This bit confused me and I cant seem to do it in the order its supposed to be can anyone help out?

Question

1.00/5 (1 vote)

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should loop 51 times, writting intergers 0-50 in order.

C#

int i = /*initialiser*/;
while (i/*condition*/50)
{
  i /*iterator*/;

console.writeline(i);
}

What I have tried:

C#

{
            for (int i=0;i<=50;i++)
                for (int j= 1;j<=51;j++)
                {
                    
                    Console.WriteLine(i);
                }

Posted 19-Nov-18 11:56am

Member 13736730

Updated 19-Nov-18 12:46pm

CHill60

v2

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CHill60 · Answer 1 · 2018-11-19T12:47:00

Solution 1

Try

C#

for (int i=0; i< 50; i++)
{
   Console.WriteLine(i);
}

OR

C#

int i = 0;
while i < 51
{
   console.WriteLine(i++);
}

NOTE - in the 2nd example I have incremented i in the first example i is incremented by the use of for

Posted 19-Nov-18 12:47pm

CHill60

Comments

Member 13736730 19-Nov-18 19:15pm

thanks for the reply, going witht the 2nd example it does need an iterator after the while loop to run 51 times doesnt it?

CHill60 20-Nov-18 12:28pm

Sorry - notifications don't seem to be working and I didn't see this. I'm not sure what you mean by putting "an iterator after the while loop"
i is the iterator in the 2nd example and is incremented by 1 each time (after) it is written to the console by i++
The loop starts at 0 and produces output until i = 50 ... 51 times.