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Hi,I have one final project about chat application. this application has login panel which are username and password, client and server panel. I tried to finish this project but I have a problem this problem is when the client send a message all of client can see this message but I want to send this message only who I want to send it. I have a user list and I did this list as well. I know my problem is the client message send to the server and server send all of clients and all of clients connected localhost. so How can I fix this problem, Please someone helps me about my project. If it is possible someone can send solving java codes. Thank you alls.
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You need to define to which client you want to send the message.
Tell the server whom you want to chat to and let the server select the client you choose. For this, each client should have a unique IP - or (on localhost) at least a unique port, on which the client is reachable.
greets
Torsten
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Hi
I have a problem with my graph colouring code,have pasted my methods which I believed were correct until I found two different answers whn using algorithm and code.
Its about colouring different countries using minimul different colours.
Im supposed to get an array[0,0,1,1,2,2,2,2,2,1].
but i get [0,0,0,0,0,0,1,1,0,0].
pliz help.
public void ApproxColour(){
int v, new_colour;
for(v = 0; v<CountryList.size(); v++){
colour[v] = -1;
}
sortVertices();
colour[0]=0;
for(int i=1; i<CountryList.size(); i++){
colour[i] = FindSmallestfreecolour(sorted_country[i]);
}
System.out.println(Arrays.toString(colour));
//return colour;
}
public int FindSmallestfreecolour(String Country){
int w;
boolean used[] = new boolean[CountryList.size()];
for(w=0; w<CountryList.size();w++){
if(isAdjacent(Country, CountryList.get(w).getName()) && colour[w] != -1){
used[colour[w]] = true;
}
}
w=0;
while (used[w])
w++;
return w;
}
public void sortVertices(){
int position = 0;
//System.out.println(Arrays.toString(degrees));
for(int j = 0; j < degrees.length; j++){
int Largest = getLargestDegree();
sorted[position] = Largest;
degrees[Largest] = -1;
position++;
country[j] = CountryList.get(j).getName();
}
//System.out.println(Arrays.toString(sorted));
int var;
for(int i=0; i<sorted.length; i++){
var = sorted[i];
sorted_country[i] = country[var];
}
//System.out.println(Arrays.toString(sorted_country));
}
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I am writing a web-based system with java. There are some labels and reports printing. Each requires different printers which are connected to the same client computer.
How could I set so that, when I Print Doc A, document A would print to printer A, and when clicked Print for Doc B, document B would print to printer B.
The URL for both the documents are different. doc A is on http://www.xyz.com and doc b is on http://www.abc.com.
info: It is a web-based system used within a lan. So each user use the system with a fixed computer.
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i started to learn java. i have middle level information about visual c# and C languages. how can i find electronical project about java ?let me suggest some learning way java language.i need some sample projects and codes.
Thanks for reading this message.
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Hi, i got this problem when i retrieve my array
Result = [org.me.sms.Records@71cb25, org.me.sms.Records@cff49f, org.me.sms.Records@c510e3]
how do i retrieve the orignator and text of it?
This is my web service code
@WebMethod(operationName = "RetrieveSMS")
public Records[] RetrieveSMS(@WebParam(name = "username") String username, @WebParam(name = "password") String password, @WebParam(name = "keyword") String keyword) {
ArrayList list = new ArrayList();
ResultSet rs = null;
String statement=null;
try {
Connection conn = null;
Class.forName("oracle.jdbc.driver.OracleDriver");
conn = DriverManager.getConnection("jdbc:oracle:thin:@127.0.0.1:1521:xe", "smslib", "smslib");
Statement s = conn.createStatement();
statement = "Select * from app_"+keyword;
rs = s.executeQuery(statement);
Records r=null;
while(rs.next())
{
r = new Records();
r.setNumber(rs.getLong("originator"));
r.setText(rs.getString("text"));
list.add(r);
}
s.close();
conn.close();
return (Records[])list.toArray(new Records[list.size()]);
} catch (Exception ex) {
ex.printStackTrace();
}
return null;
}
and my java file
public class Records {
private long number;
private String text;
public long getNumber()
{
return number;
}
public void setNumber(long num)
{
this.number = num;
}
public String getText()
{
return text;
}
public void setText(String text)
{
this.text = text;
}
}
This is my JSP that call the method
<%
try {
org.me.sms.SMSWebServiceService service = new org.me.sms.SMSWebServiceService();
org.me.sms.SMSWebService port = service.getSMSWebServicePort();
java.lang.String username = "";
java.lang.String password = "";
java.lang.String keyword = "Temp";
java.util.List<org.me.sms.Records> result = port.retrieveSMS(username, password, keyword);
out.println("Result = "+result);
} catch (Exception ex) {
}
%>
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I do know how to access an array.
