managing the location

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suppose i have main from and button in it. and i have another Form form2, when i click in the button of the main form i want Form 2 appear just below the button. No matter where i kept the button and where i kept the main form i.e. drag to any corner..

Posted 8-Apr-14 20:33pm

thedinesh01

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lukeer · Answer 1 · 2014-04-08T21:16:00

Solution 1

Get the button's location in its event handler and pass it to a custom constructor like this: (untested)

C#

private void button1_Click(object sender, EventArgs e)
{
    Button source = sender as Button;
    if (source == null)
    {
        return;
    }

    Point lowerLeft = source.PointToScreen(new Point(0, source.Height));

    Form2 child = new Form2(lowerLeft);
    child.ShowDialog();
}

class Form2 : Form
{
    public Form2()
    {
        InitializeComponent();
    }

    public Form2(Point location) : this()
    {
        this.Location = location;
    }
}

[Edit]
And set From2's StartPosition[^] property to Manual[^].
[/Edit]

Posted 8-Apr-14 21:16pm

lukeer

Updated 9-Apr-14 2:51am

v3

Comments

thedinesh01 9-Apr-14 4:00am

this did not work for me :(..

thedinesh01 9-Apr-14 4:05am

Point lowerleft = this.button1.Location;
Form2 from = new Form(lowerleft);
frm.Show().

i tried this since i got error in here.
Point lowerLeft = source.PointToScreen(source.Location.X, source.Location.Y + source.Height);

how can we fix that.

lukeer 9-Apr-14 5:33am

0) "did not work" and "got error" are too vague.
1) What did you expect?
2) What happened instead (in case of error: post complete error message)?

thedinesh01 9-Apr-14 5:42am

No overload for method 'PointToScreen' takes 2 arguments.
this was the error message i got :(..

lukeer 9-Apr-14 6:22am

PointToScreen[^] needs an argument of type Point[^]. I corrected that in my solution.
BTW: MSDN[^] comes in very handy for every .NET developer. And it has a search function.

thedinesh01 9-Apr-14 6:52am

thanks for you support but its not again working.
i run the project. and the main form appears. i drag the main form to the corner(as it is small in size). then i click, form2 appears to the previous main form location. i don't want this to happen. i am searching but still not found :(.

lukeer 9-Apr-14 7:08am

Improve your question by posting your current code. Wrap it in tags: <pre lang="c#">YourCodeHere();</pre>

thedinesh01 9-Apr-14 7:50am

code is just as yours. i just want that when i location of the form2 changes with respect to the main form.

lukeer 9-Apr-14 8:52am

Ok, I tried it in a test project and updated my solution. Works on my machine.

thedinesh01 10-Apr-14 0:27am

thanks for your support but it is not still working..

lukeer 10-Apr-14 0:59am

Then let's start over:
Show your code (Improve question, remember tags). What do you expect? What happens instead? Any error messages (complete text)? In what code line?

thedinesh01 10-Apr-14 3:51am

code as as same as yours.
let me explain you. i have Form1 with a button in it. In the click event of the form i get form 2. both the form are of small size. i run the project. i got the form1 and click the button, then from 2 appears just below the button as our ideal solution. then i close the form 2 and drag the form one to the opposite side of the screen and click the button at that time the form 2 appears at its previous location. i want form to appear again below the button which is not happening. Lukeer thanks you so much for your concern. :)

lukeer 10-Apr-14 7:25am

Are you sure it's exactly the same, especially the PointToScreen() part?

thedinesh01 10-Apr-14 8:00am

yeah.. the value of the location is changed but still the form 2 is shown at the same place :(

lukeer 10-Apr-14 8:07am

Is it the same exact place or does the form wander down and to the right a little bit with every button hit?

thedinesh01 11-Apr-14 0:41am

the form wander down to the right a little bit :)..

lukeer 11-Apr-14 1:26am

Sounds like you have Form2's StartPosition still at its default. Set it to Manual (like mentioned in the [Edit] part of my solution).

thedinesh01 11-Apr-14 1:06am

thank you lukeer. solution from johannesnestler works for me. thanks for you tired less effort :)..

lukeer 11-Apr-14 1:34am

How do you know I am tired? And since when is that smoke detector equipped with a zoom lens? ;-)

Congratulations on a working solution. Keep on coding.

thedinesh01 11-Apr-14 1:49am

its not tired, u are tired less..:). thanks you so much again... people like you inspire me to code.. :). Nice meeting you :). What are you doing these days :)..

johannesnestler · Answer 2 · 2014-04-10T02:45:00

Hi thedinesh01,

I came up with the same solution as lukeer (but I don't see a need to create a special constructor for Form2). It looks you still have problems. So maybe you give it a try:

C#

using System;
using System.Drawing;
using System.Windows.Forms;

namespace SetFormLocation
{
    class Program
    {
        static void Main(string[] args)
        {
            Form formMain = new Form();
            Button buttonOpenDialog = new Button { Text = "Open", Location = new Point(20, 20), Parent = formMain };
            buttonOpenDialog.Click += (object objSender, EventArgs ea) =>
                {
                    Button buttonSender = objSender as Button;
                    if(buttonSender == null ) return;
                    Point ptLocation = buttonSender.PointToScreen(new Point(0, buttonSender.Height));

                    Form dialog = new Form { StartPosition = FormStartPosition.Manual, DesktopLocation = ptLocation };
                    dialog.ShowDialog(formMain);
                };

            Application.Run(formMain);
        }
    }
}

(Create a new Forms project and replace the generated Program.cs file's content with the above code).

Steps involved are:
Set StartPosition to FormStartPosition.Manual
Get the Screen coordinates for your button (with PointToScreen)
Add the desired offset to the found screen coordinates (in your case the button hight)
Set DesktopLocation (or Location) for your dialog to the desired value in screen-coordinates.

Should be realy simple and works across multiple monitors etc. (I tested the code too)

Kind regards Johannes