How can I see if an element in a matrix is dividable by the num of rows and columns?

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Hello i have a small problem. I create a matrix and i want to check if any element is dividable by the num of the row he is in and the num of the column he is in.
For example:
1 2 3
4 5 6
7 8 9
6 is in the 3rd row and 2nd column. 2|6 and 3|6. So he fits with the output. Here is what i have so far.

#include <stdio.h>
#include <stdlib.h>

int main(){
    int nrows,ncols;
    scanf("%d %d", &nrows, &ncols);
    int matA[nrows][ncols];
    int i,j;
    for(i = 0; i < nrows; i++){
        for(j = 0; j < ncols; j++){
        scanf("%d",&matA[i][j]);
        }
    }


for(i = 0; i < nrows; i++){
        for(j = 0; j < ncols; j++){
        printf(" %d \t",matA[i][j]);
    }
    printf("\n");
}
printf("\n");
for(i = 1; i < nrows; i++){
    for(j = 1; j < ncols; j++){
        int nums = matA[i][j];
        if(nums / i && nums / j){
            printf(" %d \t", nums);
        } else {
            printf("Nema pogoden broj!");
        }
    }
}

    return 0;
}

What I have tried:

I've tried dividing by the number but i can't get it to return the count of the current number

Posted 28-May-18 17:04pm

Member 13848568

Updated 28-May-18 21:38pm

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Comments

Mohibur Rashid 28-May-18 23:28pm

6 is in the second row and third column.

GKP1992 28-May-18 23:45pm

What do you mean by the count of the current number? Do you want to know how many hits there are in the matrix or just the number which follows the condition?

Member 13848568 29-May-18 1:23am

I want to know if the number is dividable with the num of it's row and the num of it's column

2 solutions

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User 7429338 · Answer 1 · 2018-05-28T18:13:00

Solution 1

if(nums / i && nums / j)

This does not check divisability; it will always return a value, but without the fraction as you are using integers.

You could use the modulus operator (remainder after division) instead:

if(nums % i == 0 && nums % j == 0)

Posted 28-May-18 18:13pm

User 7429338

Comments

[no name] 29-May-18 2:23am

I saw you marked my answer as solution but then undid it. Please leave a comment if this didn't answer your question :)

CPallini · Answer 2 · 2018-05-28T21:39:00

I would say 6 is in the 2^nd row and 3^rd column.
Try

C

#include <stdio.h>
#include <stdlib.h>

int main()
{
  int nrows,ncols;
  scanf("%d %d", &nrows, &ncols);
  int matA[nrows][ncols];
  int i,j;
  for(i = 0; i < nrows; i++)
    for(j = 0; j < ncols; j++)
      scanf("%d",&matA[i][j]);


  for(i = 0; i < nrows; i++)
  {
    for(j = 0; j < ncols; j++)
      printf(" %d \t",matA[i][j]);
    printf("\n");
  }

  printf("\n");
  for(i = 0; i < nrows; i++)
    for(j = 0; j < ncols; j++)
    {
      int nums = matA[i][j];
      if(nums % (i+1) || nums % (j+1))
        printf("Nema pogoden broj!\n");
      else
        printf(" %d\n", nums);
    }
   return 0;
}