how to show popup and close the popup using jquey .

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Hi,
i want to open a popup for this i have written code as

<div id="divpop"  runat="server"></div>

$("#divpop").load("popup.aspx", function(response, status, xhr) {
  if (status == "error") {
    var msg = "Sorry but there was an error: ";
    $("#error").html(msg + xhr.status + " " + xhr.statusText);
  }
});return false;

the popup page will display image ,the popup page has two button
next ,previous .

But the problem is when i click on button next and previous

protected void imageNextClick(object sender, ImageClickEventArgs e)
   {

   }

the parent page url(http://localhost:51185/Docu.aspx) is replace by popup page url
http://localhost:51185/popup.aspx and I am not able to close the popup and go back to parent page

Posted 9-Jan-13 22:32pm

aassaahh

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*Suvabrata Roy* · Answer 1 · 2013-01-09T22:41:00

Solution 1

Hi,

Add javascript on next button click which will close you pop up and the send the request to server.

JavaScript

onclick = "$("#divpop").unload();"

Posted 9-Jan-13 22:41pm

Suvabrata Roy

Updated 9-Jan-13 22:42pm

v2

Comments

aassaahh 10-Jan-13 12:16pm

but i want to write some server side code in the next button ,which will get data from the database.

aassaahh 10-Jan-13 12:23pm

after getting data from the database user wll click cancel button which will hide the popup.

Suvabrata Roy 10-Jan-13 23:33pm

Your problem is postback,
So you can fetch data asynchronously and display data on the page.

http://jquery-with-asp.net/2011/07/button-click-event-via-ajax-with-jquery/