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QuestionOk I read the above but the Asp.net forum didn't help Pin
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GeneralRe: Ok I read the above but the Asp.net forum didn't help Pin
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AnswerRe: Ok I read the above but the Asp.net forum didn't help Pin
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AnswerRe: Ok I read the above but the Asp.net forum didn't help Pin
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GeneralRe: Ok I read the above but the Asp.net forum didn't help Pin
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GeneralRe: Ok I read the above but the Asp.net forum didn't help Pin
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GeneralRe: Ok I read the above but the Asp.net forum didn't help Pin
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AnswerRe: Ok I read the above but the Asp.net forum didn't help Pin
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Questiondocument.createElement() or .innerHTML in Javascript? Pin
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QuestionSoftware Documentation?? Pin
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led mike30-Jul-08 8:02
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Questioninserting the id of data in the second dropdown menu(this second drop down menu depends on the first drop down menu) in to my database 2.please can anyone teach me how to mantain the userid of some one who logs in so that i can use it later Pin
nahelna30-Jul-08 3:33
nahelna30-Jul-08 3:33 
for the first question:
pliz help me, i keep getting the error
[i]Notice: Undefined index: cat in c:\program files\easyphp1-8\www\myhelpdesk\postqueryagain.php on line 40[/i]
if i remove the line $cat=$_GET['cat']; the second drop down menu doesnt function well thanx guys

[code]



include('connect_db.php');
$quer2=mysql_query("SELECT DISTINCT typename,probtypeid FROM probtype order by typename");
$cat=$_GET['cat'];//This line is added to take care if your global variable is off
if(isset($cat) and strlen($cat) > 0)
{
$quer=mysql_query("SELECT DISTINCT catname FROM category where probtypeid=$cat order by catname");
}
else
{
$quer=mysql_query("SELECT DISTINCT catname FROM category order by catname");
}



echo "";
//Add your form processing page address to action in above line. Example action=dd-check.php
// Starting of first drop downlist
echo "select problem type";
while($noticia2 = mysql_fetch_array($quer2))
{
if($noticia2['probtypeid']==@$cat)
{
echo "$noticia2[typename]"."";
}
else
{
echo "$noticia2[typename]";
}
}
echo "";

//Starting of second drop downlist
echo "Select problem category";
while($noticia = mysql_fetch_array($quer))
{
echo "$noticia[catname]";
}
echo "";
//This will end the second drop down list


echo "";

?>

[/code]


i want to insert the id of the catname.thanx guys

nahelna
AnswerRe: inserting the id of data in the second dropdown menu(this second drop down menu depends on the first drop down menu) in to my database 2.please can anyone teach me how to mantain the userid of some one who logs in so that i can use it later Pin
Johnny ²30-Jul-08 4:27
Johnny ²30-Jul-08 4:27 
GeneralRe: inserting the id of data in the second dropdown menu(this second drop down menu depends on the first drop down menu) Pin
nahelna31-Jul-08 1:37
nahelna31-Jul-08 1:37 

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