Displaying multiple sql results with for each loop and update them separately with a submit button

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Hi, I am using this code to display multiple sql rows in a table. I want everytime i click the submit button on the right to run an sql query to update a value in the listings table where the user id is equal to the corresponding user id of each row. I am a bit confused on how to do it any help?

<?php
                       foreach($user_listings as $user_listing){
                               echo '<tr class="danger">';
                               echo '<td>'.$user_listing['user_id']. '</td>';
                               echo '<td>Pending Approval</td>';
                               echo '<td>'.  $user_listing['listing_header']. '</td>';
                               echo '<td>'.  $user_listing['listing_subheader']. '</td>';
                               echo '<td>'.  $user_listing['category']. '</td>';
                               echo '<td>'.  $user_listing['listing_city']. '</td>';
                               echo '<td>'.  $user_listing['listing_adress']. '</td>';
                               echo '<td>'.  $user_listing['listing_text']. '</td>';
                               echo '<td>';
                       ?>
                               <form action='' method='POST' class="approve-form">
                                   <input type='submit' value="Approve"  class="btn btn-success" name='submit' />
                                </form>
                   <?php       echo '</td>';
                               echo '</tr>';
                       }
                   ?>
                 </tbody>

Posted 29-Mar-15 5:20am

Witchblade23

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ramyajaya · Accepted Answer · 2015-03-29T05:58:00

Solution 1

This solution may be quite tricky or lengthy even, sorry for that but it worked very well in a long run and was easy to debug to.

Step 1 maintain a hidden textbox
holding the row count of the table you create.
example $ count=count ($ user_listings);

step 2 process each value using for each

Step 3 inside for each on creating table create dynamic id for the textboxes
For ex <input id='<?php echo "listing_header".$iteratedvalue?>'></input>

On submit function

Process it the same way and fetch the values from the $post[dynamic ids]
Example

VB

<? php $ value =  $ POST ["listing_header". $ iteratedvalue '];?>

Posted 29-Mar-15 5:58am

ramyajaya

Updated 29-Mar-15 12:37pm

v4

Comments

Witchblade23 29-Mar-15 13:17pm

Thank you for your answer, do you think i could also combine it with ajax so that the page dont refresh and jump up?

ramyajaya 29-Mar-15 16:51pm

You can also combine with ajax if you need . as per the scenario which you have mentioned you might not need ajax if u want to store the entries made in front end

Witchblade23 29-Mar-15 17:51pm

i am sorry but i tried the solution and i think i am missing something, could you collaborate a bit more in your steps above?

ramyajaya 29-Mar-15 18:19pm

Could u pls check on to your errors or post your code

Witchblade23 29-Mar-15 18:37pm

in step 3 what id do i have to give to the input field? Should i do the count outside the for each loop? I just can't understand how this will work

ramyajaya 29-Mar-15 18:42pm

Sorry I updated it right now it is the same as how you access in post of the value

Witchblade23 30-Mar-15 16:08pm

thanks i made it work :)