But my code does it in a different way.
First it adds my Record object into an arraylist called list and it returns this
return (Records[])list.toArray(new Records[list.size()]);
The above code i took from some tutorial that teach me how to return a database record into a WEB SERVICE method.
In my client index.jsp, i consume the web service with the following code
org.me.sms.SMSWebServiceService service = new org.me.sms.SMSWebServiceService();
org.me.sms.SMSWebService port = service.getSMSWebServicePort();
java.lang.String username = "";
java.lang.String password = "";
java.lang.String keyword = "Temp";
java.util.List<org.me.sms.Records> result = port.retrieveSMS(username, password, keyword);
out.println("Result = "+result);
I could not access the methods in my Records class.
I tried out.println("Result = "+result.getText); but it wont work
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In the above JSP, result is defined as a List. A List is not an array. Even if it was an array, your code wouldn't work the way you seem to expect. Consider the following:
String[] myArray = { "a", "b", "c" };
System.out.println("myArray = " + myArray);
If you know about arrays, you will know that this does not show you the contents of myArray. Try it and see what it does.
I recommend that you read up about arrays and collections.
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I need code for encrypt a any file using .net and decrypt it using java
please any send sample code
Thanks in advance
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Do you have a particular encryption algorithm in mind or is it just a general question? When you say .NET do you mean C#, VB, or do you not care which language? Do you want to roll your own encryption solution or use some sort of framework or toolkit (PGP or similar). Is the file stored on disk in encrypted format for asynchronous access or exchanged over a network synchronously?
As long as you use the same encryption algorithm at both ends (Java and .NET) there is no problem with doing this at all. There are plenty of tutorials on the interweb google thing that show you how to do this for just about every technology under the sun.
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thank Q for replay
i tried to implement a application using AES algorithm, but i did not successed. In .net i am using vb.net
please send me a any sample code to encrypt a file using .net and decrypt it using java
Thank Q
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Does such a thing exist in Java? For example, I can always do something like:
AJSDate startDate = new AJSDate("20090811");but I would rather have it as:
AJSDate startDate = "20090811";
"Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
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No, you cannot do this in Java. It was a deliberate choice by Gosling et al. as one of their original design aims for the language was simplicity and transparency: you should always know what code does simply by looking at it, with no "hidden" effects. ("Simplicity" and Java, oh how the world has changed.)
What you can do is set up a static factory method, something like:
AJSDate startDate = AJSDate.valueOf("200090811")
That's probably a better solution for dates if you're concerned about time zones because it allows you to overload the factory method to specify a time zone as well, which you can't easily do with operator overloading.
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i am making a project in java awt and backend as ms -access.
my project is online quiz
i want that the java should retrieve random questions ten out of 50 question from ms access database table without repetation of question in one login .
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You could give a sequence number(1-50) to each of the questions in you access db and then do something like this every time you select a question (Generate a question number)
Random rnd = new Random();
int questionnum = rnd.nextInt(50) + 1;
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I was tasked to write a program asks the user for the name of a file. The program should display the contents of the file with each line preceded witha line number followed by a colon. The line numbering should start at 1.
