How to open my file with my program?

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Hi dears
I programmed a video player in c#.
this program is trying to read "*.KMPC" files.
in my program I should define the file path and the file name. For example @"c:/MyVideoFile.kmpc"
Now I have to rename all my files in copy that file into Drive "C" and after that Run the program.
I want to overcome this issue and modify my program. I want if I double-click in my fine with any name in any Drive My program will enable to recognize the file path and file name.
Please help me

Posted 28-May-14 0:49am

alireza ghasemi

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karthik Udhayakumar 28-May-14 6:51am

What have you tried so far?where is your code and where you are stuck up?

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lukeer · Answer 1 · 2014-05-28T01:20:00

It's a 2-step process to get that done.
1) tell your OS to pass the file to your program
2) make your program capable of handling the OS call

1) Right-click on one of the video files,
choose "Open with >" and
"Choose standard application"
Search the file system for your program

2) OS calls your program with the file as a command-line parameter.
You can access that parameter via the GetCommandLineArgs method.
In your software, check if there is a valid filename in that argument list and if there is, play that file instead of the hard-coded one.

For a more sophisticated command line parser, have a look at C#/.NET Command Line Argument Parser Reloaded

Richard MacCutchan · Answer 2 · 2014-05-28T01:01:00

Solution 1

Use the OpenFileDialog Class[^].

Posted 28-May-14 1:01am

Richard MacCutchan

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alireza ghasemi 28-May-14 7:07am

Hi Dear Richard MacCutchan
I knew that class. But I want some thing more than that. I want when my Program are close after I clikced on my file atumatically the program understands the file path and file name that I clicked on it.
For example when somebody clicked on mp3 Files the MWplayer will open and will play that file.

Vincent Beek 28-May-14 7:41am

You will have to create a mimetype, where you assosiate the .kpmc files with your program.