Error:an outgoing call cannot be made since the application is dispatching an input-synchronous call

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Hi
I am working on c# windows application. I am using Edraw office viewer component(.ocx file) in my project, and while running my application if i go to desktop or press (win+d) key i am getting an exception "an outgoing call cannot be made since the application is dispatching an input-synchronous call".Please provide solution for this problem.

Thanks

Posted 20-Mar-14 22:51pm

Member 10391350

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Synetech 17-Jul-14 22:53pm

If you (or anyone else) are (still) having this problem, check the following two pages; they have some explanations and solutions which seem to be helpful.

• An outgoing call cannot be made since the application is dispatching an input-synchronous call
• COM outbound call results in “An outgoing call cannot be made since the application is dispatching an input-synchronous call.”

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Ankur^\m/ · Answer 1 · 2014-03-20T23:00:00

Solution 1

Have you checked here[^]?

Posted 20-Mar-14 23:00pm

Ankur^\m/

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Member 10391350 21-Mar-14 5:42am

cant get solution from those links

Ankur^\m/ 24-Mar-14 1:39am

That's your job to find out. Did you go through the links and tried anything?

Synetech 17-Jul-14 22:49pm

> That's your job to find out.

Actually no, no it’s not. The reason they asked was because they couldn’t figure it out and reached out for help. LMGTFY is stupid and idiotic. It is not 1998 anymore, and even grandparents are familiar with Google as a first stop, so your response was anything but helpful, and in fact, offensive and insulting. ಠ_ಠ (The worst part of it is that whenever someone condescends to suggest Google as an “answer” to a question, by that point the page with the question itself is often one of the top search results.)

How would you like it if you had a medical problem and when you went to the doctor, they just gave you a phone-book opened to “Doctors” and told you it’s your job to find a solution. Or, if they just handed you a slip of paper with the library call-number of the Physician’s Desk Reference and told you that it’s your job to use that to figure out what’s wrong with you? ◔_◔

Ankur^\m/ 1-Aug-14 8:55am

When you ask a question here, the guideline displayed on the right clearly says (point 2): "have you searched or Googled?".
The user has exact error message with him. A simple Google search gives so many discussions already on the error. Moreover Google is smart enough to show the most relevant and best ones in the very first page. Most issues have already been faced by people and the programmer community have already discussed them and shared the solutions. My point is - a simple search would have helped him already. And if it didn't, then he should have come and asked here... most of us would have helped happily. I hope you understand what I am saying.

I would also like to mention that the link you have provided in your comment to the user is the first link in the search result link I have provided.

Synetech 2-Aug-14 10:58am

You do realize that Google’s search results are not static and they change over time, and are also region-dependent right? It’s likely that the aforementioned pages were in fact, not the top search results at the time that the OP asked and only bubbled up later on.

Additionally, while the OP has not listed where they live, statically, there is a pretty good chance that they do not live in North America and the local version of Google that they use does not list those at the top (if at all). I have seen people rant on SuperUser about someone not using Google, only to have me explain that the asker was from China or Iran or something so their search results are dramatically different, and point out that telling them to use Google was unnecessarily condescending. Like I said, everybody knows about Google now, even those that cannot even use it due to government blocks.

For what it’s worth, I suppose most people, especially those living in countries where the government doesn’t filter the Internet, probably don’t realize that search results are region-dependent.