ASP.NET

18-Jul-06 1:27

Hi ,
i have posted this question before & i reposted it , now i need the answer please ,i really need it i swear cuz i'm building an asp.net application & i have to finish it .

well,i will explain to make it more clear :

i want that when i type a letter or a number or whatever in ma textbox , this letter appear in a label , i mean once i type the letter , i want that letter appear in ma label

i hope uyou understand i think it is clear

i initialized the autopostback propriety of ma textbox into true but it works just when the focus leave the text box not for each letter

try to be good if you can't be the best

Paddy Boyd18-Jul-06 1:37

Paddy Boyd

18-Jul-06 1:37

You need to do this in javascript probably. Use the onKeyUp event.

Mohammed Amine18-Jul-06 1:48

18-Jul-06 1:48

thnx man , but can you give me a clear example because i heard before that i have to use javascript but the problem is that nobody told me how ?

thank you again

try to be good if you can't be the best

Not Active18-Jul-06 2:32

Not Active

18-Jul-06 2:32

Mohammed Amine wrote:
nobody told me how

WHy don't you try figuring it out on your own rather than expecting people to give you the answers. There are many resources available to learn Javascript.

Not Active18-Jul-06 2:30

Not Active

18-Jul-06 2:30

Mohammed Amine wrote:
i have posted this question before & i reposted it , now i need the answer please

This isn't a help desk and your not asking your professor, although he is probably monitoring.

Pradipta Basu18-Jul-06 6:19

18-Jul-06 6:19

From the posts it seems that you need the javascript solution.

Let the textbox id be txt1
The asp:label that you are using transforms into a <span>
let its id be lbl1

then write something like
document.getElementById("lbl1").innerHTML = document.getElementById("txt1").value;

I think this will do your job.

Thanks,

Pradipta Basu

Mohammed Amine18-Jul-06 11:00

18-Jul-06 11:00

ok, thank you i want to try it but can you tell me where should i write this line ? & can you try to explain a little bit please like that i will be sure of ma self

thank you very much

try to be good if you can't be the best

Pradipta Basu19-Jul-06 2:25

19-Jul-06 2:25

You can look at the code below. Hope this will solve your problem.

<br />
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" > <br />
<br />
<html><br />
  <head><br />
    <title>Test</title><br />
    <meta name="GENERATOR" Content="Microsoft Visual Studio .NET 7.1"><br />
    <meta name="CODE_LANGUAGE" Content="C#"><br />
    <meta name=vs_defaultClientScript content="JavaScript"><br />
    <meta name=vs_targetSchema content="http://schemas.microsoft.com/intellisense/ie5"><br />
		<script type="text/javascript"><br />
			<!--<br />
			function setValue()<br />
			{<br />
				document.getElementById("lblName").innerHTML = document.getElementById("txtName").value;<br />
			}<br />
			//--><br />
		</script><br />
  </head><br />
  <body><br />
	<br />
    <form id="Form1" method="post" runat="server"><br />
		<asp:TextBox ID="txtName" Runat="server" onkeyup="Javascript:setValue();"></asp:TextBox><br /><br />
		<asp:Label ID="lblName" Runat="server" /><br />
<br />
     </form><br />
	<br />
  </body><br />
</html><br />

Save this in a aspx file and then run. Note that it is not using any code-behind.

Thanks

Pradipta Basu

Mohammed Amine19-Jul-06 4:58

19-Jul-06 4:58

Hi , thank you very much man i appreciate your help , but i will annoy you a little bit Poke tongue | ;-P

, please can you explain that line to me ?

what is the role of innerHTML ?

the necessary is understanding that line ok ?? pleaaaaase & thank you very very much

try to be good if you can't be the best

Pradipta Basu20-Jul-06 4:58

20-Jul-06 4:58

Please have a look at the following link. This explains very wll the concept of innerHTML.

http://developer.mozilla.org/en/docs/DOM:element.innerHTML

Thanks,

Pradipta Basu

Pradipta Basu20-Jul-06 5:10

20-Jul-06 5:10

For IE you can also use innerText. But it won't work in Mozilla. So using innerHTML is better.

