Phone number format for label

Question

1.00/5 (1 vote)

See more:

Hey guys

I have a label.i am using it like U.S. phone number in {0:(###)-###-####}.

it's working fine but it removes leading zero from number.

for example:
like 0123456789 it returns 123456789
and other cases it working fine.

suppose number is 23456 then it format it right.

so main problem is it is reducing leading zero.

please help me

Posted 30-Jan-14 3:00am

Rahul_Pandit

Updated 30-Jan-14 3:02am

v2

Add a Solution

Comments

dharam1 30-Jan-14 9:32am

Please post some code what you are trying.

Rahul_Pandit 30-Jan-14 9:35am

lblHealthPhone.Text = String.Format("{0:(###)-###-####}", double.Parse(0002345578));

Richard MacCutchan 30-Jan-14 10:13am

That makes no sense, why would you try to parse an integer into a double? Try
String.Format("{0:(000)-###-####}", 2345778);. Also see http://msdn.microsoft.com/en-us/library/0c899ak8(v=vs.110).aspx.

Rahul_Pandit 31-Jan-14 1:15am

YOur code is not working.it is not creating phone number format like (011)-030-3450

Rahul_Pandit 31-Jan-14 1:21am

it's not necessary to put zero at first always.

i want exact value what user have saved for phone number.like 002,0000002223,09876598465,9892384987
exact what user entered.My current format removes all leading zeros.

Richard MacCutchan 31-Jan-14 3:20am

Then you need to save exactly what the user enters, and not convert it to integers.

Richard MacCutchan 31-Jan-14 3:22am

I have just tested with that number and it works perfectly. You must be doing something different.

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Rahul_Pandit · Accepted Answer · 2014-01-30T22:44:00

I have solved it myself by creating this function

C#

public static string FormatPhone(string n)
       {
           string returnNumber = n;
           string areaCode = "";
           string usPrefix = "";
           string usNum = "";

           //Handle US Phones (10 digits) or else don't format
           if (!String.IsNullOrEmpty(n))
           {
               switch (n.Length)
               {
                   case 1:
                       areaCode = n.Substring(0, 1);
                       returnNumber = String.Format("({0})", areaCode);
                       break;
                   case 2:
                       areaCode = n.Substring(0, 2);
                       returnNumber = String.Format("({0})", areaCode);
                       break;
                   case 3:
                       areaCode = n.Substring(0, 3);
                       returnNumber = String.Format("({0})", areaCode);
                       break;
                   case 4:
                       areaCode = n.Substring(0, 3);
                       usPrefix = n.Substring(3, 1);
                       returnNumber = String.Format("({0})-{1}", areaCode, usPrefix);
                       break;
                   case 5:
                       areaCode = n.Substring(0, 3);
                       usPrefix = n.Substring(3, 2);
                       returnNumber = String.Format("({0})-{1}", areaCode, usPrefix);
                       break;
                   case 6:
                       areaCode = n.Substring(0, 3);
                       usPrefix = n.Substring(3, 3);
                       returnNumber = String.Format("({0})-{1}", areaCode, usPrefix);
                       break;
                   case 7:
                       areaCode = n.Substring(0, 3);
                       usPrefix = n.Substring(3, 3);
                       usNum = n.Substring(6, 1);
                       returnNumber = String.Format("({0})-{1}-{2}", areaCode, usPrefix, usNum);
                       break;
                   case 8:
                       areaCode = n.Substring(0, 3);
                       usPrefix = n.Substring(3, 3);
                       usNum = n.Substring(6, 2);
                       returnNumber = String.Format("({0})-{1}-{2}", areaCode, usPrefix, usNum);
                       break;
                   case 9:
                       areaCode = n.Substring(0, 3);
                       usPrefix = n.Substring(3, 3);
                       usNum = n.Substring(6, 3);
                       returnNumber = String.Format("({0})-{1}-{2}", areaCode, usPrefix, usNum);
                       break;
                   case 10:
                       areaCode = n.Substring(0, 3);
                       usPrefix = n.Substring(3, 3);
                       usNum = n.Substring(6, 4);
                       returnNumber = String.Format("({0})-{1}-{2}", areaCode, usPrefix, usNum);
                       break;
                   default:
                       areaCode = n.Substring(0, 3);
                       usPrefix = n.Substring(3, 3);
                       usNum = n.Substring(6, 4);
                       returnNumber = String.Format("({0})-{1}-{2}", areaCode, usPrefix, usNum);
                       break;

               }

           }
           return returnNumber;
       }