Need help on SQL Error

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MySQL

web-hosting

Hello Guys,

I don't have any problems when I was developing in my localhost computer but when I deploy the system I encounter problems in the database

This is the SQL Command:

CREATE ALGORITHM=UNDEFINED DEFINER=`root`@`localhost` SQL SECURITY DEFINER VIEW `jobslist_view` AS select `a`.`job_id` AS `job_id`,`a`.`position` AS `position`,`a`.`description` AS `description`,`a`.`date_posted` AS `date_posted`,`a`.`date_inactive` AS `date_inactive`,`a`.`number_of_vacancy` AS `number_of_vacancy`,`b`.`hospital_id` AS `hospital_id`,`b`.`hospital_name` AS `hospital_name`,`b`.`hospital_address` AS `hospital_address`,`b`.`hospital_phone` AS `hospital_phone`,`b`.`hospital_email` AS `hospital_email`,`c`.`realname` AS `realname`,`c`.`user_id` AS `user_id` from ((`jobs_tbl` `a` left join `hospitals_tbl` `b` on((`a`.`hospital_id` = `b`.`hospital_id`))) left join `users_tbl` `c` on((`a`.`user_id` = `c`.`user_id`))) where (`a`.`archive` = 0);

This is the error message
#1227 - Access denied; you need the SUPER privilege for this operation
You can also see the actual error message here:
Image

I don't have any problem in my local computer in performing that sql statement. But I am having problem when i upload it in my new hosting provider. I am not sure but I think this problem is from the hosting provider side because of user privilege. But I really want to ask idea from your side guys.

I try to change the user name and ipaddress that is given by the hosting provider but the outcome is still the same.

CREATE ALGORITHM=UNDEFINED DEFINER=`admin_user`@`125.5.102.200` SQL SECURITY DEFINER VIEW `jobslist_view` AS select `a`.`job_id` AS `job_id`,`a`.`position` AS `position`,`a`.`description` AS `description`,`a`.`date_posted` AS `date_posted`,`a`.`date_inactive` AS `date_inactive`,`a`.`number_of_vacancy` AS `number_of_vacancy`,`b`.`hospital_id` AS `hospital_id`,`b`.`hospital_name` AS `hospital_name`,`b`.`hospital_address` AS `hospital_address`,`b`.`hospital_phone` AS `hospital_phone`,`b`.`hospital_email` AS `hospital_email`,`c`.`realname` AS `realname`,`c`.`user_id` AS `user_id` from ((`jobs_tbl` `a` left join `hospitals_tbl` `b` on((`a`.`hospital_id` = `b`.`hospital_id`))) left join `users_tbl` `c` on((`a`.`user_id` = `c`.`user_id`))) where (`a`.`archive` = 0);

Thank You.