Ajax Posting Problem

Question

5.00/5 (1 vote)

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Hi,

I'm trying to post data to controller using ajax post it contains a model and string,the string value comes to the controller but the model is always null.Can anyone help.Attaching the code

JavaScript

<script>
    function save() {
        var st = "Test";
        var source = ({
            'Name': $('#Name').val(),
            'Code': $('#Code').val(),
            'Address': $('#Address').val(),
            'City': $('#City').val(),
            'State': $('#State').val(),
            'Country': $('#Country').val(),
            'Phone': $('#Phone').val(),
            'Fax':$('#Fax').val()
        });
        $.ajax({
            type: "POST",
            url:'@Url.Action("Save", "Hospitals")',
            data: { 'st': st, 'hospital': source }
        });
    }
</script>

Controller

C#

public ActionResult Save(string st,Hospital hospital)
       {
           if (ModelState.IsValid)
           {
               db.Hospitals.Add(hospital);
               db.SaveChanges();
               return RedirectToAction("Index");
           }
           else
           {
               var dept = db.Departments.ToList();
               ViewBag.department = dept;
           }

           return View(hospital);
       }

Here always the model will be null but will get he string variable.

Posted 16-Jun-14 20:31pm

Mani89

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2 solutions

Solution 1

Please try as shown below.Use JSON.stringify().

<script>
    function save() {
        var st = "Test";
        var source = ({
            'Name': $('#Name').val(),
            'Code': $('#Code').val(),
            'Address': $('#Address').val(),
            'City': $('#City').val(),
            'State': $('#State').val(),
            'Country': $('#Country').val(),
            'Phone': $('#Phone').val(),
            'Fax':$('#Fax').val()
        });
        $.ajax({
            type: "POST",
            url:'@Url.Action("Save", "Hospitals")',
            contentType: "application/json", 
            data: { 'st': st, 'hospital': JSON.stringify(source) }
        });
    }
</script>

Check for more info: JSON.stringify()

Posted 16-Jun-14 23:34pm

Sampath Lokuge

Comments

Mani89 17-Jun-14 6:04am

Hi sampath,
Thanks for the immediate reply.I have tried the solution you said but now its going to actionresult for the index page,instead of going to the url mentioned.Then I tried removing "contentType: "application/json" for that it wil go to the url but null value for the model.Can you help me??

Sampath Lokuge 17-Jun-14 7:19am

Please check this sample.http://stackoverflow.com/questions/5980389/proper-way-to-use-ajax-post-in-jquery-to-pass-model-from-strongly-typed-mvc3-vie

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Mani89 · Accepted Answer · 2014-06-23T18:52:00

Jquery

JavaScript

<script>
    function save() {
        var cval;
        var str = "";
        $(".chkmaincat:checked").each(function (i) {
            cval = $(this).val();
            str = str + cval + ",";
        });
        alert(str);
        var source =
        {
            'Name': $('#Name').val(),
            'Code': $('#Code').val(),
            'Address': $('#Address').val(),
            'City': +$('#City').val(),
            'State': $('#State').val(),
            'City': $('#City').val(),
            'Country': $('#Country').val(),
            'Phone': $('#Phone').val(),
            'Fax': $('#Fax').val()
        }

        $.ajax({
            type: "POST",
            url: '/Hospitals/Save?st='+str,
            data: source
        });

    }
</script></script>

Controller

JavaScript

public ActionResult Save(string st,Hospital hospital)
       {
           if (ModelState.IsValid)
           {
               db.Hospitals.Add(hospital);
               db.SaveChanges();
               return RedirectToAction("Index");
           }
           else
           {
               var dept = db.Departments.ToList();
               ViewBag.department = dept;
           }

           return View(hospital);
       }

By doing the above i got the string value as well as the modal.Thank you everyone for the help.