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Renu A wrote: But still I am getting the run time message.
What do mean by a run time message?
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Run time error such as: If instead the below can't I get page cannot be displayed.
Server Error in '/SOL/SolOnline' Application.
--------------------------------------------------------------------------------
ORA-00933: SQL command not properly ended
Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.
Exception Details: Oracle.DataAccess.Client.OracleException: ORA-00933: SQL command not properly ended
Source Error:
An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below.
Stack Trace:
[OracleException: ORA-00933: SQL command not properly ended]
Oracle.DataAccess.Client.OracleException.HandleErrorHelper(Int32 errCode, OracleConnection conn, IntPtr opsErrCtx, OpoSqlValCtx* pOpoSqlValCtx, Object src, String procedure) +693
Oracle.DataAccess.Client.OracleCommand.ExecuteNonQuery() +2128
SlcCore.OracleWebConnection.ExecuteCommand(String sqlStatement)
SlcCore.ApplicationRunInformation.LogoutSession()
SlcCore.ApplicationRunInformation..ctor(HttpRequest request, HttpResponse response, String oracleConnectionInformation, String cookieIdentifier, Boolean blnLogout)
CSolOnline.CSOLFunctions.PageLogout(HttpRequest& request, HttpResponse& response) +51
CSolOnline.LogoutUserCtrl.Logout_Click(Object sender, EventArgs e) +56
System.Web.UI.WebControls.LinkButton.OnClick(EventArgs e) +108
System.Web.UI.WebControls.LinkButton.System.Web.UI.IPostBackEventHandler.RaisePostBackEvent(String eventArgument) +57
System.Web.UI.Page.RaisePostBackEvent(IPostBackEventHandler sourceControl, String eventArgument) +18
System.Web.UI.Page.RaisePostBackEvent(NameValueCollection postData) +138
System.Web.UI.Page.ProcessRequestMain() +1277
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Gosh!!!
This is no message but an excpetion. 
Look at this [^]
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yes i know...I have purposely added that error .............but can we handle that...I have also given one more update in my earlier mail as to what exactly is happening.
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I got a nice article which mentions how to handle undhandled error.
http://www.15seconds.com/issue/030102.htm
It even works when the error is on the webpage itself.
But now my problem is, In the code we have used a dll. (which is a seperate project type of classlibrary). Now in this when the sql fires and if it gives error in the catch block it directly says as
Throw Exception.
Now that's the problem. This error does not come on the webpage as it is not trapped. It directly throws the error in the dll itself.
Can I handle this error in my application without changing my code??
Thanks.
Rains
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Newbie question here: I’ve got a page with a text box with a requered field validator and a label that should say “OK” if there is text in the field (using Page.IsValid) or “Bad” if not. However, it doesn’t say “Bad” when there is no text. Below is the page code and the source code. Can anyone help me under stand why this is happening? Thanks!
PAGE CODE:
<%@ Page Language="VB" AutoEventWireup="false" CodeFile="pageIsValidTest.aspx.vb" Inherits="pageIsValidTest" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" >
<head runat="server">
<title>Untitled Page</title>
</head>
<body>
<form id="form1" runat="server">
<div>
Textbox:
<asp:TextBox ID="TextBox" runat="server"></asp:TextBox>
<asp:RequiredFieldValidator ID="RequiredFieldValidator1" runat="server" ControlToValidate="TextBox"
ErrorMessage="enter text"></asp:RequiredFieldValidator><br />
<asp:Button ID="Button1" runat="server" Text="Button" /><br />
Label:
<asp:Label ID="Label" runat="server"></asp:Label></div>
</form>
</body>
</html>
SOURCE CODE
Partial Class pageIsValidTest
Inherits System.Web.UI.Page
Protected Sub Button1_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles Button1.Click
If Page.IsValid Then
Label.Text = "OK"
Else
Label.Text = "Bad"
End If
End Sub
End Class
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Hi BigMish2,
You need to validate the page before you can tell if it's valid:
Page.Validate()
If Page.IsValid Then
Label.Text = "OK"
Else
Label.Text = "Bad"
End If
I hope this helps.
Ryan
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Thanks Ryan but unfortunately that did not work.
Update: interestingly I get the same behavior as with the code I posted before with the following source code (meaning that Label only displays “OK” if I put text in the text box even when I comment out the conditional!):
Partial Class pageIsValidTest
Inherits System.Web.UI.Page
Protected Sub Button1_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles Button1.Click
'If Page.IsValid Then
Label.Text = "OK"
'Else
'Label.Text = "Bad"
'End If
End Sub
End Class
What is going on?!
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I'm not sure why it wouldn't work after you'd added the Page.Validate()line, does it give an error?
You've commented out the condition the condition, but you haven't commented out Label.Text = "OK" so every time you click the button it will set the labels text to OK regardless of what you do on the page.
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No no error, it just dosn't display "Bad" if I leave the field blank.
I wasn't clear: it only says "OK" if there is text in the feild!
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Hi there,
What you are doing is a server validation using the Validators set on the page, and Page.IsValid property returns a value according to wether a certain Validation Group is valid or not OR all validation controls are valid or not on the page.
