want to bind string using comma separated

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string json="[
{
"ParentId":"a9764da3147845c184bd272cef6a5937",
"Path":"/LMS/Cabinet/bdc2cd8e1da3451c84e332d1aa74f605",
"CreatedBY":"admin",
"IsActive":"Y",
"CabinetName":"LMS",
"FolderTag":"IT mobile computing,Comm Skills",
"Name":"JAVA",
"UpdatedBY":"",
"Type":"Folder",
"IsDelete":"N",
"UpdatedON":"",
"Id":"bdc2cd8e1da3451c84e332d1aa74f605",
"CreatedON":"2015_09_08-11:19:50",
"TemplateId":"dd42c8a71a954c1d948ef35492ee1242"
},
{
"ParentId":"a9764da3147845c184bd272cef6a5937",
"Path":"/LMS/Cabinet/3aae020c256f4dc1ab705af67bede2c7",
"CreatedBY":"admin",
"IsActive":"Y",
"CabinetName":"LMS",
"FolderTag":"IT mobile computing,Comm Skills",
"Name":"Spring",
"UpdatedBY":"",
"Type":"Folder",
"IsDelete":"N",
"UpdatedON":"",
"Id":"3aae020c256f4dc1ab705af67bede2c7",
"CreatedON":"2015_09_04-16:58:05",
"TemplateId":"dd42c8a71a954c1d948ef35492ee1242"
},
{
"ParentId":"a9764da3147845c184bd272cef6a5937",
"Path":"/LMS/Cabinet/c139b33a22a94a25bf624b94450aee3e",
"CreatedBY":"admin",
"IsActive":"Y",
"CabinetName":"LMS",
"FolderTag":"Social Skills",
"Name":"SQL",
"UpdatedBY":"",
"Type":"Folder",
"IsDelete":"N",
"UpdatedON":"",
"Id":"c139b33a22a94a25bf624b94450aee3e",
"CreatedON":"2015_09_04-16:54:44",
"TemplateId":"dd42c8a71a954c1d948ef35492ee1242"
}
] "

this is my json string and i want to only "Name" field with comma separated into another variable...

example: string res={"JAVA","SPRING","SQL",...}

like that plz give me solution

Posted 9-Sep-15 0:35am

Member 11942465

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Comments

Amit Jadli 9-Sep-15 7:03am

dynamic iJson = JsonConvert.DeserializeObject(json);
List<string> res = new List<string>();
foreach (var item in iJson)
{
res.add(item.Name);
}

By this you can get all names in list string.

Thanks7872 9-Sep-15 8:07am

What have you tried till now?

Member 11942465 9-Sep-15 8:36am

will u plz send me code

Member 11942465 9-Sep-15 8:42am

dynamic jsonObj = JsonConvert.DeserializeObject(json);

List<string> res = new List<string>();
foreach (var item in jsonObj)
{
res.Add(item.Name);
}

Member 11942465 9-Sep-15 8:40am

this is my code

dynamic jsonObj = JsonConvert.DeserializeObject(json);

List<string> res = new List<string>();
foreach (var item in jsonObj)
{
res.Add(item.Name);
}

Member 11942465 9-Sep-15 9:00am

i have an error when m run application
The best overloaded method match for 'System.Collections.Generic.List<webapplication_test.webform1.jsonresult>.Add(WebApplication_Test.WebForm1.JsonResult)' has some invalid arguments

foreach (var item in jsonObj)
{
res.Add(item.Name);
}

Member 11942465 10-Sep-15 1:28am

thank u sooo much its done

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Member 11732163 · Answer 1 · 2015-09-09T02:03:00

Solution 1

var objdata = $.parseJSON(json);

In objdata you will get all the values in which using for loop, get the values in the index 6, which is name

Posted 9-Sep-15 2:03am

Member 11732163

Comments

Member 11942465 9-Sep-15 8:36am

will u plz sen me code

Thanks7872 9-Sep-15 8:43am

No one will. Try it and come back when you have specific question.

Member 11942465 9-Sep-15 8:50am

i want only name field value like this {"JAVA","SPRING","SQL",...}
thats it

Member 11942465 18-Sep-15 8:17am

Try this
var result = JsonConvert.DeserializeObject<jsonobject[]>(json);
string jsonnum = string.Join(",", result.Select(x => x.Name).ToArray());