SQL Query with Group By

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SQL-Server-2005

Hi Friends,

I have a doubt in sql server 2005. I have a some records like

No Name
1 aaa
1 bbb
2 ccc
1 ddd
3 eee
2 fff

I want the result like :

No Name
1 aaa,bbb,ddd
2 ccc,fff
3 eee

I tried : select no,name from table1 group by no,name.

It will give result like my above table format... but i want the below format.How can write query?

No Name
1 aaa,bbb,ddd
2 ccc,fff
3 eee

Posted 11-Jul-13 20:44pm

eswaran_guna

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berrymaria 12-Jul-13 3:42am

you accepted my answer.. and then you undo it.. then you accepted it .. then undo.. then accepted.. then undo..

3 solutions

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Priyanka7777 · Answer 1 · 2013-07-11T21:17:00

Solution 2

Try this:

SQL

SELECT No,
       SUBSTRING(
       (Select (',' + Name)
       from Temp_Table t2
       where t1.No=t2.No
       order by
       No,
       Name
       FOR xml path( '' ) ),3,1000)
       FROM Temp_Table t1
       group by No

Posted 11-Jul-13 21:17pm

Priyanka7777

Comments

jaideepsinh 12-Jul-13 3:46am

5+ve.

Priyanka7777 12-Jul-13 3:47am

Thnx.

pjaar89 · Answer 2 · 2013-07-11T21:12:00

Hi, there is no equivalent function such a GROUP_CONCAT in MySQL but I found an interesting trick, please try:

SQL

SELECT
[No],
STUFF((
SELECT ', ' + CAST([Name] AS VARCHAR(MAX)) FROM [table1] WHERE [No] = [table1_copy].[No]
FOR XML PATH ('')),
1,2,'') AS [Name_Values]
FROM [table1] [table1_copy]
GROUP BY [No]

berrymaria · Answer 3 · 2013-07-11T21:19:00

Solution 3

It works for me, try this:

SQL

Select distinct ST2.NO, 
           (Select ST1.NAME + ',' AS [text()]
            From dbo.AA ST1
            Where ST1.NO = ST2.NO
            ORDER BY ST1.NO
            For XML PATH ('')) [Name]
     From dbo.AA ST2

Posted 11-Jul-13 21:19pm

berrymaria