This problem is related to C language. Plzz give me proper explanation.

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C

#include<conio.h>
#include<stdio.h>
void main()
{
 int a;
 float b;
 a=1/3+1/3+1/3;
 printf("%d",a);
 getch();
 return;
}

here the output is :0
instead of 1 why??????????????

What I have tried:

i have worked out this code in turbo c++
but the output is always 0 instead of 1 why???????

Posted 3-Jan-18 0:39am

Amit Razdan

Updated 3-Jan-18 0:57am

CPallini

v2

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CPallini · Accepted Answer · 2018-01-03T00:49:00

Solution 1

Because 1/3 is computed using the integer division. try

C

#include <stdio.h>
int main()
{
  int a;
  float b;
  b = 1.0f / 3 + 1.0f / 3 + 1.0f / 3;
  a = (int) b;
  printf("%d, %f\n",a, b);
  getchar();
  return 0;
}

And, please, stop using turbo C (it was good about 30 years ago). Use a modern compiler.

Posted 3-Jan-18 0:49am

CPallini

Updated 3-Jan-18 0:53am

v4

Comments

Peter_in_2780 3-Jan-18 6:57am

You might still get 0! The expression for b will evaluate to something like 1.0 - (one lsb)

Amit Razdan 3-Jan-18 10:13am

thank u very much sir.....

CPallini 3-Jan-18 18:29pm

You are welcome.