C# how to remove any element from the elements I wrote.

Question

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I have DynamicArray class, i want write a function in class which will remove any element from the elements I wrote. For example`
DynamicArray d = new DynamicArray(4,5,6,1,2)
when i will call d.remove(2) function, it will remove number 6 and will print` 4,5,1,2

What I have tried:

I don't know how write that function
public int remove()
{

}

Posted 18-Jan-18 20:09pm

Suren97

Updated 18-Jan-18 20:56pm

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3 solutions

Solution 2

I refer you back to the last time you asked this question: C# how to remove random element[^] where you were reminded that the solution to teh question before that: C# - how can I count the number of elements in an array?[^] contains the algorithm.

We are not here to do your homework. It is there so that you think about what you have been told, and try to understand it. It is also there so that your tutor can identify areas where you are weak, and focus more attention on remedial action.
Try it yourself, you may find it is not as difficult as you think.

Because if you don't, you will never learn how to "think correctly" and be able to do this for yourself. And that means you will fail your course, as when you get to the exam you will have no one to write it for you ... So sit down, start reading, start thinking - and give it a try instead of expecting others to do it for you: that isn;t how development works.

Posted 18-Jan-18 20:16pm

OriginalGriff

Comments

[no name] 19-Jan-18 2:59am

5 out 5 for this answer.People should understand before asking questions if those are answered already by community members.I urge the community to vote for the solution given yesterday for a much needed question as i have resolved this question by using a sql Fiddle.

https://www.codeproject.com/Answers/1225902/How-do-I-get-the-below-output-in-sql-Please-help-m?cmt=970075#cmt970075

Solution 1

Why don't you use List<int>, see example here: [Dotnetperls]

Posted 18-Jan-18 20:15pm

RickZeeland

Comments

Suren97 19-Jan-18 2:35am

Need me write that function in class then call it in Main method

Suren97 19-Jan-18 2:37am

here is show how write it in Main method

lukeer 19-Jan-18 4:11am

That's because the List<whatever> class is already brought to you by the .NET framework.

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Karthik_Mahalingam · Accepted Answer · 2018-01-18T20:56:00

Solution 3

try like this

public class DynamicArray {
    List<int> lstItems = new List<int>();
    public DynamicArray(params int[] items)
    {
        lstItems.AddRange(items);
    }
    public int[] Remove(int a) {
        lstItems.Remove(a);
        return lstItems.ToArray();
    }
}

DynamicArray d = new DynamicArray(4, 5, 6, 1, 2);
int[] items =  d.Remove(2); // 4,5,6,1
int[] items1 =  d.Remove(1); // 4,5,6
int[] items2 = d.Remove(4); // 5,6

Posted 18-Jan-18 20:56pm

Karthik_Mahalingam

Comments

Suren97 19-Jan-18 3:16am

it's output Sysem.Int32[]

Karthik_Mahalingam 19-Jan-18 3:40am

yes
Sysem.Int32 or int , both are same.

lukeer 19-Jan-18 4:16am

By "it's output", you mean the result of d.ToString() or items.ToString(), or items1.ToString(), am I right?
If yes, then you need to write a function for that which iterates over all elements of the array and prints them. That's a different topic from removin an element from a n array.

Suren97 19-Jan-18 3:43am

but Need me it output all numbers without removed number 4,5,1,2

Karthik_Mahalingam 19-Jan-18 3:45am

i think you are talking about index ?

Suren97 19-Jan-18 4:31am

yes, i must write index for example 2 and it will remove number 6

Suren97 19-Jan-18 4:32am

(4,5,6,1,2)
d.Remove(2)
it will remove number 6

Karthik_Mahalingam 19-Jan-18 4:40am

then use removeAt

  
 public int[] Remove(int a) {
        if(lstItems.Count >a )
        lstItems.RemoveAt(a);
        return lstItems.ToArray();
    }

Suren97 20-Jan-18 3:14am

then i will print Items?
DynamicArray d = new DynamicArray(4, 5, 6, 1, 2);
int[] items = d.Remove(2);
Console.WriteLine(items);
right?

Karthik_Mahalingam 20-Jan-18 3:15am

Use
Console.writeline( string.join(",", items);

Suren97 20-Jan-18 3:39am

ok, Thank you very much :)

Karthik_Mahalingam 20-Jan-18 3:54am

Welcome