Hex to Dec conversion issue

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Hi,
can anyone tell me what conversion rule is used to convert below numbers ?

0B2AA4CC > 0222646835
00AA62CD > 0005596219
0A24ACD0 > 0088232880

Both numbers are UID from EM Marine 125kHz ID card (probably EM4102),
left string is HEX number from existing DB and right string is gathered from USB card reader (HID device).

USB card reader should use 8H10D output, but it doesn't match when I try convert left number like:

C#

Console.WriteLine(BitConverter.ToUInt32(new byte[] { 0xCC, 0xA4, 0x2A, 0x0B }, 0));

I also tried to use little/big/middle endian, but no success.

Posted 16-Dec-14 3:36am

vacko

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Chris Ross 2 16-Dec-14 9:54am

Have you read the data sheet for the EM4102? (http://www.google.co.uk/url?sa=t&rct=j&q=&esrc=s&source=web&cd=1&ved=0CCEQFjAA&url=http%3A%2F%2Fwww.mcselec.com%2Ftiny%2Fdwn%2F193%2F54&ei=R0WQVPj4Kauy7Qa1soCAAg&usg=AFQjCNFZCEhbONWVUP9k69STcHYxUSVogQ&bvm=bv.81828268,d.ZGU&cad=rja)

I took a quick look at it, and at a guess the 'hex' number you show above is maybe a hex representation of a bit stream the device outputs? In the data sheet, notice that "Data can be codes as Manchester, Biphase or PSK" (page 1). I think it also carries a parity bit (page 5). Now, whatever device you are using to read the EM device probably handles the encoding/decoding ... but maybe it's up to you to strip the parity?

Sergey Alexandrovich Kryukov 16-Dec-14 10:34am

You need to understand the principle, which is quite simple, not the "rule". Programming is not done by formulas or grandmother's recipe.
—SA

2 solutions

Solution 1

The fact that two of the whatever-encoded values show the same decimal (?) result indicates no linear conversion is going on here. I assume you are going to need the device manufacturer's information on the internal formats.

Posted 16-Dec-14 3:51am

BillWoodruff

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Andreas Gieriet · Accepted Answer · 2014-12-16T04:25:00

Write both values as hex, side by side, then as bits, e.g.

             0B2AA4CC = 0000 1011 0010 1010 1010 0100 1100 1100
0222646835 = 0D455233 = 0000 1101 0100 0101 0101 0010 0011 0011

Do you see the pattern? The bit sequence is inverse (per nibble).

1) take the 8 digit hex number
2) convert each hex digit to the reverse bit sequence value
3) create a 10 digit decimal number from it
4) put all together 8-bit-hex > 10-digit-dec

[EDIT]
Some dense code to show the conversion working.
The nibbles to inverse are looked up by using the lowest nibble of the input value and shifting that input value right for each next nibble. The locked up value is then shifted left to the respective position and set into the target value.

C#

class Program
{
    static readonly UInt32[] LOOKUP =
    { 0x0,0x8,0x4,0xC,0x2,0xA,0x6,0xE,0x1,0x9,0x5,0xD,0x3,0xB,0x7,0xF };
    static UInt32 Convert8HTo10D(UInt32 val8H)
    {
        UInt32 val10D = 0x0;
        for (int pos = 0; pos < 32; pos += 4, val8H >>= 4) val10D |= LOOKUP[val8H & 0xF] << pos;
        return val10D;
    }
    static void Write8H10D(UInt32 val8H)
    {
        Console.WriteLine("{0:X08} > {1:D10}", val8H, Convert8HTo10D(val8H));
    }
    static void Main(string[] args)
    {
        Write8H10D(0x0B2AA4CC);
        Write8H10D(0x00AA62CD);
        Write8H10D(0x0A24ACD0);
    }
}

This results in

0B2AA4CC > 0222646835
00AA62CD > 0005596219
0A24ACD0 > 0088232880

[/EDIT]

Cheers
Andi