In other words checking its value immediatley will be with no value for you, you have to call Page.Validate(validationGroupName) first in order for this value to return the desired and good value of it.
You can call Page.Validate() to validate all validators on the page, or call Page.Validate(validationGroupName) if you have a group, you can set a group of validation on the controls using the ValidationGroup property if you wanted.
Hope that helps.
Sincerely Samer Abu Rabie
Imagination is more important than knowledge !
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Hey All,
I have create some sample code for send sms from the website, have look at the article posted in Code Project.
http://www.codeproject.com/KB/aspnet/SendSMS_ASPDOTNET20.aspx
Regards,
Smart Boy
Mumbai,
(INDIA)
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when i try to install a web setup project on windows vista with iis7
it gives me an error .
'Instalation intrupted' plz some one help me i am stuck with this problem.
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Installation interrupted message is too generic. Is there any specific error messages? Have you checked in the event viewer?
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Check if you got the IIS6 metadata compatibility components installed on you pc.
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I take a mistake like belleow message with runtime ;
"A control with ID 'lnk1' could not be found for the trigger in UpdatePanel 'UpdatePanel2'.."
lnk1 is my LinkButton's ID thats in the Ajax Accordion Menu content ..
and the part of code :
-----------
<Triggers>
<asp:AsyncPostBackTrigger ControlID="lnk1" EventName="Click" />
</Triggers>
</asp:UpdatePanel>
-----------
And Please Help me .. Thank u so much for each answers..!
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Can u post complete ajax update panel code.
Also check for the ID for Case sensitive.
Regards,
Smart Boy
Mumbai,
(INDIA)
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There isn't problem ID's about case sensitive..
and the code below :
<asp:UpdatePanel ID="UpdatePanel2" UpdateMode="Conditional" runat="server">
<ContentTemplate>
<asp:GridView ID="GridView1" runat="server" CellPadding="4" ForeColor="#333333" GridLines="None" HorizontalAlign="Center" AllowPaging="True" AllowSorting="True">
<FooterStyle BackColor="LightGray" Font-Bold="True" ForeColor="White" BorderStyle="Solid" BorderWidth="2px" Font-Size="Small" />
<RowStyle BackColor="#F7F6F3" ForeColor="#333333" Font-Size="Small" />
<PagerStyle BackColor="LightGray" ForeColor="MediumBlue" HorizontalAlign="Justify" BorderStyle="Solid" BorderWidth="2px" Font-Size="X-Small" />
<SelectedRowStyle BackColor="#E2DED6" Font-Bold="True" ForeColor="#333333" />
<HeaderStyle BackColor="LightGray" Font-Bold="True" ForeColor="MediumBlue" BorderColor="Black" BorderStyle="Solid" BorderWidth="2px" Font-Names="Verdana" Font-Size="X-Small" Font-Strikeout="False" Font-Underline="True" />
<EditRowStyle BackColor="#999999" />
<AlternatingRowStyle BackColor="White" ForeColor="#284775" />
<Columns>
<asp:ImageField DataImageUrlField="MARKA_ADI" DataImageUrlFormatString="images/{0}.jpg"
HeaderText="GÖRÜNÜM">
</asp:ImageField>
</Columns>
</asp:GridView>
</ContentTemplate>
<Triggers>
<asp:AsyncPostBackTrigger ControlID="lnk2" EventName="Click" />
</Triggers>
</asp:UpdatePanel>
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In first post u have said that ur button name was "lnk1" and now in ur this reply with the code ur button name is "lnk2"
Regards,
Smart Boy
Mumbai,
(INDIA)
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The name lnk1 or lnk2 is not important,
I have already a few LinkButton instance, in the Content of Accordion Menu..
Thats the important point, the update panel can not find whatever linkbutton, that i write in the trigger..
Thanks..
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is this link button is in menu?
Regards,
Smart Boy
Mumbai,
(INDIA)
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yep !
like this :
<Content>
<table style="border-color:Black" border="0" cellpadding="0" cellspacing="0" width="129" >
<tr>
<td class="accordionPaneContent">
<p style="text-align:center">
<asp:LinkButton Font-Underline="false" CssClass="accordionPaneLink" ID="lnk1" onclick="lnk1_Click" Text="1" runat="server">HewlettPackard</asp:LinkButton>
</p>
</td>
</tr>
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In event name of ur update panel u have written "Click" as event but in ur linkbutton control onclick event value is "lnk1_Click".
If u r writing ur code in ASP.Net then Handler in the event like
Protected Sub lnk1_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles lnk1.Click
And remove the event name in the Code onclick="lnk1_Click" from ur html and try then.
Best of Luck.
Regards,
Smart Boy
Mumbai,
(INDIA)
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Hi i am looking into implementing the ajax toolkit password strength control and was wondering if it is possible to use this control to prevent the user from submitting the form. I have got the control working so that it informs the user of the strength of their password however i am able to submit the form even if the password requirements are not met.
“You will never be a leader unless you first learn to follow and be led.”
–Tiorio
"Coming together is a beginning, staying together is progress, and working together is success." Henry Ford
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