How to display a value on the table field through javascript?

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Javascript

HTML5

Cordova

Down is my code to list the names of a particular customer from a table selecting the active project from the project table.

function addTable() {

    var myTableDiv = document.getElementById("myDynamicTable");
    var table = document.createElement('TABLE');
    table.border='1';

    var tableBody = document.createElement('TBODY');
    table.appendChild(tableBody);
  db.transaction(function(transaction)
    {
    
     var pro=localStorage.getItem("ActiveProject");
     var activePro='Select Prjdb_id from ProjectTable where Proj_name="'+pro+'" ';
    transaction.executeSql(activePro , [],  function(transaction, result)
    {
             for (var i = 0; i <  result.rows.length; i++)
             {
                var row = result.rows.item(i);
                    id=row.Prjdb_id;
             }
               db=openDatabase(id, version, displayName,maxSize);
      if(id)
         {
          transaction.executeSql('SELECT * FROM customer' , [],  function(transaction, result)
          {
         
            le=result.rows.length;
            if (result.rows.length != 0)
            {
            var row = result.rows.item(i);
            var name= row.Cust_name;
            for(var i=0;i<2;i++)
            {
            var tr = document.createElement('TR');
            tableBody.appendChild(tr);
            for (var j=0; j<le; j++)
            {
            var td = document.createElement('TD');
            td.width='75';
            td.appendChild(document.createTextNode(name));
            tr.appendChild(td);
            }
            }
            myTableDiv.appendChild(table);
            }
          },errorHandler);
         }
    });
 });

function errorHandler(tx, error)
{
  alert("Database Error: " + error);
}

It goes well till the if(id) condition inside the condition it opens the database too.But doesnot enter the next line of executing the sql command.
Can anybody please help me...