Some of the reference-type instances is null while you assume it is not null. This situation is created not in the code you show. The exception is thrown when you try to dereference such null member/variable.
You did not show where the exception with the message "Object reference not set to an instance of an object" is thrown.
Not to worry. This is one of the very easiest cases to detect and fix. It simply means that some member/variable of some reference type is dereferenced by using and of its instance (non-static) members, which requires this member/variable to be non-null, but in fact it appears to be null. Simply execute it under debugger, it will stop the execution where the exception is thrown. Put a break point on that line, restart the application and come to this point again. Evaluate all references involved in next line and see which one is null while it needs to be not null. After you figure this out, fix the code: wither make sure the member/variable is properly initialized to a non-null reference, or check it for null and, in case of null, do something else.
Please see also:
want to display next record on button click. but got an error in if condition of next record function "object reference not set to an instance of an object"[
^].
Good luck,
—SA