I Am A Beginner In Java Can I Write This Code In Another Way.?

Question

3.00/5 (4 votes)

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Java

if (x % 100 == 11 || x % 100 == 22 || x % 100 == 33 || x % 100 == 44
				|| x % 100 == 55 || x % 100 == 66 || x % 100 == 77
				|| x % 100 == 88 || x % 100 == 99 || x % 100 == 00) {

			return true;
		}

Posted 18-Sep-14 4:18am

shashanknautiyal

Updated 18-Sep-14 4:23am

PIEBALDconsult

v2

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4 solutions

Solution 3

C#

int tempINT = x % 100;
            if (tempINT % 11 == 0
                || tempINT == 0)
            {
                return true;
            }

Posted 18-Sep-14 4:54am

KaraUgur

Comments

hypermellow 18-Sep-14 11:03am

Nice! 5'd

shashanknautiyal 18-Sep-14 11:04am

thank you for your suggestion ..i want to check whether a number has the same last two digits or not and returns true or false in simple way with out switch case if possible

TorstenH. 19-Sep-14 2:11am

+5!

@OP: You need to figure a way to cut the number down to a 2 digit.

Solution 4

Further to other answers, you want to know that the last two digits are divisible by 11:

Java

boolean lastTwoEleven(int x)
{
    // mod 100 gives last two digits & mod 11 checks if divisble
    return ((x % 100) % 11) == 0;
}

Posted 22-Sep-14 23:32pm

Nagy Vilmos

Solution 1

Hi,

You could use a switch statement:

[update}
Since you are looking to reuse this logic, it would be better to wrap it in a function, that way you can call it multiple times (without rewriting it).

Java

if(doSomeCheck(x)==true){
 ... do stuff
}else{
 ... do other stuff
}

if(doSomeCheck(y)==true){
 ... do stuff
}else{
 ... do other stuff
}


public boolean doSomeCheck(int x){
 boolean bOut=false;
 switch(x % 100){
  case 0:
  case 11:
  case 22:
  case 33:
  case 44:
  case 55:
  case 66:
  case 77:
  case 88:
  case 99:
   bOut=true;
   break;
  default:
   bOut=false;
 }
 return bOut;
}

Hope it helps.

Posted 18-Sep-14 4:26am

hypermellow

Updated 18-Sep-14 4:59am

v4

Comments

shashanknautiyal 18-Sep-14 10:52am

thank u for your suggestion i have four int variables x,y,z,w for all four i have to compare it with this values (11,22,33.....) so i have to build four switch case ?
actually i want to find which int variable has last two no same(like 45611 ) and output would be in boolean

hypermellow 18-Sep-14 11:00am

Hi, I've updated my solution to avoid re-writing the switch statement multiple times.

Hope it helps.

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PIEBALDconsult · Accepted Answer · 2014-09-18T04:31:00

Solution 2

(I don't know Java.)

How about:

Java

return (x % 100 == 11 || x % 100 == 22 || x % 100 == 33 || x % 100 == 44
  || x % 100 == 55 || x % 100 == 66 || x % 100 == 77
  || x % 100 == 88 || x % 100 == 99 || x % 100 == 00) ;

You could use a local variable to hold x % 100 and save some typing.
I suppose you could use a switch or some sort of lookup table.

Also, consider this:

C#

int x = 455 ;
int x1 = x % 10 ;
int x10 = x / 10 % 10 ;

bool b = x1 == x10 ;

So, to put that all together:

Java

public boolean doSomeCheck(int x){ return ( x % 10 ) == ( x / 10 % 10 ) ; }

Posted 18-Sep-14 4:31am

PIEBALDconsult

Updated 18-Sep-14 5:27am

v3

Comments

hypermellow 18-Sep-14 11:04am

The 2nd of your approachs is really nice! 5'd

shashanknautiyal 18-Sep-14 11:05am

thank you for your suggestion ...still working on it

Sergey Alexandrovich Kryukov 18-Sep-14 13:30pm

Step by step... 5ed.

Even the first sample is useful: it helps to demonstrate how silly are the lines like

if (A)
   return true; // but A is already Boolean!
// and what to return is not A? :-)

—SA