 30 seconds to spot.
     printf("access");

     //checkin big squares
     square(i, j, row, column); //to determine which big square we are in
     for(x = (*row * 3 - 2); x < (*row * 3 + 1); x++)
     {
          for(y = *column * 3 - 2; y < *column * 3 + 1; y++)
          {
               if(f[x][y] == f[*i][*j])
               {
                    return 0;
               }
          }
     }

     //checkin sides
     for(x = 1; x < 10; x++)
     {
          if(f[x][*j] == f[*i][*j])
          {
               return 0;
          }
     }

     for(y = 1; y < 10; y++)
     {
          if(f[*i][y] == f[*i][*j])
          {
               return 0;
          }
     }

return 1; //common convention is to return ZERO (0) at the end of int main(). 
//The program that ran your program may or may not interpret the value you return,
// but in the case that it does, it may mis-interpret the 1 you have returned as an error. 
}

sahih wrote:

Yes, my stepper motor driver supports serial port communication.

rbwest86 wrote:

I was wondering if I would keep int main() completely separate, and then have the function which retrieves the local computer name a subclass of the retrieval process. I am more or less trying to organize my program.

rbwest86 wrote:

Question Number three, where can I find a good reading for retrieving information via the registry? I have looked on MSDN and did not find a registry library.

rbwest86 wrote:

I was wondering if I would keep int main() completely separate, and then have the function which retrieves the local computer name a subclass of the retrieval process. I am more or less trying to organize my program.