What is the value of 'n' here in this program to find pair with given sum in an array

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C++

#include <stdio.h>
#include <stdlib.h>

//program to find pair with given sum in the array.
void findPair(int arr[], int n, int sum)
{
    int i,j;
    for(i=0;i<n-1;i++)
    {
        for(j=i+1;j<n;j++)
        {
            if(arr[i] + arr[j] == sum)
            {
                printf("Pair found at index %d and %d", i,j);
                return;
            }
        }
    }
    printf("Pair not found");
}
int main()
{
    int arr[] = { 8,7,2,5,3,1};
    int sum = 10;

    int n = sizeof(arr)/sizeof(arr[0]);
    findPair(arr, n, sum);
    return 0;
}

What I have tried:

C++

#include <stdio.h>
#include <stdlib.h>

//program to find pair with given sum in the array.
void findPair(int arr[], int n, int sum)
{
    int i,j;
    for(i=0;i<n-1;i++)
    {
        for(j=i+1;j<n;j++)
        {
            if(arr[i] + arr[j] == sum)
            {
                printf("Pair found at index %d and %d", i,j);
                return;
            }
        }
    }
    printf("Pair not found");
}
int main()
{
    int arr[] = { 8,7,2,5,3,1};
    int sum = 10;

    int n = sizeof(arr)/sizeof(arr[0]);
    findPair(arr, n, sum);
    return 0;
}

Posted 24-Nov-17 19:12pm

Member 13540309

Updated 24-Nov-17 20:41pm

Kenneth Haugland

v2

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Comments

Kenneth Haugland 25-Nov-17 2:06am

Why do you send n to your function? Your calculation of it also looks strange to me.

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OriginalGriff · Answer 1 · 2017-11-24T20:41:00

Solution 1

It's the number of elements in your array:

C++

int arr[] = { 8,7,2,5,3,1};
... 
int n = sizeof(arr)/sizeof(arr[0]);

sizeof(arr) is the total number of bytes in the array, sizeof(arr[0]) is the size in bytes of the first element of the array, so n is bytes in array / bytes in each element == elements in array.

Posted 24-Nov-17 20:41pm

OriginalGriff

Comments

CPallini 25-Nov-17 6:42am

5.