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its not working, showing errors
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what is the error?
Sathiya
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Data Source=(Server Name/IP/PC Name);Initial Catalog=(DB Name);Integrated Security=True
Sathiya
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am getting the error like "only elements are allowed"
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Use like this
Server=SERVER;Database=ABC;Uid=sa; PWD=12; Connect Timeout=360; pooling=true; Max Pool Size=200
Sathya
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stil i get the error like "login failed"
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Now Start->SQLserver Mgmt Studio-> Login using Windows Authentication. Check whether you can able to connect.
Sathiya
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Understand the question first dear...
If it's "Windows Authentication". There'll be no Uid/pwd. Setting -"Integrated Secruity" to "True/SSPI" will solve the problem.
Sathiya
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Someone shoud be invited to your place so that you can get it done ... otherwise seems connecting to DB is too hard for you .... LOL !! You should have known whats Sql Server authentication and Windows Authentication ..... if you dont read or gather any knowledge ... 1000 posts will be null and void !!!!
Try to read something at least ....
Thanks,
Arindam D Tewary
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Don't degrade others. If they are learning phase.
Sathiya
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Thank u very much for ur words
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Problem is solved or not.
Sathiya
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i know the diff between both, I doesn't need any of ur advice.
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Rathi don't get tension try surly u will solve the problem
Sathya
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SathyaSiva wrote: Rathi don't get tension try surly u will solve the problem
This is not a Chat Forum.
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u also use this like chat
Sathya
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Please Dont spam this site.
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Please dont misuse a good and healthy forum for your sick mentality.
Its annoying that you want to chat here.
Thanks,
Arindam D Tewary
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It does't make any differece if you dont use your knowledge while working. and specilly if question reflects other thing !! Anyway ... happy coding and posting ..... you can again ignore this advice also ..
Thanks,
Arindam D Tewary
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i am trying to access another machine then open a terminal window and ask user name and password.(may be this probleam to install kasperkey anti virus on another machine) when enter the user name and password to access another machine. But i want to that write user name and password in my application when execute run my application to enter autometically username and password in terminal window to access another machine. plz help me.
modified on Saturday, June 28, 2008 6:59 AM
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Rinki Mukheraji wrote: am trying to access another machine then open a terminal window and ask user name and password
With Asp.net ?
Rinki Mukheraji wrote: when execute my exe enter autometically username and password in terminal window to access another machine.
Again with Asp.net ??
<blockquote class="FQ"><div class="FQA">Rinki Mukheraji wrote:</div> plz help me.</blockquote>
I think this is not the proper forum to ask .
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Internet Explorer is not supporting this .
What shuld I do to get this code to be supported in IE ?
when I tried to add the following properties to a grid view.
GridLines="Horizontal" RowStyle-BorderColor="ActiveBorder" RowStyle-BorderStyle="dotted" RowStyle- BorderWidth="1px"
i cannot set border width in IE but it works in firefox
Ashok
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if you have scenario when you have two diferent code which is working for 2 different browser then you you have identify which browser it is. You can do this by Javascript and then you have to set boder width by javascript code.
detection of browser using javascript
function whichBrs() {
var agt=navigator.userAgent.toLowerCase();
if (agt.indexOf("opera") != -1) return 'Opera';
if (agt.indexOf("staroffice") != -1) return 'Star Office';
if (agt.indexOf("webtv") != -1) return 'WebTV';
if (agt.indexOf("beonex") != -1) return 'Beonex';
if (agt.indexOf("chimera") != -1) return 'Chimera';
if (agt.indexOf("netpositive") != -1) return 'NetPositive';
if (agt.indexOf("phoenix") != -1) return 'Phoenix';
if (agt.indexOf("firefox") != -1) return 'Firefox';
if (agt.indexOf("safari") != -1) return 'Safari';
if (agt.indexOf("skipstone") != -1) return 'SkipStone';
if (agt.indexOf("msie") != -1) return 'Internet Explorer';
if (agt.indexOf("netscape") != -1) return 'Netscape';
if (agt.indexOf("mozilla/5.0") != -1) return 'Mozilla';
if (agt.indexOf('\/') != -1) {
if (agt.substr(0,agt.indexOf('\/')) != 'mozilla') {
return navigator.userAgent.substr(0,agt.indexOf('\/'));}
else return 'Netscape';} else if (agt.indexOf(' ') != -1)
return navigator.userAgent.substr(0,agt.indexOf(' '));
else return navigator.userAgent;
}
Hope it helps you :)
Thanks,
Arindam D Tewary
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