print the content of files from a particular directory

Question

0.00/5 (No votes)

See more:

Hi,

I displayed all the files from a directory using the cmd,

ls /home/user1/. Now I need to display all content of particular files present in this directory

For ex.

ls /home/user1/tmp/ containt three files
sample1.txt sample2.txt sample3.txt sample5.js sample6.html

How to display only the content of .txt files present in these files

I have tired ls /home/user1/tmp/ | grep '.txt$' | cat /home/user1/tmp

But it is not working as I need.

Please help. Thanks in advancd

Posted 19-Nov-12 23:15pm

srmohanr

Updated 19-Nov-12 23:29pm

v2

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Graham Breach · Accepted Answer · 2012-11-19T23:25:00

Solution 1

Just use a wildcard with cat:

cat /home/user1/tmp/*.txt

Posted 19-Nov-12 23:25pm

Graham Breach

Comments

srmohanr 20-Nov-12 5:35am

Thanks for your great help.

Please tell me how to count the number of blank lines in those contents

I have tried cat /home/user1/tmp/*.txt | grep -n | wc -l

Graham Breach 20-Nov-12 5:42am

This works for me:
cat /home/user1/tmp/*.txt | egrep '^$' | wc -l

srmohanr 20-Nov-12 5:56am

Thanks for your great help

srmohanr 20-Nov-12 6:01am

what should do to execute commands under the presently working directory and without using './'.
For example:

I am under ~/sample, I have a command "mycmd" in this folder. How can I execute the it by using $mycmd

srmohanr 20-Nov-12 6:03am

'mycmd' already has an execute permission.

Graham Breach 20-Nov-12 6:06am

If you really want to do that, you will have to add "./" to your path. Exactly how you do that depends on which shell you are using.

Having to use "./" means that you do not accidentally run files in the current directory, which is a good thing.

srmohanr 20-Nov-12 6:10am

It have tried export PATH=~/sample:$PATH

It's working.

Thanks for your valuable information.

srmohanr 20-Nov-12 6:39am

I have a file contains group of words from a to z. Now I need to get all the words that have a,e,i,o,u in order

For example : abstancious.

I have tried cat /home/user1/tmp/file.txt | grep [aeiou]

But it showing all files that starts with those words.

Please help me