Objects not recognized when inside a function

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1.00/5 (1 vote)

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Hello,

I am writing a software application that I want to update the Status Strips Label with a value passed from one function(class) to another. The problem is the new function does not recognize the tool strip as an object. Is there anyway around this issue?

Posted 11-Jul-14 5:10am

Retro617

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George Jonsson 11-Jul-14 11:15am

Really?
I'm not sure how you expect anyone to help you with the information you provide.
Please improve the question.

Retro617 11-Jul-14 12:02pm

Thank you George. You are right my question was terribly vague. So this is what I want to do, I am creating a back up program. I found the only way to get the file names from all the sub directories was to create a function call to my ShowAllFolders(). Inside of that I created a queue so that I do not have to wait forever for the files to be searched. A basic in and out if you will.

At this point I want to show the file names being queued in my status strip label(which I have created). Unfortunately, the status strip is not available to write to, I will put the threee functions I want to work together with here:

private void backgroundWorker2_DoWork(object sender, DoWorkEventArgs e)
{
// System.Threading.Thread.Sleep(60000);

foreach(string s in Directory.GetLogicalDrives())
{
ShowAllFoldersUnder(s, 0);
}

}

public static void ShowAllFoldersUnder(string path, int indent)
{
workingFolder localWorkingFolder;

Queue folderListQueue = new Queue();
int keyCounter = 0;
try
{
foreach (string folder in Directory.GetDirectories(path))
{
localWorkingFolder.completeWorkingPath = folder;
folderListQueue.Enqueue(localWorkingFolder);
Console.WriteLine("Count of Items in the Queue: " + folderListQueue.Count);
Console.WriteLine("{0}{1}", new string(' ', indent), Path.GetFullPath(folder));
localWorkingFolder = (workingFolder)folderListQueue.Dequeue();
string PathToSearch = localWorkingFolder.completeWorkingPath;
//Console.WriteLine(localWorkingFolder);
try
{ foreach(string f in Directory.GetFiles(PathToSearch,"*.*"))
{
UpdateStatus(f);
Console.WriteLine(f);
}
}
catch (System.Exception excpt)
{
Console.WriteLine(excpt.Message);
}

ShowAllFoldersUnder(folder, +2);
keyCounter++;
}
}
catch (UnauthorizedAccessException) { }
Console.WriteLine("There were " + keyCounter + " files to be searched");
}

public static void UpdateStatus(string fileSearched)
{
string updatedFile = fileSearched;
//MessageBox.Show(updatedFile);
return;

}Thank you George. You are right my question was terribly vague. So this is what I want to do, I am creating a back up program. I found the only way to get the file names from all the sub directories was to create a function call to my ShowAllFolders(). Inside of that I created a queue so that I do not have to wait forever for the files to be searched. A basic in and out if you will.

At this point I want to show the file names being queued in my status strip label(which I have created). Unfortunately, the status strip is not available to write to, I will put the threee functions I want to work together with here:

private void backgroundWorker2_DoWork(object sender, DoWorkEventArgs e)
{
// System.Threading.Thread.Sleep(60000);

foreach(string s in Directory.GetLogicalDrives())
{
ShowAllFoldersUnder(s, 0);
}

}

public static void ShowAllFoldersUnder(string path, int indent)
{
workingFolder localWorkingFolder;

Queue folderListQueue = new Queue();
int keyCounter = 0;
try
{
foreach (string folder

CHill60 11-Jul-14 11:41am

Post the code in the function, tell us where that function is. I suspect it's out of scope.

Retro617 11-Jul-14 12:02pm

Thank you George. You are right my question was terribly vague. So this is what I want to do, I am creating a back up program. I found the only way to get the file names from all the sub directories was to create a function call to my ShowAllFolders(). Inside of that I created a queue so that I do not have to wait forever for the files to be searched. A basic in and out if you will.

At this point I want to show the file names being queued in my status strip label(which I have created). Unfortunately, the status strip is not available to write to, I will put the threee functions I want to work together with here:

private void backgroundWorker2_DoWork(object sender, DoWorkEventArgs e)
{
// System.Threading.Thread.Sleep(60000);

foreach(string s in Directory.GetLogicalDrives())
{
ShowAllFoldersUnder(s, 0);
}

}

public static void ShowAllFoldersUnder(string path, int indent)
{
workingFolder localWorkingFolder;

Queue folderListQueue = new Queue();
int keyCounter = 0;
try
{
foreach (string folder in Directory.GetDirectories(path))
{
localWorkingFolder.completeWorkingPath = folder;
folderListQueue.Enqueue(localWorkingFolder);
Console.WriteLine("Count of Items in the Queue: " + folderListQueue.Count);
Console.WriteLine("{0}{1}", new string(' ', indent), Path.GetFullPath(folder));
localWorkingFolder = (workingFolder)folderListQueue.Dequeue();
string PathToSearch = localWorkingFolder.completeWorkingPath;
//Console.WriteLine(localWorkingFolder);
try
{ foreach(string f in Directory.GetFiles(PathToSearch,"*.*"))
{
UpdateStatus(f);
Console.WriteLine(f);
}
}
catch (System.Exception excpt)
{
Console.WriteLine(excpt.Message);
}

ShowAllFoldersUnder(folder, +2);
keyCounter++;
}
}
catch (UnauthorizedAccessException) { }
Console.WriteLine("There were " + keyCounter + " files to be searched");
}

public static void UpdateStatus(string fileSearched)
{
string updatedFile = fileSearched;
//MessageBox.Show(updatedFile);
return;

}

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OriginalGriff · Accepted Answer · 2014-07-11T06:07:00

Let me see if I've got what you are trying to do:
You have two classes, one called Class1 and the Class2.
Class1 contains a StatusStripLabel.
Class1 calls a function in Class2:

C#

Class2 c2 = new Class2();
c2.Method(666);

From the instance of Class2, you want to update the the label in Class1.

You can't access anything from Class1 in Class2 unless it is public (assuming Class2 is not derived from Class1), and even if it was, you would need the actual instance of Class1 to be sure of getting the right control within the displayed instance - creating a new one will not work.

If you have to do this, then it's likely that you should read this: Transferring information between two forms, Part 2: Child to Parent[^] - it's based around doing everything in Forms, but the same technique works for all classes.