|
ptvce wrote: can i do that
Yes
Paul Marfleet
"No, his mind is not for rent
To any God or government"
Tom Sawyer - Rush
|
|
|
|
|
|
ptvce wrote: how ?
By writing code
ptvce wrote: do u know?
Probably. But you should try and solve the problem yourself first before expecting someone to give you a solution. Do some research, write some code and post again if you are still having problems.
Paul Marfleet
"No, his mind is not for rent
To any God or government"
Tom Sawyer - Rush
|
|
|
|
|
i think u can use TreeNodeExpanded event.
sepel
|
|
|
|
|
Hai Everybody,
I am creating a windows and web application.
When the user clicks on the menu in the windows application the web has to be opened ut it should not ask for the login and the user who have logged in has to be passed to the Session in web as well as wise versa.
Can any one help me do to it.
Thanks in Advance.
Best Regards,
M. J. Jaya Chitra
|
|
|
|
|
M. J. Jaya Chitra wrote:
When the user clicks on the menu in the windows application the web has to be opened ut it should not ask for the login
Does your web application use Forms Authentication? If so, you need to perform the authentication programmatically. Look at the FormsAuthentication class, particularly the Authenticate[^] method.
Paul Marfleet
"No, his mind is not for rent
To any God or government"
Tom Sawyer - Rush
|
|
|
|
|
We are developing an Asp.NET application. Everything was working fine and well. We had SQL 2000 in a Windows 2000 machine and development machine was having Windows XP. But, then we had to format the Windows 2000 machine. Windows 2003 was now installed in the machine. We then installed SQL 2000. It asked for a minimum of SP3 for SQL 2000. We installed SP3 as well as SP4. After this we were able to access the SQL 2000 database from Enterprise Manager, Query Analyzer as well as a Desktop application. But when we wanted to populate a Grid View in an ASP.NET page from the database we got the following error:
"An error has occurred while establishing a connection to the server. When connecting to SQL Server 2005, this failure may be caused by the fact that under the default settings SQL Server does not allow remote connections. (provider: Named Pipes Provider, error: 40 - Could not open a connection to SQL Server)"
We googled and we tried different things but we were unable to arrive at a solution. Our work is getting hampered because of this. If anybody can please provide a solution for the same, we would be highly grateful and thankful since we are in the midst of a project.
|
|
|
|
|
Check the connection String of Grid View !!!
|
|
|
|
|
thank you for quick response.
I have checked it several times.
It is ok.
thanks
|
|
|
|
|
i used the update panel , in this way too, i achieved the reduction of access time.But how can i define the funciton using the ajax to do the same.
If you have an apple & I have an apple and we exchange our apples, then each of us will still have only one apple but if you have an idea & I have an idea and we exchange our ideas, then each of us will have two ideas!
|
|
|
|
|
Pankaj Garg wrote: But how can i define the funciton using the ajax to do the same.
can you explain in details that what you are trying to do ??
|
|
|
|
|
can i write the fucntion in the source file , in order to do the editing in the gridview .
If you have an apple & I have an apple and we exchange our apples, then each of us will still have only one apple but if you have an idea & I have an idea and we exchange our ideas, then each of us will have two ideas!
|
|
|
|
|
Function will reamin in the same source file, just put the Gridview inside the update panel, if it take much time to retrive or update date use UpdateProgressbar !!!
|
|
|
|
|
do u have any link , that pertains to very basic free ebook for ajax (covering all topics.)
If you have an apple & I have an apple and we exchange our apples, then each of us will still have only one apple but if you have an idea & I have an idea and we exchange our ideas, then each of us will have two ideas!
|
|
|
|
|
|
Hi,
I have an ASP.Net application and I have enabled the above two properties on my page. Everything works fine on every OS-Browser combination, but on Windows 2000, with IE5,
1. As soon as the page opens up, I get a JavaScript error "Object doesn't support this property or method". I identified the problem is because of enabling MaintainScrollPositionOnPostBack, which tries to change the submit property of the page: I set the property to false and all works fine even on IE5
theForm.submit = WebForm_SaveScrollPositionSubmit;
2. The page implements ICallbackEventHandler, and has script callbacks at various intervals on the page. When the page submits, I get the error "Invalid Postback or callback argument...use ClientScriptManager.RegisterForEventValidation in order to register the postback or callback data for validation"
As I said, this problem only occurs on IE5, but I searched around and there are not a lot of people complaining about this.
Has anyone else faced this problem with IE5 before, or can I avoid this problem somehow?
