how to compare 2 arrays value by their position

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1.00/5 (2 votes)

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i have 2 array
a[]={1,2,3,4,5}
b[]={2,3,4,4,5}
2 arrays are same length
here i have to compare this 2 according to their position,i any position do not match give error unsuccessful
like a[0]=1
b[0]=2
error unsuccessful
no further comparison

Posted 23-Nov-15 0:46am

Member 11970398

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phil.o 23-Nov-15 7:00am

What have you tried? That seems so trivial.

Patrice T 24-Nov-15 3:48am

HomeWork ?

Member 11403530 24-Nov-15 5:26am

a[]={1,2,3,4,5}
This isn't array. This is array with an object.

use this
var a = [1,2,3,4,5]

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CPallini · Answer 1 · 2015-11-23T01:01:00

Solution 1

That's trivial. Make a loop over the array items, exiting with false at first mismatch. If the loop completes (no mismatches) then return true.

Posted 23-Nov-15 1:01am

CPallini

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Member 11970398 23-Nov-15 7:43am

can u help me with this

Raje_ · Answer 2 · 2015-11-23T02:52:00

You can try this way :

JavaScript

var  a = new Array(1,2,3,4,5);
           var b = new Array(2,3,4,4,5);
           var errorCounter = 0;
           if (a.length != b.length) { errorCounter = 1 }
           //a.sort();
           //b.sort();
           for (var i = 0, l = a.length; i < l; i++) {
               if (a[i] !== b[i]) {
                   errorCounter++;
               }
           }
           if (errorCounter > 0) {
               alert("Not Same");
           }
           else{
               alert("Same");
           }

[Edit] : commented sorting method.
Good luck.

Member 11970398 · Answer 3 · 2015-11-23T01:22:00

Solution 2

for (i=0; i < len; i++) {
if (A[i] !== B[i]) {
o.push({idx: i, elem1: A[i], elem2: B[i]});
}
}

Posted 23-Nov-15 1:22am