Thanks,

Pradipta Basu

server

locaas18-Jul-06 1:08

locaas

18-Jul-06 1:08

hello
i am using vs2005 and microsoft sql server 2005. In vs->server explorel it does not show me any databases. What is the default path of the data for sql server 2005?

Re: server

StonePit18-Jul-06 4:04

StonePit

18-Jul-06 4:04

In Server Explorer try to add new Connection

Stonepit

Custom Web user Control

MalikRizwan18-Jul-06 0:53

MalikRizwan

18-Jul-06 0:53

I have a custom control with two properties and one overrided method render .. whenever i assign DataTable to one property i preserves it but when the render function is called its value is null
here is my code

<br />
using System;<br />
using System.Data;<br />
using System.Configuration;<br />
using System.Web;<br />
using System.Web.Security;<br />
using System.Web.UI;<br />
using System.Web.UI.WebControls;<br />
using System.Web.UI.WebControls.WebParts;<br />
using System.Web.UI.HtmlControls;<br />
namespace Nav<br />
{<br />
    /// <summary><br />
    /// Summary description for ucMenu<br />
    /// </summary><br />
    [ToolboxData("<{0}:ucMenu runat=server></{0}:ucMenu>")]<br />
    public class ucMenu : WebControl<br />
    {<br />
        DataTable _dtMenu; <br />
        string _id;<br />
        public ucMenu()<br />
        {<br />
            // <br />
            // TODO: Add constructor logic here<br />
            // <br />
            //_dsMenu = new DataSet();<br />
<br />
        }<br />
        public DataTable XMLDataSource<br />
        {<br />
            get<br />
            {<br />
                return (_dtMenu);<br />
            }<br />
            set<br />
            {<br />
                _dtMenu = value.Copy();<br />
            }<br />
            <br />
        }<br />
        public string  NavID<br />
        {<br />
            get<br />
            {<br />
                return (_id);<br />
            }<br />
            set<br />
            {<br />
                _id = value;<br />
            }<br />
<br />
        }<br />
        protected override void Render(HtmlTextWriter writer)<br />
        {<br />
            writer.Write("<ul id=" + _id + ">");<br />
            if (_dtMenu != null)<br />
            {<br />
                for (int i = 0; i < _dtMenu.Rows.Count; i++)<br />
                    {<br />
                        writer.Write("<li><a href=" + _dtMenu.Rows[i]["href"].ToString() + " >" + _dtMenu.Rows[i]["text"].ToString() + "</a></li>");<br />
                    }<br />
                <br />
            }<br />
            writer.Write("</ul>");<br />
            writer.Flush();<br />
            base.Render(writer);<br />
        <br />
        }<br />
    }<br />
}

IN HTML i m embedding it as
<MyBar:ucMenu ID="UcMenu1" runat="server" />
and in code behind
protected ucMenu MyBar = new ucMenu();
on top of class
can you please tell me why my datatable refernce to null in render even i have ref it to datatable from property

R A M

minhpc_bk18-Jul-06 16:13

minhpc_bk

18-Jul-06 16:13

How do you set the XMLDataSource property? in code-behind or in the web page? Are you sure that the value is not null by the time you set the property of the control?

MalikRizwan18-Jul-06 17:50

MalikRizwan

18-Jul-06 17:50

I m setting through code behind and value is not null when i set it to XMLDataSource property. It assigns the value correctly because i have checked through debugging. I think there is some problem with declaring the control .. isnt it?

R A M

minhpc_bk18-Jul-06 20:19

minhpc_bk

18-Jul-06 20:19

Rizvi Malik wrote:
MyBar:ucMenu ID="UcMenu1" runat="server" />
and in code behind
protected ucMenu MyBar = new ucMenu();

Ah yes, now I look at your sample code again and see the cause: You declare the control in the web page with the id UcMenu1, meanwhile you declare a new instance MyBar in code-behind, and I guess that you set the property of the second instance other than the first one. In this case, you can declare the control in code-behind like this: (in the version 2.0, you no need to this):

protected ucMenu UcMenu1;