Two datagridviews: Sending information from one to the other

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I have two DataGridView's: DataGridView2, DataGridView3.

I have checkboxes in DataGridView2 in a column named "Column1".

I want to be able to select multiple rows in DataGridView2 and click and button and DataGridView3 would contain only the checkboxed rows.

This is what I have so far in the "Transfer" button:

dataGridView3.Rows.Clear();
            string x = string.Empty;
            for (int ii = 0; ii <= dataGridView2.Rows.Count - 1; ii++)
            {

                DataGridViewCheckBoxCell checkCell = (DataGridViewCheckBoxCell)dataGridView2.Rows[ii].Cells["Column1"];



                //buttonCell.Enabled = !(Boolean)checkCell.Value;



                //Displays the status value of the check box


                if (dataGridView2.Rows[ii].Cells["Column1"].Value == null || dataGridView2.Rows[ii].Cells["Column1"].Value.ToString() == "" || Convert.ToBoolean(dataGridView2.Rows[ii].Cells["Column1"].Value) == false)
                { }
                else
                {

                    if (dataGridView2.Rows[ii].Cells[0].Value != null)
                    { dataGridView3.Rows.Add(null,dataGridView2.Rows[ii].Cells[1].Value.ToString()); }

                    if (dataGridView2.Rows[ii].Cells[0].Value != null)
                    { dataGridView3.Rows[dataGridView3.Rows.Count + 1].Cells[1].Value = dataGridView2.Rows[ii].Cells[2].Value.ToString(); }

                    //if (dataGridView2.Rows[ii].Cells[0].Value != null || dataGridView2.Rows[ii].Cells[0].Value != "")
                    //{ dataGridView3.Rows.Add(dataGridView2.Rows[ii].Cells[0].Value.ToString()); }



                        //dataGridView3.Rows[ii].Cells[3].Value = dataGridView2.Rows[ii].Cells[3].Value.ToString();

                }

Posted 24-Apr-11 12:51pm

ori samara

Updated 24-Apr-11 15:38pm

HimanshuJoshi

v2

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HimanshuJoshi 24-Apr-11 21:39pm

Added pre tag.

velvet7 25-Apr-11 1:34am

Well, I couldn't get exactly what do you want, but check this:
dataGridView2.SelectedRows[index].Cells["cellname"].Value

This will get the selected cell's value.

1 solution

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This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

LakshmiNarayana Nalluri · Answer 1 · 2011-04-25T00:15:00

public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
SqlConnection cn = new SqlConnection("server=LakshmiNarayana;uid=sa;pwd=cybage@123;database=narayana");
private void Form1_Load(object sender, EventArgs e)
{
SqlDataAdapter da = new SqlDataAdapter("select * from student", cn);
DataTable dt = new DataTable();
da.Fill(dt);
dataGridView1.DataSource = dt;
DataGridViewColumn dc1 = new DataGridViewColumn(new DataGridViewTextBoxCell());
DataGridViewColumn dc2 = new DataGridViewColumn(new DataGridViewTextBoxCell());
DataGridViewColumn dc3 = new DataGridViewColumn(new DataGridViewTextBoxCell());
dataGridView2.Columns.Add(dc1);
dataGridView2.Columns.Add(dc2);
dataGridView2.Columns.Add(dc3);
}
private void button1_Click(object sender, EventArgs e)
{
dataGridView2.Rows.Clear();
string x = string.Empty;

for (int ii = 0; ii <= dataGridView1.Rows.Count - 1; ii++)
{
DataGridViewCheckBoxCell checkCell = (DataGridViewCheckBoxCell)dataGridView1.Rows[ii].Cells["Column1"];
if (dataGridView1.Rows[ii].Cells["Column1"].Value == null || dataGridView1.Rows[ii].Cells["Column1"].Value.ToString() == "" || Convert.ToBoolean(dataGridView1.Rows[ii].Cells["Column1"].Value) == false)
{
}
else
{
//if (dataGridView1.Rows[ii].Cells[0].Value != null)
//{
//dataGridView2 .ColumnAdded
dataGridView2.Rows.Add(dataGridView1.Rows[ii].Cells[1].Value.ToString(), dataGridView1.Rows[ii].Cells[2].Value.ToString(), dataGridView1.Rows[ii].Cells[3].Value.ToString());
//}
//if (dataGridView1.Rows[ii].Cells[0].Value != null)
//{
// dataGridView2.Rows[dataGridView2.Rows.Count + 1].Cells[1].Value = dataGridView1.Rows[ii].Cells[2].Value.ToString();
//}

}

}

}

}

Two datagridviews: Sending information from one to the other

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Two datagridviews: Sending information from one to the other

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Solution 1

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