Thanks,
Praveen
There has to be more to life than just this
|
|
|
|
|
I have an AJAX page inside this I have tree control and when I use the RegisterArrayDeclaration(System.Web.UI.Page, System.String, System.String) to register an array it gives me the followign error:
Method not found: 'Void System.Web.UI.ScriptManager.RegisterArrayDeclaration(System.Web.UI.Page, System.String, System.String)'
Can any one tell me how to solve this?
Best Regards,
M. J. Jaya Chitra
|
|
|
|
|
Hi all,
I just want to add several controls at runtime like dropdown list, text box abd button. And, when we click the button again one row will be added with the set of controls likewise.can anyone please help me?
Thanks in Advance.
Thanks & Regards,
Radha
|
|
|
|
|
To add controls dynamically, create the control objects in code and then add them to the Controls collection for the current page.
Paul Marfleet
"No, his mind is not for rent
To any God or government"
Tom Sawyer - Rush
|
|
|
|
|
Step1:
Add one panel to your page.
Step 2:
Create object of your Control
Button B=new Button()
Step 3:
Add properties that you need ....
like
B.Name="Test Button"
B.ID="Button1"
B.Text="Click Me"
Step 4:
Add Event Handler with the Control
B.Click+= new System.EventHandler(Button_click)
Tricks : After Write B.Click += Press TAB again TAB.... next part and Function body will create automatically
Step 5:
Add the control to your page
panel1.controls.add(B)
Step 6:
write function for Button_click
procted void Button_Click(Object Sender, EvnetsArgs e )
{
}
Steps 7: Run....
|
|
|
|
|
Thank You, Abhijit.
I can create controls now. The thing is i have to create ten rows of controls(dropdownlist,textbox) when the page loads and if i want to add more rows i can add by clicking a button. And, i need to load Dropdownlist values from database. Please help me.
Thanks & Regards,
Radha
|
|
|
|
|
Radha27 wrote: The thing is i have to create ten rows of controls(dropdownlist,textbox)
Is each row will contain Dropdown list and text box ???
if yes, then create a function the will generate one DropdownList and Textbox , Call that 10 times at form load and you can call the same on button click.
If it is not clear, then just give me the breif idea that what you are trying to do !!!
I will surely help you, if i Can !!!!
|
|
|
|
|
Thank you Abhijit.
Let me explain my scenario.
Basically this is for one application's Data Entry form.Each row will contain 2 Dropdown lists and 8 textboxes.10 rows shuold be loaded by default i mean at form load and a Addmore button will be there. If i want to add more data, additional rows will be added by clicking Addmore button.
(Dropdown list values shold be loaded from database.)
Can u help me?
(And i tried like what u have explained in ur previous post. But it doesn't work. Only one row is being loaded.)
Thanks & Regards,
Radha
|
|
|
|
|
> Create Runtime Table to maintain the allignment
>> Add Dropdownlist and Textbox inside each
[ That will create also in runtime ]
MAke this thing inside a function !!!
you have to use Table , Dropdownlist , and Textbox Classes Object . And it should be Array of Object !!!!
>>> Add Event Handler when you required !!!!
>>>> For Database Data, When you create the Dropdown list , use D.Items.Add() on that function itself.
>>>>> And on Button Click Call the same Function .....
--------------------------
For your reference!!
Dynamic Array of Button[^]
--------------------------
This will just add one row with that table..........
This is the simpliest IDea ....
One more idea ..... that you can create one Custom Web user control ....(ascx) file......
>>>>>>>
Regarding The Tricks ::: It was not about adding Column or anything else...
This is the .NET general Trick !!!!
e.g
when your write a if statement ....if have to write
if(condition)<br />
{<br />
{<br />
else<br />
{ <br />
}
Now just try this..
write if and press TAB
Check what the difference,similarly try with switch, for, while statement . and where i am talking there it will do the same thing...
----
Check my latest article ....
|
|
|
|
|
Abhijit, Please check the code shown below and help me;
for (int i = 0; i < 10; i++)
{
Text1[i] = new TextBox();
//b[i].ID = i; //Can use ID
Text1[i].ID = "Text1" + i.ToString();
Text1[i].TextMode = TextBoxMode.MultiLine;
c1.Controls.Add(Text1[i]);
}
Here, i tried to add the text box to Table cell c1.
But, i dont get the result.
Did i miss anything here?
Thanks & Regards,
Radha
|
|
|
|
General 
News 
Suggestion 
Question 
Bug 
Answer 
Joke 
Praise 
Rant 
Admin 
Submit an article or tip
