How do I get coefficient from an equation as an input

Question

1.00/5 (1 vote)

See more:

i wanted to solve equations by taking the equation from user instead of taking only coefficient how do i collect the coefficents from the equation

What I have tried:

C++

#include <iostream>
#include <string>

using namespace std;

int main()
{
   string s;
   cin>>s;
   for(int i=0;i<strlen(s);i++)
   {
       if()
   }
    return 0;
}

Posted 17-Mar-16 6:59am

Member 12270086

Updated 17-Mar-16 7:51am

Matt T Heffron

v2

Add a Solution

Comments

jeron1 17-Mar-16 13:19pm

Have you tried it on paper? If you're going to show code, try to show code that can compile.

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

CPallini · Answer 1 · 2016-03-17T07:25:00

try, for instance

C++

#include <iostream>
using namespace std;

int main()
{

 double a,b;

 cout << "the equation is 'ax+b = 0'" << endl;
 cout << "please enter the value of 'a'" << endl;
 cin >> a;
 cout << "now, please enter the value of 'b'" << endl;
 cin >> b;

 if ( a != 0.0)
   cout << "the value of 'x' is " << (-b/a) << endl;
 else
   cout << "sorry, unable to find out the value of 'x'" << endl;

}

[update]
If you need to accept from the user a single string like, for instance

C++

23.75 x + 10.18 = 0

The you have to build a (simple) parser in order to

formally validate the equation
extract the values a = 23.75, b = 10.18

.
Google is you friend[^].
[/update]