I got to the point of displaying the content in the file but I am not sure how to code for the line numbers and colons. Any suggestions?
Here is what I have so far:
import java.util.Scanner; // Needed for the Scanner class
import java.io.*; // Needed for the File class
/**
This program reads data from a file.
*/
public class LineNumbers
{
public static void main(String[] args) throws IOException
{
// Create a Scanner object for keyboard input.
Scanner keyboard = new Scanner(System.in);
// Get the filename.
System.out.print("Enter the filename: ");
String filename = keyboard.nextLine();
// Open the file.
File file = new File(filename);
Scanner inputFile = new Scanner(file);
// Read lines from the file until no more are left.
while (inputFile.hasNext())
{
// Read the next name.
String familyName = inputFile.nextLine();
// Display the last name read.
System.out.println(familyName);
}
// Close the file.
inputFile.close();
}
}
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You're a beginner therefore at some point recently you should have counted from 1 to 10 in a loop.
Fill in the blanks.
int lineNumber = 1;
while(....)
{
....
System.out.println(lineNumber + ": " + ....);
lineNumber++;
}
ps. Please put your code in <pre></pre> tags; as it makes it more readable. 
If at first you don't succeed, you're not Chuck Norris.
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Here is what you should do
<br />
int lines = 1;<br />
while (inputFile.hasNext())<br />
{<br />
String familyName = inputFile.nextLine();<br />
<br />
System.out.println( lines + " " + familyName + ";" );<br />
lines++;<br />
}<br />
Netmani
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Thank you for your help. Works like a charm!!!!
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Gentleman:
I just added a Java window to an ASP web page which shows an enlarged graphic. This works perfectly in Explorer, however it does something unusual in Firefox. Firefox opens a user request interface which asks the following:
What should Firefox do with this file:
Open With ... etc
or
Save
Neither option will open the new graphic in the Java window as it does in Explorer. Following is the code that I am using to open call the Window and get the graphic:
IN THE HEADER
<%--Large WIndow Scripts --%>
<script type="text/javascript">
function OpenLargeWindow1(image)
{
window.open("Ads/" + image, "", " width=760,height=300,top=200,left=200,scrollbars=0").focus();
}
</script>
IN THE BODY
<a href="javascript:OpenLargeWindow1('gears33.png')">
<asp:Image ID="Image18" runat="server" ImageUrl="~/Ads/plus_sign.png" /></a>
Does Firefox require a proprietary code or what option in the select process will put the graphic in the window if any? OR ???.
Any insight to this dilemma is appreciated.
Thank You, Pat
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This is not a Java question but a Javascript question and is more applicable to the Web Development forum.
I believe Firefox downloads some file types rather than showing them and the same can be said for Internet Explorer, pdf's and png's for example. I would suggest creating a page which takes a 'get' variable which would then display the image on the page. Eg. javascript:OpenLargeWindow1('showimage.aspx?img=gears33.png') to avoid browser inconsistencies.
If at first you don't succeed, you're not Chuck Norris.
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Fly,
Thank you for your reply. Being a Java novice, I do not understand the exact context of this code, but in fact, I have created a new page using your suggestion and with the graphics properly located, I am able to get the desired results in both browsers. It's a little long winded and I do not know if it is the best way to do it, but it works and I thank you for your input. Accordingly, I have marked your answer as correct and appreciate your help.
Re: Forum -- I apologize if I am "in the wrong place", but that is what comes from not knowing about a particular subject. I assumed that Java and Javascript are alike enough that a Java programmer would have the answer, since there is no category for Javascript. No offense was intended and I will use the other forum for future questions in this area. In fact, since the application is (.aspx), I also posted this question to the other (.Net) people, of which I am one, thinking this might be a common problem, but no one there replied to it. I am new to "Internet Applications" and I dislike this programming very much (all my experience comes from programming business desktop applications in C#), but in the words of the immortal John Wayne, "A Mans Got To Do What A Mans Got To Do!". Thank you again for your help...Pat
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