How to use function pointers?

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hi all:-)

i have the following Problem (i think it is a function pointer Problem)

i have to set in a Programm "DLLSPLIT"

DLLSPLIT is defined as follows:

typedef int (WINAPI DLLSPLIT) (LPSTR);

i have to do:

DLLSPLIT* dllsplit= .... (what to write here????)

i tried define a function:

int foo(LPSTR bla)
{
//do something
}

and then dllsplit= &foo;

but that doesnt work....

can someone help me?

Posted 19-Nov-14 22:52pm

Member 10781325

Updated 19-Nov-14 22:53pm

v3

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nv3 20-Nov-14 5:07am

Define foo as:
int WINAPI foo (LPSTR p)
{
...
}
You must exactly match the definition in the typedef!
If that doesn't help, then show the exact error messages you are getting. "That doesn't work" is not a good starting point for others to help you.

2 solutions

Solution 1

Given the appearance of the WINAPI define, it's likely a matter of calling convention mismatch (see here[^] for instance) but without more detail about exactly how it "doesn't work" we can't help.

Posted 19-Nov-14 23:05pm

Orjan Westin

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den2k88 · Accepted Answer · 2014-11-19T23:08:00

Please post the exact error message given by the compiler.

Note that the default calling convention for C/C++ functions is __cdecl, you probably want to define foo as

C++

int __stdcall foo(LPSTR bla)

that is the requirement for the pointers declared as WINAPI.

Note also that if you're in a class then foo should be static and declared as __stdcall, because in classes the defualt calling convention is __thiscall.

Or, as the other users said above,

C++

int WINAPI foo (LPSTR bla)

afer all WINAPI is just a define for __stdcall