How Do I Cut A Part Of String I Dont Need

Question

0.00/5 (No votes)

See more:

Hi guys, i have here a string for example
Dim str as String
string = "CodeProject"

now i want a function that will cut the "Project" from the string leaving the string value "Code"

Any ideas on how to do this? Thanks

I dont have google :)

Posted 23-Jan-14 19:35pm

Goenitz

Updated 23-Jan-14 19:39pm

v2

Add a Solution

2 solutions

Solution 2

You can use Sustring method,

C#

string cs = "CodeProject";

                var res = cs.Substring(4);

                Console.Write(res);

Posted 23-Jan-14 19:46pm

Bojjaiah

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

ArunRajendra · Accepted Answer · 2014-01-23T19:44:00

Solution 1

You can use regular expression replace method. I am giving the sample in c#.

C#

using System.Text.RegularExpressions;


String str = "CodeProject"
Regex rgx = new Regex("Project");
      string result = rgx.Replace(str , " ");

Posted 23-Jan-14 19:44pm

ArunRajendra

Updated 23-Jan-14 19:50pm

v2

Comments

Goenitz 24-Jan-14 1:48am

can you elaborate pattern? :)

ArunRajendra 24-Jan-14 1:49am

Solution updated :)