C# Open and edit a form.............

Hi,

Handle the Load event of form2 in your main form.
Do whatever you want to do with Main form in this method which assigned with handler.

Hope it will help you.

Regards
AR

form2 newform2 = new form2();
newform2.show();

//here you are changing the background color of a picture box
//stored in THIS form: NOT form2!!
picturebox1.backcolor = color.green;

Did you attend somethign like this?

form2 newform2 = new form2();
newform2.Show();
newform2.picturebox1.BackColor = Color.Green;

I'd say you have to read about instances and objects again. But for a quick help: Make picturebox1 accessible from outside - (a property on Form2 exposing the PictureBox would be best, but just setting the Modifyer property of your PictureBox to public should do it for you)
After that - try it with Olivier Levrey's Code

form2 newform2 = new form2();
newform2.Show();
newform2.picturebox1.BackColor = Color.Green;

Anyway in a clean solution Form2 would handle this itself (during load, construction, show, etc.) But I think this is not real world code? If you still can't get it done I'll create a complete example for you - just let me know..

Hi systemerror121,

I think as I understand from your question you need to to change the backcolr of the picturebox in form2 when opening it.

so you can add your code in the constructor of the form2 class or in form2_load event handler as follows :

public Form2()
{
    InitializeComponent();
    picturebox1.backcolor = color.green;
}

or

public void Form2_Load(object sender, EventArgs e)
{
    picturebox1.backcolor = color.green;
}

I hope this help,
:)