snprintf is giving error on Linux build

Question

0.00/5 (No votes)

See more:

Hi All,

when I am using below code on Linux the build is failing with the below error .

Could you please let me know what could be wrong with this usage on LInux.

/usr/include/bits/stdio2.h:66:44: error: call to int __builtin___snprintf_chk(char*, unsigned int, int, unsigned int, const char*, ...) will always overflow destination buffer Linking CXX shared library

C++

snprintf(formatStr,sizeof(result),"%%0%ullX", precision);

Appreciate your help.

Thanks,
Sudhakar

Posted 2-Mar-14 23:02pm

Member 3975629

Add a Solution

Comments

Richard MacCutchan 3-Mar-14 5:10am

What is formatStr, what is result, what is precision?

Member 3975629 3-Mar-14 5:13am

char result[255] = {0};
char formatStr[20] = {0};
unsigned char precision;

precision i am passing as 16

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Vedat Ozan Oner · Accepted Answer · 2014-03-02T23:19:00

I think usage of snprintf is wrong. see here: snprintf[^]
the first parameter is buffer, the second parameter is the size of the first parameter(buffer size).

It should be like

snprintf(result,sizeof(result),"%%0%ullX", precision);

I tried the following example and it is OK.

C#

#include <stdio.h>

int main() {

 int i;
 char buff[100];
 i=snprintf(buff, sizeof(buff), "%d", 10);
 if(i>0)
  buff[i]=0;
 printf("%s %d", buff, i);

 return 0;
}

But I am not sure if your format string is correct ("%%0%ullX")