Click here to Skip to main content
15,891,951 members
Please Sign up or sign in to vote.
0.00/5 (No votes)
See more:
Double fine = Convert.ToDouble(txtfine.Text);
Posted
Comments
[no name] 17-Dec-12 5:01am    
Make sure your textbox value contains only integer or float.
or
try Double fine = Convert.ToDouble(txtfine.Text.Trim());
Tarun Mangukiya 18-Dec-12 2:41am    
This error can be due to empty textbox too...

1 solution

use Double.tryParse instead of Convert. class. it add better safety to the application.
 
Share this answer
 

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)



CodeProject, 20 Bay Street, 11th Floor Toronto, Ontario, Canada M5J 2N8 +1 (416) 849-8900