xml serialization - dynamically change element name

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I am using xmlserialization, created some classes, but for one node I want xml as

XML

<AliasNames>
<AliasGivenName1>Joe</AliasGivenName1>
<AliasMiddleName1>A</AliasMiddleName1>
<AliasFamilyName1>Doe</AliasFamilyName1>
<AliasGivenName2>Jerry</AliasGivenName2>
<AliasMiddleName2>B</AliasMiddleName2>
<AliasFamilyName2>Doe</AliasFamilyName2>
<AliasGivenName3>Jim</AliasGivenName3>
<AliasMiddleName3>C</AliasMiddleName3>
<AliasFamilyName3>Doe</AliasFamilyName3>


</AliasNames>

This contains index added to xml node.

how can I accomplish this, please help.

Thanks in advance.

Posted 26-Jul-13 2:52am

pritam ajmire

Updated 26-Jul-13 3:23am

Pheonyx

v2

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Pheonyx 26-Jul-13 9:22am

Sorry but your question is unclear, can you explain further.
Please use the Improve Question option to add more information to explain your requirements.

3 solutions

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Pascal-78 · Answer 1 · 2013-07-26T04:32:00

You should reconsider the way you are serialising your data to have something more "xml-like":

XML

<aliasnames>
  <aliasname>
    <given>Joe</given>
    <middle>A</middle>
    <family>Doe</family>
  </aliasname>
  <aliasname>
    <given>Jerry</given>
    <middle>B</middle>
    <family>Doe</family>
  </aliasname>
  <aliasname>
    <given>Jim</given>
    <middle>C</middle>
    <family>Doe</family>
  </aliasname>
</aliasnames>

This can be done using an array of AliasName class with Given, Middle and Family properties.

If you cannot change the xml format, you should use the XmlDocument by yourself:

C#

XmlDocument xml = new XmlDocument();
XmlElement eltRoot = xml.CreateElement("AliasNames");
xml.AppendChild(eltRoot);
for(int i=1; i<=arrayOfNames.Length(); ++i)
{
  XmlElement elt = xml.CreateElement("AliasGivenName"+i);
  elt.InnertText = arrayOfNames[i].GivenName;
  eltRoot.AppendChild(elt);
  elt = xml.CreateElement("AliasMiddleName"+i);
  elt.InnerText = arrayOfNames[i].MiddleName;
  eltRoot.AppendChild(elt);
  elt = xml.CreateElement("AliasFamilyName"+i);
  elt.InnertText = arrayOfNames[i].FamilyName;
  eltRoot.AppendChild(elt);
}
xml.Save(filename);

woopsydoozy · Answer 2 · 2013-07-26T04:28:00

Don't do it that way. Do this instead:

HTML

<aliasnames>
 <aliasname>
   <aliasgivenname>Joe</aliasgivenname>
   <aliasmiddlename>A</aliasmiddlename>
   <aliasfamilyname>Doe</aliasfamilyname>
 </aliasname>
 <aliasname>
   <aliasgivenname>Jerry</aliasgivenname>
   <aliasmiddlename>B</aliasmiddlename>
   <aliasfamilyname>Doe</aliasfamilyname>
 </aliasname>
 <aliasname>
   <aliasgivenname>Jim</aliasgivenname>
   <aliasmiddlename>C</aliasmiddlename>
   <aliasfamilyname>Doe</aliasfamilyname>
 </aliasname>
</aliasnames>

pritam ajmire · Answer 3 · 2013-07-29T00:14:00

Thanks for your response. I have integrated code supplied by you with my code using xml serializer.

C#

// function returns XmlDocument with values
public XmlDocument GetAliasNames()
{
  XmlDocument xml = new XmlDocument();
  XmlElement eltRoot = xml.CreateElement("AliasNames");
  xml.AppendChild(eltRoot);
  for(int i=1; i<=arrayOfNames.Length(); ++i)
  {
    XmlElement elt = xml.CreateElement("AliasGivenName"+i);
    elt.InnertText = arrayOfNames[i].GivenName;
    eltRoot.AppendChild(elt);
    elt = xml.CreateElement("AliasMiddleName"+i);
    elt.InnerText = arrayOfNames[i].MiddleName;
    eltRoot.AppendChild(elt);
    elt = xml.CreateElement("AliasFamilyName"+i);
    elt.InnertText = arrayOfNames[i].FamilyName;
    eltRoot.AppendChild(elt);
  }
  return xml;
}

I had a class as;

C#

public class _PersonalData
{
    public _PersonName PersonName = new _PersonName();
    public _DemographicDetail DemographicDetail = new _DemographicDetail();

    public XmlDocument AliasNames { get; set; }
}

and I set values as;

C#

PersonalData.AliasNames = GetAliasNames();

and my xml is as;

XML

<BackgroundSearchPackage>
<PersonalData>
<PersonName>
<GivenName>pritam</GivenName>
<MiddleName>ravi</MiddleName>
<FamilyName>Ajmire</FamilyName>
</PersonName>
<DemographicDetail>
<Ssn>234523dsf</Ssn>
<DateOfBirth>14/23/1990</DateOfBirth>
<Race>dsf</Race>
<GenderCode>M</GenderCode>
</DemographicDetail>
<AliasNames>
<AliasNames>
<AliasGivenName1>GN1</AliasGivenName1>
<AliasMiddleName1>MN1</AliasMiddleName1>
<AliasFamilyName1>FN1</AliasFamilyName1>
</AliasNames>
</AliasNames>
</PersonalData>
</BackgroundSearchPackage>

xml serialization - dynamically change element name

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