Model Pop Up Extender In Ajax

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ASP.NET

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Hi,
Event under asp.net ajax control Model pop up extender is not firing, plz give me the solution

Posted 2-May-11 20:02pm

Rupam Sarve

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Mahendra.p25 3-May-11 2:12am

which event. Please elaborate or post your code

Sandeep Mewara 3-May-11 2:32am

And how do we guess what and how you are doing it?

Ankur^\m/ 3-May-11 3:35am

You ~~plz~~ please give us more details.

Sunasara Imdadhusen 3-May-11 5:28am

Not clear!!!

bbirajdar 14-May-12 12:58pm

Not firing? It must have run out of the bullets.. ;) .. How can somebody help you if you dont show them the code.. ? Are you really a programmer ?

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Nayan Ambaliya · Answer 1 · 2011-05-03T20:20:00

Please be a little bit more descriptive about your question
Anyways, I am assuming the below scenarios

1. You click a button on the .aspx page but the modal popup is now shown
2. You have a button inside the panel which is shown when modal popup is active and that button when clicked does not fire the event.

Solution for point 1

ASPX Page:

//Normal Button
<asp:button runat="server" id="btnClickMe" text="Click Me" xmlns:asp="#unknown">
<asp:button runat="server" id="btnDummyClickMe" text="Click Me" style="display:none;" xmlns:asp="#unknown">

<cc1:modalpopupextender  runat="server" id="mpeShow" popupcontrolid="pnlPopup" targetcontrolid="btnDummyClickMe" ...="" xmlns:cc1="#unknown">

Code Behind Page

//Normal Button Click
protected void btnClickMe_Click(object sender, EventArgs e)
{
//do whatever operations you want to do
this.mpeShow.Show();
}

This will show the modal popup when click on the button named: Click Me

Solution for point 2
It generally happens that when you click a button inside the modal popup panel, the event is fired but the popup disappears.
Say for example, in the modal popup shown, you have two textboxes and a button. When you click that button, value from the first text box needs to be copied over to second text box.
For this purpose, it is the same code as

this.TextBox2.Text = this.Textbox1.Text;

But, along with this, you need to include the line as:
this.mpeShow.Show();

So the steps would be in the button click of a button inside the pop up panel:

//show the pop up
//type something in text box
//click the button
//do whatever operation you like to do
//show the popup again

Hope this helps. If you have any other questions in mind, or you think I understand the question differently, please let me know and I can explain better.

-Nayan
Coding is an earthly heaven

Shaikh Sohail · Answer 2 · 2012-05-14T06:11:00

XML

<asp:UpdatePanel ID="UpdatePanel1" runat="server">
    <ContentTemplate>
        <asp:Button ID="Btnshow" runat="server" Text="Show" OnClick="Btnshow_Click" />
        <asp:Button ID="BtnTarget" runat="server" Text="Target" Style="display: none" />
        <asp:TextBox ID="TextBox1" runat="server">
        </asp:TextBox>
        <input type="button" value="Get" onclick="abc()" />
        <asp:ModalPopupExtender ID="ModalPopupExtender1" runat="server" TargetControlID="BtnTarget"
            PopupControlID="Panel1">
        </asp:ModalPopupExtender>
        <asp:Panel ID="Panel1" runat="server" BackColor="Black" Width="300px" Height="300px">
            <asp:UpdatePanel ID="UpdatePanel2" runat="server" ChildrenAsTriggers="false" UpdateMode="Conditional">
                <ContentTemplate>
                    <asp:Button ID="BtnHide" runat="server" Text="Hide Button" OnClick="BtnHide_Click" />
                </ContentTemplate>
                <Triggers>
                    <asp:AsyncPostBackTrigger ControlID="BtnHide" EventName="Click" />
                </Triggers>
            </asp:UpdatePanel>
        </asp:Panel>
    </ContentTemplate>
    <Triggers>
        <asp:AsyncPostBackTrigger ControlID="Btnshow" EventName="Click" />
    </Triggers>
</asp:UpdatePanel>

C#

protected void Btnshow_Click(object sender, EventArgs e)
  {
      ModalPopupExtender1.Show();
  }
  protected void BtnHide_Click(object sender, EventArgs e)
  {
      ModalPopupExtender1.Hide();
  }

Model Pop Up Extender In Ajax

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