update data in tables with foreign key

Question

1.80/5 (2 votes)

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SQL-Server-2008

i have a problem while updating data in tables through c# widows form i have 2 tables,linked with foreign key i didn't find any solution for query for 2 tables

i use this code for simple update
but i want to update data in 2 tables with foreign key
so plz send me that code

C#

string myconnection = "datasource=127.0.0.1;port=3306;username=root;password=7621361";
MySqlConnection myconn = new MySqlConnection(myconnection);

MySqlCommand selectcommand = new MySqlCommand("insert into mydb.employee (idemployee,name,type) values ('"+this.textBox3.Text+"','"+this.textBox4.Text+"','"+this.textBox5.Text+"') ; " + "insert into mydb.emp_account(idemp_account,loan,bill,balance,total) values ( '" + this.textBox6.Text + "','" + this.textBox7.Text + "','" + this.textBox8.Text + "','" + this.textBox9.Text + "','" + this.textBox10.Text + "');", myconn);
MySqlDataReader myreaderr;


                try
                {
                    myconn.Open();
                    myreaderr = selectcommand.ExecuteReader();
                    MessageBox.Show("saved");
                    while (myreaderr.Read())
                    {
                    }
                }
                catch (Exception ex)
                {
                    MessageBox.Show(ex.Message);
                }

Posted 19-Dec-13 2:32am

abdulrehman7621

Updated 19-Dec-13 2:45am

Maciej Los

v2

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Comments

Murugan Kolanji 19-Dec-13 14:34pm

What was the error?

creepz03 19-Dec-13 18:58pm

You want a much better approach? ..then create a stored procedure.

[no name] 19-Dec-13 20:03pm

SP do not help if one violates constraints.

3 solutions

Solution 2

i m giving example for this please use transaction always when you are insert,update data in two or more tables....................
Dbconnection _db = new Dbconnection();
_db.Orgconnectionstring = _db.Orgconnectionstrig + ";Data Source= " + dbpath + "\\Database\\BIZSOP_ORG.accdb";
OleDbConnection conn = new OleDbConnection(_db.Orgconnectionstring);
conn.Open();
OleDbTransaction tc = conn.BeginTransaction();
try
{
int retval = 0;
OleDbCommand cmdcommand = new OleDbCommand("Delete From SubDepartment where(DeptID=" + omdept.DeptID + ")", conn);
cmdcommand.Transaction = tc;
cmdcommand.ExecuteNonQuery();
cmdcommand = new OleDbCommand("Delete From Department where(DeptID=" + omdept.DeptID + ")",conn,tc);
cmdcommand.ExecuteNonQuery();

tc.Commit();
return retval;
}
catch (Exception ex)
{
tc.Rollback();
return 0;
}

Posted 19-Dec-13 12:20pm

sp_suresh

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dbrenth · Accepted Answer · 2013-12-19T10:19:00

You may want to split your SQLCommand into two commands and run them in a transaction. (Look at myconn.BeginTransaction(), myconn.Commit(), and myconn.Rollback(). Here if the second query fails you will be left with a half processed record.

Then, because you are doing INSERTS, you want to run selectcommand.RunNonQuery();

Once you get it running, you will want to look into using SQLParameters. They will protect you from someone entering bad data into your textboxes.

Good Luck

idle63 · Accepted Answer · 2013-12-19T13:49:00

Most probably you violate the foreign key constraint.

Your two SQL statements a little bit more clear:

Master:

SQL

insert into mydb.employee (idemployee,name,type) 
values ('"+this.textBox3.Text+"','"+this.textBox4.Text+"','"+this.textBox5.Text+"')

Detail:

SQL

insert into mydb.emp_account(idemp_account,loan,bill,balance,total) 
values ( '" + this.textBox6.Text + "','" + this.textBox7.Text + "','" + this.textBox8.Text + "','" + this.textBox9.Text + "','" + this.textBox10.Text + "')

Where in the detail insert statement (emp_account) you have a foreign key to the master table?
At least this.textBox3.Text (I assume employee.idemployee is primary) should apear in detail insert to fullfill foreignkey constraint (with appropriate field of course).

It would help a lot to answer if you give a short overview about this two tables and there fields.

update data in tables with foreign key

3 solutions

Solution 1

Solution 2

Solution 3

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